1. A wave is traveling down a 3-m long wire for 0.3 seconds. What is the period of the wave?
Known :
Time interval (t) = 0.3 seconds
Wanted : Period (T)
Solution :
1 wavelength = 1 crests + 1 troughs
Period = 2 x 0.1 second = 0.2 seconds
[irp]
2. The wave speed according to figure below is…
Known :
1 wavelength has 1 crests and 1 troughs. According to figure above, 1 wavelength = 2 meters x 4 = 8 meters.
Periode of wave (T) = 0.5 x 4 = 2 seconds
Wanted : The wave speed (v)
Solution :
The wave speed :
v = s / t = λ / T = 8 meters / 2 seconds = 4 meters/second
[irp]
3. The distance between point A and B is 30 cm. What is the wave speed according to figure below.
Known :
From A to B, there is ¾ wavelength. If the distance between A and B is 30 cm, then the distance of ¼ wavelength is 30 cm / 3 = 10 cm. Thus, 1 wavelength = 4 x 10 cm = 40 cm.
According to the figure above, a period of the wave is 4 seconds.
Wanted : The wave speed (v)
Solution :
v = d / t = λ / t
v = the wave speed, d = distance, λ = wavelength, t = time interval
The wave speed :
v = λ / t = 40 cm / 4 seconds = 10 cm / 1 second = 10 cm/second
[irp]
4. If the distance of A and B = 250 cm, then the wave speed is…
Known :
Distance of A and B = 5/4 wavelength = 250 cm.
1/4 wavelength = 250 cm / 5 = 50 cm
1 wavelength = 4/4 wavelength = 4 x 50 cm = 200 cm
Period (T) = 2 seconds
Wanted : The wave speed
Solution :
Formula of the wave speed :
v = d / t = λ / t
v = the wave speed, d = distance λ = wavelength, t = time interval
The wave speed :
v = 200 cm / 2 seconds = 100 cm/second
5. Amplitude of wave are shown by….
Solution :
The amplitude of the wave is BB’ and DD”.
