Solved problems in projectile motion – determine the time interval
1. A kicked football leaves the ground at an angle θ = 30o to the horizontal with an initial speed of 10 m/s. Calculate the time interval to reach the maximum height! Acceleration of gravity is 10 m/s2.
Known :
Angle (θ) = 30o
Initial velocity (vo) = 10 m/s
Acceleration of gravity (g) = 10 m/s2
Wanted : Time interval to reach the maximum height
Solution :
Vertical component of initial velocity :
voy = vo sin θ = (10 m/s)(sin 30o) = (10 m/s)(0.5) = 5 m/s
Time interval to reach maximum height is determined by the vertical motion equation. Choose upward direction as positive and downward direction as negative.
Known :
Initial velocity (vo) = 5 m/s (positive upward)
Acceleration of gravity (g) = –10 m/s2 (negative downward)
Final velocity at maximum height (vt) = 0
Wanted : time interval (t)
Solution :
vt = vo + g t
0 = 5 + (-10)t
0 = 5 – 10 t
5 = 10 t
t = 5/10 = 0.5 s
2. A body is projected upward at angle of 30o to the horizontal with an initial speed of 30 m/s. Calculate time of flight! Acceleration of gravity is 10 m/s2.
Known :
Angle (θ) = 30o
Initial velocity (vo) = 8 m/s
Acceleration of gravity (g) = 10 m/s2
Wanted : Time interval before body hits the ground
Solution :
Vertical component of initial velocity :
voy = vo sin θ = (8 m/s)(sin 30o) = (8 m/s)(0.5) = 4 m/s
We first calculate time interval to reach the maximum height using equation of vertical motion.
Choose upward direction as positive and downward direction as negative.
Known :
Initial velocity (vo) = 4 m/s (positive upward)
Acceleration of gravity (g) = –10 m/s2 (negative downward)
Final velocity at the maximum height (vt) = 0
Wanted : Time interval (t)
Solution :
vt = vo + g t
0 = 4 + (-10)t
0 = 4 – 10 t
4 = 10 t
t = 4/10 = 0,4 s
Time interval to reach the maximum height is 0.4 s.
Time in air is 2 x 0.4 s = 0.8 s.
3. A body is projected upward at an angle of 30o with the horizontal from a building 10 meters high. Its initial speed is 40 m/s. How long does it take the body to reach the ground? Acceleration of gravity is 10 m/s2.
Known :
Angle (θ) = 30o
Initial height (ho) = 10 meters
Initial velocity (vo) = 40 m/s
Acceleration of gravity (g) = 10 m/s2
Wanted : Time in air (t)
Solution :
Vertical component of initial velocity :
voy = vo sin θ = (40 m/s)(sin 30o) = (40 m/s)(0.5) = 20 m/s
We first calculate time interval to reach the maximum height using equation of vertical motion.
Choose upward direction as positive and downward direction as negative.
Known :
Initial velocity (vo) = 20 m/s (positive upward)
Acceleration of gravity (g) = –10 m/s2 (negative downward)
Final velocity at peak (vt) = 0
Wanted : Time interval (t)
Solution :
vt = vo + g t
0 = 20 + (-10)t
0 = 20 – 10 t
20 = 10 t
t = 20/10 = 2 seconds
Time in air = 2 x 2 seconds = 4 seconds.
The object is 10 meters above the ground. 4 seconds is the time interval to reach a place that parallels to the initial position. The ball is still moving downward.
The time interval to reach the ground is calculated using the equation of free fall motion.
Known :
Acceleration of gravity (g) = 10 m/s2
High (h) = 10 meters
Wanted : Time interval (t)
Solution :
h = 1/2 g t2
10 = 1/2 (10) t2
10 = 5 t2
t2 = 10/5 = 2
t = √2 = 1.4 seconds
Time interval = 1.4 seconds.
Total time interval = 4 seconds + 1.4 seconds = 5.4 seconds.
4. A small ball projected horizontally with initial velocity vo = 15 m/s from a building 5 meters high. Calculate time in the air! Acceleration of gravity is 10 m/s2
Known :
High (h) = 5 meters
Initial velocity (vo) = 15 m/s
Acceleration of gravity (g) = 10 m/s2
Wanted: Time in the air (t)
Solution :
Time in the air is calculated using the equation of freely falling motion.
Known :
High (h) = 5 meters
Acceleration of gravity (g) = 10 m/s2
Wanted : Time interval (t)
Solution :
h = 1/2 g t2
5 = 1/2 (10) t2
5 = 5 t2
t2 = 5/5 = 1
t = √1 = 1 second
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- Resolve initial velocity into horizontal and vertical components
- Determine the horizontal displacement
- Determine the maximum height
- Determine the time interval
- Determine the position of object
- Determine the final velocity