Il-liġi ta' Charles (pressjoni kostanti) – problemi u soluzzjonijiet

1. In a closed container, the gas expands so that the final volume becomes 3 times the initial volume (V = initial volume, T = initial temperatura). What is the final temperature?

Magħruf:

Volum inizjali (V1) = V

Volum finali (V2) = 3V

Temperatura inizjali (T1) = T

Mfittxija: Temperatura finali (T2)

Soluzzjoni:

Il-formula ta ' Il-liġi ta’ Charles :

Charles's law (constant pressure) - problems and solutions 1

The final temperature of gases becomes 3 times the initial temperature.

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2. Jiendeal gases initially have volume V and temperature T. If the gas undergoes the isobaric process so that the temperature becomes 2 times the initial temperature then the final volume of gases is…

Magħruf:

Volum inizjali (V1) = V

Temperatura inizjali (T1) = T

Temperatura finali (T2) = 2T

Mfittxija: final volume (V2)

Soluzzjoni:

Charles's law (constant pressure) - problems and solutions 2

The final volume of gases becomes 2 times the initial volume.

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3. In a closed container, ideal gases initially have a volume of 2 liters and temperature of 27oC. If the final volume of gases becomes 3 liters then the final temperature is…

Magħruf:

Volum inizjali (V1) = 2 litri = 2 dm3 = 2x10-3 m3

Volum finali (V2) = 3 litri = 3 dm3 = 3x10-3 m3

Temperatura inizjali (T1) = 27oĊ + 273 = 300 K

Meħtieġ: Temperatura finali (T2)

Soluzzjoni:

Charles's law (constant pressure) - problems and solutions 3

The final temperature is 177oC or 177 + 273 = 450 Kelvin.

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