1. എസ് അകലം ജലോപരിതലത്തിലെ രണ്ട് തിരമാലകൾക്കിടയിലുള്ള ദൂരം 20 മീ. ഒരു വസ്തു ജലോപരിതലത്തിൽ പൊങ്ങിക്കിടക്കുന്നതിനാൽ കമ്പന ചലനം അനുഭവപ്പെടുന്നു. ഒരു കമ്പനത്തിലൂടെ സഞ്ചരിക്കാനുള്ള സമയം 4 സെക്കൻഡ് ആണെങ്കിൽ, തിരമാലയുടെ വേഗത …. m/s ആണ്.
A. 20
B. 15
C. 10
D. 5
അറിയപ്പെടുന്നത്:
തരംഗദൈർഘ്യം (λ) = 20 meters
Period (T) = 4 seconds
ആവശ്യമുണ്ട്: തരംഗ വേഗത (v)
പരിഹാരം:
തരംഗ വേഗതയുടെ സമവാക്യം:
v = λ / T = 20 meters / 4 seconds = 5 meters / second
ശരിയായ ഉത്തരം D ആണ്.
2. Two points A and B are on the rope and are 90 cm apart from one another. On the rope propagates the transverse waves, so that point A is at the top of the wave, point B at the bottom of the wave, and between them, there are two crests and two troughs. If the wave period is 0.3 seconds, then the wave propagation is…
എ. 10.8 സെ.മീ/സെ.
ബി. 18.0 സെ.മീ/സെ.
സി. 120.0 സെ.മീ/സെ.
ഡി. 200.0 സെ.മീ/സെ.
അറിയപ്പെടുന്നത്:
Distance AB (l) = 90 cm
Period of wave (T) = 0.3 seconds
Frequency of wave (f) = 1/0.3 seconds
Point A is at the crest of the wave and point B is at the trough of the wave.
Between point A and B, there are two crests and two troughs.
ആവശ്യമുണ്ട്: Speed of wave (v = f λ)
പരിഹാരം:
Based on figure, can conclude there are 2.5 wavelengths. Distance of a wavelength (λ) = 90 cm / 2.5 = 36 cm
തരംഗ വേഗത:
v = f λ = (1 / 0.3)(36) = 36 / 0.3 = 120 cm/s.
ശരിയായ ഉത്തരം സി ആണ്.
3. The following graph displays the displacement of a point in one medium as a function of time when a wave passes through the medium.
If the wavelength is 6 meters, then the speed of the wave propagation is…
എ. 3 മീ/സെ
ബി. 6 മീ/സെ
സി. 8 മീ/സെ
ഡി. 12 മീ/സെ
അറിയപ്പെടുന്നത്:
There are two wavelengths based on the graph above.
Distance of 1 wavelength (λ) = 6 meters / 2 = 3 meters
Period (T) = 0.5 seconds
ആവശ്യമുണ്ട്: Speed of waves (v)
പരിഹാരം:
v = f λ = λ / T = 3 meters / 0.5 seconds = 6 meters / second
ശരിയായ ഉത്തരം ബി ആണ്.
4. Based on the figure below, the point that has phase difference ¾ with point A is ….
A. Point B
B. Point C
C. Point D
D. Point E
പരിഹാരം
Point B has a phase difference of ¼ λ with point A
Point C has a phase difference of 2/4 λ or 1/2 λ with point A
Point D has a phase difference of 3/4 λ with point A
Point F has a phase difference of 5/4 λ with point A.
ശരിയായ ഉത്തരം സി ആണ്.
5. On a pond’s surface, there are two dry leaves 60 centimeters away from each other. Both move up and down like the surface of the water with a frequency of 2 Hz. When one leaf is at the crest, the other leaves are at the trough, and between them, there is one crest and one trough. Determine the speed of the wave propagation of the wave.
എ. 20 സെ.മീ/സെ.
ബി. 30 സെ.മീ/സെ.
സി. 80 സെ.മീ/സെ.
ഡി. 120 സെ.മീ/സെ.
അറിയപ്പെടുന്നത്:
Distance between both leaves = 60 cm
Frequency (f) = 2 Hz = 2
ആവശ്യമുണ്ട്: The speed of wave
പരിഹാരം:
Between both leaves, there are 1.5 wavelengths. Distance of 1 wavelength is (λ) = 60 cm / 1.5 = 40 cm
Speed of wave (v) :
v = f λ = (2 Hz)(40 cm) = 80 cm/second
ശരിയായ ഉത്തരം സി ആണ്.
6. Based on the figure below, determine the amplitude, period, frequency, and speed of the wave.
പരിഹാരം:
Amplitude (A) = 4 meters
Period (T) = 6 seconds / 3 = 2 seconds
Frequency (f) = 1 / T = 1 / 2 = 0.5 hertz
Wavelength (λ) = 24 meters / 3 = 8 meters
Speed of wave (v) = f λ = (0.5 hertz)(8 meters) = 4 meters/second or
Speed of wave (v) = λ / T = 8 meters / 2 second = 4 meters/second
ശരിയായ ഉത്തരം D ആണ്.
7. On a string with length of 1.2 m and mass of 200 g formed 1.5 sinusoidal waves with frequency of 50 Hz. Based on these data, determine the wave period and the tension force of the rope.
A. Period = 0.02 seconds and tension force = 6.67 N
B. Period = 0.01 seconds and tension force = 6.67 N
C. Period = 0.02 seconds and tension force = 266.67 N
D. Period = 0.01 seconds and tension force = 266.67 N
അറിയപ്പെടുന്നത്:
Length of rope (l) = 1.2 meters and there are 1.5 sinusoidal waves so that distance of 1 wavelength (λ) = 1.2 meters / 1.5 = 0.8 meters
Mass of rope (m) = 200 gram = 0.2 kg
ആവൃത്തി (f) = 50 Hz
Density of rope (µ) = m/l = 0.2 kg / 1.2 meters = (1/6) kg/meter
ആവശ്യമുണ്ട്: Period of wave (T) and the tension force of rope (T)
പരിഹാരം:
Period of wave :
T = 1 / f = 1 / 50 Hz = 0.02 seconds
The speed of wave on rope :
v = f λ = (50 Hz)(0.8 meters) = 40 meters/second
The tension force (T) :
ശരിയായ ഉത്തരം സി ആണ്.
