Exemplum quaestionis ad vectorem resultantem determinandum utens vectoribus componentibus

Duo exempla quaestionum de determinando vectore resultante utens vectoribus componentibus

1. F₁ = 6 N, F₂ = 10 N. Resultans duorum vectorum vis est…

Disputatio
F_1x F =₁ XXX cos^o = (6)(0,5) = 3 N (positivum quia in directione x positiva est)
F_2x F =₂ XXX cos^o = (10)(0,5√3) = 5√3 = (5)(1,372) = -8,66 N (negativum quia in directione x negativa est)
F_1y F =₁ peccatum 60^o = (6)(0,5√3) = 3√3 = (3)(1,372) = 4,116 N (positivum quia in directione y positiva est)
F_2y F =₂ peccatum 30^o = (10)(0,5) = -5 N (negativum quia in directione y negativa est)

F_x F =_1x - F_2x = 3 – 8,66 = -5,66 N
F_y F =_1y - F_2y  = 4,116 – 5 = -0,884 N

Vector resultans est 5,7 N.

2. F₁ = 4 N, F₂ = 4 N, F₃ = 8 N. Resultans trium vectorum virium est…

Disputatio
F_1x F =₁ XXX cos^o = (4)(0,5) = 2 N (positivum quia in directione x positiva est)
F_2x = -4 N (negativum quia in directione x negativa est)
F_3x F =₃ XXX cos^o = (8)(0,5) = 4 N (positivum quia in directione x positiva est)
F_1y F =₁ peccatum 60^o = (4)(0,5√³) = 2√³ N (positivum quia in directione y positiva est)
F_2y = 0
F_3y F =₃ peccatum 60^o = (8)(0,5√3) = -4√3 N (negativum quia in directione y negativa est)

F_x F =_1x - F_2x F +_3x = 2 – 4 + 4 = 2 N
F_y F =_1y F +_2y  - F_3y = 2√3 + 0 – 4√3 = -2√3 N

Vector resultans est 4 N.

Quaestiones de determinando vectore resultante utens vectoribus componentibus

1. F₁ = 6 N, F₂ = 12 N. Resultans duorum vectorum vis est…
2. F₁ = 10 N, F₂ = 10 N, F₃ = 15 N. Resultans trium vectorum virium est…

[Anglice:] Solvendo problemata vectoria – determinando resultantem duorum vectorum utens componentibus vectoris]