9 Converting temperature scales (Celsius scale Fahrenheit scale Kelvin scale)
1. 50 oC = ….. oF ?
פתרון
At standard atmospheric לחץ, the freezing point of water is 0 oC on the Celsius scale ו 32 oF on the Fahrenheit scale. At standard atmospheric pressure, the boiling point of water is 100 oC on the Celsius scale and 212 oF on the Fahrenheit scale.
0 oC = 32 oפ' ו-100 oC = 212 oF. A change of 5 Co = a change of 9 Fo.
For a Celsius scale, the distance between 0 oC ו- 100 oC divided into 100 equal intervals. For a Fahrenheit scale, the distance between 0 oC ו- 100 oC divided into 180 equal intervals.
ToF = (180/100) Toג + 32
ToF = (9/5) Toג + 32
ToF = (9/5) 50 + 32
ToF = (9) 10 + 32
ToF = 90 + 32
ToF = 122
50 oC = 122 oF
2. 86 oF = ….. oC ?
פתרון
ToC = (100/180)(ToF – 32)
ToC = (5/9)(ToF – 32)
ToC = (5/9)(86 – 32)
ToC = (5/9)(54)
ToC = (5)(6)
ToC = 30
86 oF = 30 oC
3. 50oC = ….. K ?
פתרון
ט = ט oג + 273
T = 50 + 273
T = 323
50 oC= 323 K
4. 212oF = ….. K ?
פתרון
ToC = (100/180)(ToF – 32)
ToC = (5/9)(ToF – 32)
ToC = (5/9)(212 – 32)
ToC = (5/9)(180)
ToC = (5)(20)
ToC = 100
212 oF = 100 oג + 273
212 oF = 373 K
5. אקס oC = x oF
x = ….. ?
פתרון
1 : Converting Celsius scale into Fahrenheit scale

2 : Converting Fahrenheit scale into Celsius scale

6. 122°F = ….. Celsius
פתרון
The conversion between the two temperature scales can be written :
TC = 5/9 (TF - 32)
TC = טֶמפֶּרָטוּרָה in Celsius, TF = temperature in Fahrenheit
The temperature in Celsius :
TC = 5/9 (122 – 32) = TC = 5/9 (90) = 5 (10)
TC = 50 oC
7. The figure below shows the temperature measurement of a liquid with the Fahrenheit scale thermometer! If the temperature of the liquid is measured using a Celsius scale thermometer, then מה הוא the liquid temperature.
ידוע:
פרנהייט סולם (TF) = 95oF
מבוקש: Celsius scale
פתרון:
At a pressure of 1 atm, the freezing point of water is 0 °C while the Fahrenheit scale is 32 oF. Conversely, the boiling point of water for the Celsius scale is 100 oC while the Fahrenheit scale is 212 oF.
On the Celsius scale, between 0 °C and 100 ° C there are 100 ° while on the Fahrenheit scale between 32 °F to 212 °F there is 180°.
TC = 100/180 (TF - 32)
TC = 5/9 (TF - 32)
TC = 5/9 (95 - 32)
TC = 5/9 (63)
TC = 315 / 9
TC = 35oC
8. Based on figure below, determine the temperature P on the Celsius thermometer.
פתרון
TC = 100/180 (TF - 32) 
TC = 5/9 (TF - 32)
TC = 5/9 (104 – 32)
TC = 5/9 (72)
TC = 360 / 9
TC = 40 oC
9. If the temperature of Celsius scale as shown in figure below, determine the temperature of Fahrenheit scale as shown in figure below.
פתרון:
ToF = (180/100) Toג + 32
ToF = (9/5) Toג + 32
ToF = (9/5) 60 + 32
ToF = (9) 12 + 32
ToF = 108 + 32
ToF = 140
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