Ojiji nke nchekwa ike igwe maka mmegharị ihe mberede - nsogbu na ngwọta

1. Bọọlụ a gbara ụkwụ na-apụ n'ala n'akụkụ θ = 30 o na ọsọ mbụ nke 10 m/s. Oke bọọlụ = 0.1 kg. Ọsọ ọsọ nke ike ndọda bụ 1 0 m/s 2. Chọpụta (a) Ike ike ndọda n'ebe kachasị elu (b) Isi kachasị elu ma ọ bụ elu kachasị elu

A maara:

Ibu (m) = 0.1 kg

Ọsọ mbụ (v o ) = 10 m/s

Nkuku = 30 o

Ọsọ ọsọ nke ike ndọda (g) = 10 m/s 2

Ngwọta:

(a) Ike ike ndọda

Ojiji nke nchekwa ike igwe maka mmegharị ihe mberede - nsogbu na ngwọta 1

Gbakọọ ihe mejupụtara kwụ ọtọ (v ox ) na ihe mejupụtara kwụ ọtọ (v oy ) nke ọsọ mbụ.

Ojiji nke nchekwa ike igwe maka mmegharị ihe mberede - nsogbu na ngwọta 2Ojiji nke nchekwa ike igwe maka mmegharị ihe mberede - nsogbu na ngwọta 2vox = vo cos θ = (10)(kọs 30)o) = (10)(0.5√3) = 5√3 m/s

v oy = v o mmehie θ = (10) (mmehie 30 o ) = (10) ( 0.5) = 5 m/s

Ike igwe mbụ

Ike mekanikal mbụ (ME o ) = ike kinetic (KE)

ME o = KE = ½ mv o 2 = ½ (0.1) (10) 2 = ½ (0.1) (100) = ½ (10) = 5 Joules

Ike mekanikal ikpeazụ

Ike kinetic n'ebe kachasị elu:

KE = ½ mv ehi 2 = ½ (0.1) (5√3) 2 = ½ (0.1) ((25) (3)) = ½ (0.1) (75) = 3.75 Joules

Ụkpụrụ nke nchekwa ike igwe

Ike mekanikal mbụ (ME o ) = ike mekanikal ikpeazụ (ME t )

KE = PE + KE

5 = EP + 3.75

PE = 5 – 3.75 = 1.25 Joule

Ike ike ndọda n'ebe kachasị elu bụ 1.25 joules.

(b) Isi kachasị elu ma ọ bụ elu kachasị elu

PE = mgh

1.25 = (0.1)(10) awa

1.25 = awa

Ogologo kachasị elu bụ mita ise.

[irp]

2. A na-atụpụta bọọlụ 0.1-kg n'usoro site na ọsọ mbụ v o = 10 m/s site na ụlọ dị mita 10 n'ịdị elu. Ọsọ ọsọ nke ike ndọda bụ 10 m/s 2. Chọpụta ike kinetic nke bọọlụ ahụ mgbe ọ dara n'ala.

A maara:

Ibu (m) = 0.1 kg

Ọsọ mbụ (v o ) = 10 m/s

Ọsọ ọsọ nke ike ndọda (g) = 10 m/s 2

Mgbanwe n'ịdị elu (h) = 10 – 2 = 8 m

Achọrọ: ike kinetic na mita 2 n'elu ala

Ngwọta:

Ike ike ndọda (PE) = mgh = (0.1)(10)(10) = 10 Joules

Ike kinetic mbụ (KE)= ½ mv o 2 = ½ (0.1)(10) 2 = ½ (0.1)(100) = ½ (10) = 5 Joules

Ike kinetic ikpeazụ = ike ike ndọda mbụ + ike kinetic mbụ = 10 + 5 = 15 Joules

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