Lipotso tsa mohlala oa khoebo

Mehlala e 9 ea Lipotso tsa Khoebo

1. Matla a di-Newton tse 20 a sebediswa bolokong ho fihlela boloko bo tsamaya sebaka sa dimithara tse 2. Mosebetsi o etswang ke matla a F bolokong ke…
Puisano
Hoa tsebahala :
Matla (F) = 20 N
Ho falla (ma) = limithara tse 2
Angle = 0 (lehlakore la matla le tšoana le lehlakore la ho falla kapa lehlakore la matla le tsamaisana le lehlakore la ho falla hoo sekhutlo se entsoeng ke matla le ho falla e leng lefela)
E botsitsoe : Boiteko (W)
Jawab :
Catatan :
Haeba tataiso ea matla e tšoana le tataiso ea ho falla, bala mosebetsi u sebelisa foromo W = F s, ntle le ho hloka ho eketsa cos tit.

2. Ntho e eme e sa sisinyehe holim'a bokaholimo bo boreleli ba fatše. Matla F = 10 N a sebelisoa nthong eo, a etsa sekhutlo sa 30^o kgahlanong le bokaholimo ba mokatong. Haeba ntho e tsamaya mithara e le 1, ke mosebetsi o mokae o etswang ke matla a F hodima ntho eo?
Puisano
Hoa tsebahala :
Matla (F) = 10 Newton
Matla a lebileng ho falla (F_x) = F cos 30^o = (10)(0,5√3) = 5√3 Li-Newton
Ho falla (ma) = limithara tse 1
E botsitsoe : boiteko (W) ?
Jawab :
W = F_x s = (5√3)(1) = 5√3 Joule

3. Ntho e boima ba 1 kg e oela ka bolokolohi ho tloha bophahamong ba limithara tse 2. Haeba lebelo le bakoang ke matla a khoheli e le 10 m/s², fumana mosebetsi o etsoang ke matla a khoheli nthong eo!
Puisano
Hoa tsebahala :
Boima ba ntho (m) = 1 kg
Bophahamo (h) = limithara tse 2
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²
E botsitsoe : Mosebetsi o etsoang ke matla a khoheli nthong (W)
Jawab :
Tsela eo matla a khoheli kapa boima ba 'mele (w) bo shebileng tlase ka ho otloloha, tsela eo ho falla ha ntho (s) ho eona le eona e shebileng tlase ka ho otloloha e le hore matla a khoheli a be ka lehlakoreng le le leng le tsela eo ntho e fallang ka eona.
W = F s = wh = mgh
W = (1)(10)(2) = 20 Joule

4. Seliba se fanyehiloe ka boima ba 1 kg e le hore seliba se be le keketseho ea bolelele ba 2 cm. Haeba lebelo le bakoang ke matla a khoheli e le 10 m/s², fumana (a) sekgahla sa selemo (b) mosebetsi o etswang ke selemo hodima mojaro
Puisano
Hoa tsebahala :
Boima (m) = 1 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²
Keketseho ea bolelele ba selemo (x) = 2 cm = 0,02 metres
E botsitsoe : kamehla ea selemo le mosebetsi o etsoang ke matla a selemo
Jawab :
(a) Sephetho sa selemo
Foromo ea molao oa Hooke :
F = k x.
Fetola foromo ena ho bala botsitso ba selemo:
k = F / x = w / x = mg / x
k = (1)(10) / 0,02 = 10 / 0,02
k = 500 Newton/mithara
(b) Mosebetsi o entsoeng ke lebotho la selemo
W = – ½ kx²
W = – ½ (500)(0,02)²
W = – (250)(0,0004)
W = -0,1 Joule
Mosebetsi o etsoang ke matla a selemo hodima mojaro o mobe hobane tataiso ya matla a selemo e fapane le tataiso ya ho falla ha mojaro.

5. Lebokose le ntseng le le hodima mokatong le potlakiswa ka matla a 10 N hoo lebokose le tsamayang sebaka sa dimithara tse 2. Haeba matla a sutumetsang a le ka lehlakoreng le le leng le ho falla ha lebokose mme lebokose le sebetswa ke matla a kinetic friction a 2 Newtons, jwale mosebetsi o felletseng o entsweng lebokoseng ke...
Puisano
Hoa tsebahala :
Matla (F) = 10 Newton
Matla a khohlano a Kinetic (F)_k) = 2 Newton
Ho falla (ma) = limithara tse 2
E botsitsoe Boiteko bohle (W)_kakaretso)
Jawab :
Mosebetsi o etsoang ka likhoka (F):
W₁ = F s cos 0 = (10)(2)(1) = 20 Joule
Mosebetsi o etsoang ke matla a kinetic friction (F)_k):
W₂ =F_k s = (2)(2)(cos 180) = (2)(2)(-1) = -4 Li-joule
Boiteko bohle ke:
W_kakaretso = W.₁ - W₂
W_kakaretso = 20 - 4
W_kakaretso = 16 Joule

6. Ntho e boima ba 5 kg e hodimo ho lefatshe ka dimithara tse 10. Ho potlaka ka lebaka la matla a khoheli = 10 m/s^-2. Boiteko bo hlokahalang ho tsamaisa ntho ho ea bophahamong ba limithara tse 15 ho tloha holim'a lefatše ke...

A. . 75 Joule

B. . 250 Joule

C. . 500 Joule

D. . 750 Joule

E. 1.250 Joule

Puisano

Hoa tsebahala hore:

Boima ba ntho (m) = 5 kg

Bophahamo (h) = limithara tse 10

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

O botsitse: Leka ho suthisetsa ntho bophahamong ba limithara tse 15

Karabo:

Boiteko ba ho tsamaisa ntho bonyane bo lekana le matla a khoheli a sebetsang nthong eo.

Foromo ea mosebetsi o entsoeng ka matla a khoheli:

W = wh = mgh

Tlhaloso: W = boiteko, w = matla a khoheli, h = bophahamo, m ​​= boima, g = ho potlaka ha matla a khoheli

Foromo ea mosebetsi o entsoeng ke:

W = wh = mgh = (5 kg)(10 m/s²)(10 m) = 500 kg m²/s² = 500 Joule

Karabo e nepahetseng ke C.

7. Ntho e boima ba 2 kg e tsamaya hodima bokahodimo bo boreledi ka lebelo la 2 m/s.^-1 Metsotsoana e seng mekae hamorao ntho eo e ile ea tsamaea ka lebelo la 5 ms^-1 Mosebetsi o entsoeng nthong ena nakong ena ke...

A. 4 Joule

B. 9 Joule

C. 15 Joule

D. 21 Joule

E. 25 Joule

Puisano

Hoa tsebahala hore:

Boima ba ntho (m) = 2 kg

Lebelo la pele (v)_o) = 2 ms^-1

Lebelo la ho qetela (v)_t) = 5 ms^-1

O botsitse: Mosebetsi o etsoang nthong nakong eo ea nako

Karabo:

Theorem ea matla a kinetic ea mosebetsi e bolela hore mosebetsi oohle o entsoeng nthong o lekana le phetoho ea matla a kinetic a ntho.

W = ΔEK = EK₂ – EK₁ = 1/2 mv_t² – 1/2 mv_o² = 1/2 m (v_t² - v_o²) = 1/2 (2)(5²-2²) = (1)(25-4) = 21 Joule

8. Tafole e boima ba 10 kg qalong e phomotse fatshe e boreleli, e sutumelletsoa metsotsoana e 3, e tsamaea ka mola o otlolohileng ka lebelo la 2 m/s.^-2Boholo ba boiteko bo etsahetseng e ne e le…

A. 20 Joule

B. 30 Joule

C. 60 Joule

D. 180 Joule

E. 360 Joule

Puisano

Hoa tsebahala :

Boima (m) = 10 kg

Lebelo la pele (v)_o) = 0 (qalong tafole e eme)

Nako ea ho arohana (t) = metsotsoana e 3

Ho potlaka (a) = 2 m/s²

E botsitsoe : boiteko (W) ?

Jawab :

Taba ea pele, bala sebaka se tsamailoeng u sebelisa foromo ea GLBB:

s = v_o t + ½ ho² = (0)(3) + ½ (2)(3)²

s = 0 + (1)(9) = 9

Mosebetsi o entsoeng tafoleng:

W = F s = (ma)(s) = (10)(2)(9) = 180 Joule

Karabo e nepahetseng ke D.

9 SBoloko bo boima ba 1,5 kg bo sutumelletsoa holimo ke matla a sa fetoheng F = 15 N sebakeng se sekametseng joalo ka ha ho bontšitsoe setšoantšong. Nka hore ho potlaka ka lebaka la matla a khoheli (g) ke 10 m/s.^-2 'me khohlano pakeng tsa boloko le sefofane se sekametseng ke lefela. Mosebetsi oohle o entsoeng bolokong ke…

A. 15 J

B. 30 J

C. 35 J

D. 45 J

E. 50 J

Puisano

Hoa tsebahala :

Boima ba boloko (m) = 1,5 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Boima ba boloko (w) = mg = (1,5)(10) = 15 Newton

Matla a ho sututsa (F) = 15 Newton

E botsitsoe : mosebetsi o felletseng o entsweng bolokong (W) ?

Jawab :

Ho na le matla a mabedi a sebetsang hodima boloko; matla a bapileng le ho falla ha boloko, e leng matla a ho sututsa (F) le boima ba boloko bo bapileng le bokahodimo ba sefofane se sekametseng (w)._x).

Mosebetsi o etsoang ke matla a sututsang ke:

W₁ = F s = (15 N)(2 m) = 30 N m = 30 Joule

Mosebetsi o entsoeng ke matla a khoheli:

W₂ = w_x s = (ha e le hantle 30^o)(2 m) = (15 N)(1/2)(2 m) = 15 N m = 15 Joule

Kakaretso ea mosebetsi o entsoeng bolokong:

W_kakaretso = W.₁ - W₂ = 30 J – 15 J = 15 Joule

Karabo e nepahetseng ke A.