Mehlala e 6 ea lipotso mabapi le ts'ebeliso ea molao oa pele oa thermodynamics lits'ebetsong tsa isobaric (khatello e sa khaotseng)
1. Khatello (P) – kerafo ea bophahamo ba modumo (V) ea khase e fetang ts'ebetsong ea isobaric. Mosebetsi o etsoang ke khase ts'ebetsong ea AB ke…
Puisano
Hoa tsebahala :
Khatello (P) = 5 x 105 N / limithara2
Molumo oa pele (V)1) = 2 m3
Moqolo oa ho qetela (V)2) = 6 m3
E botsitsoe : mosebetsi o entsoeng ts'ebetsong AB
Jawab :
W = P (V)2 - V1)
W = (5 x 105)(6 – 2) = (5 x 105(4)
W = 20 x 105 = 2x106 Joule
2. Phapang mosebetsing o etsoang ke khase lits'ebetsong tsa AB le CD ke…
Puisano
Hoa tsebahala :
Ts'ebetso ea Isobaric AB :
Khatello (P) = 6 atm = 6 x 105 N / limithara2
Molumo oa pele (V)1) = lilithara tse 1 = 1 dm3 = 1x10-3 m3
Moqolo oa ho qetela (V)2) = lilithara tse 3 = 3 dm3 = 3x10-3 m3
Ts'ebetso ea isobaric ea CD :
Khatello (P) = 4 atm = 4 x 105 N / limithara2
Molumo oa pele (V)1) = lilithara tse 2 = 2 dm3 = 2x10-3 m3
Moqolo oa ho qetela (V)2) = lilithara tse 5 = 5 dm3 = 5x10-3 m3
E botsitsoe Phapang mosebetsing o etsoang ke khase lits'ebetsong tsa AB le CD
Jawab :
Mosebetsi o entsoeng ke khase ts'ebetsong AB:
W = P (V)2 - V1)
W = (6 x 105)(3 x 10-3 - 1 x 10-3)
W = (6 x 105)(2 x 10-3)
W = 12 x 102 = 1200 Joule
Mosebetsi o entsoeng ke khase ts'ebetsong ea CD:
W = P (V)2 - V1)
W = (4 x 105)(5 x 10-3 - 2 x 10-3)
W = (4 x 105)(3 x 10-3)
W = 12 x 102 = 1200 Joule
Phapang mosebetsing o etsoang ke khase lits'ebetsong tsa AB le CD ke 1200 - 1200 = 0.
3. Mosebetsi o entsoeng ke khase ts'ebetsong ea ABC ke…
Puisano
Hoa tsebahala :
Khatello ea 1 (P)1) = 6 x 105 Pascal = 6 x 105 N / limithara2
Khatello ea 2 (P)2) = 3 x 105 Pascal = 3 x 105 N / limithara2
Buka ea 1 (V)1) = 2 cm3 = 2x10-6 m3
Buka ea 2 (V)2) = 6 cm3 = 6x10-6 m3
E botsitsoe : Maiteko a entsoeng ts'ebetsong ea ABC.
Jawab :
Mokhoeng oa AB, bophahamo ba modumo ha bo fetohe, kahoo ha ho mosebetsi o etsoang ke khase. Khase e sebetsa feela mokhoeng oa BC. Kahoo mosebetsi o sebetsang mokhoeng oa ABC = mosebetsi o sebetsang mokhoeng oa BC.
W = P2 (V2 - V1)
W = (3 x 105)(6 x 10-6 - 2 x 10-6)
W = (3 x 105)(4 x 10-6)
W = 12 x 10-1
W = 1,2 Joule
Mosebetsi o entsoeng ts'ebetsong ea ABC = 1,2 Joules.
4. Polelo e nepahetseng mabapi le lits'ebetso tsa thermodynamic ke…
A. Isobaric ke mokhoa oa ho fetola khase ka khatello e sa khaotseng.
B. Isobaric ke mokhoa oa ho fetola khase mochesong o sa fetoheng.
C. Isochoric ke mokhoa oa ho fetola khase ka khatello e sa khaotseng.
D. isotherm ke mokhoa oa ho fetola khase ka molumo o sa fetoheng.
E. Isochoric ke mokhoa oa ho fetola khase mochesong o sa fetoheng.
Puisano
Isobaric = khatello e sa khaotseng
Isochoric = molumo o sa fetoheng
Isothermal = mocheso o sa fetoheng
Karabo e nepahetseng ke A.
5. Papiso ea boiteko lits'ebetsong tsa I le II ho latela kerafo e ka tlase ke...
K. 4: 3
B. 3: 4
C. 2: 3
D. 1: 2
E. 1: 3
Puisano:
Hoa tsebahala :
Ts'ebetso ea I: P = 15 N/m2, V1 = 15 limithara3, V2 = 35 limithara3
Ts'ebetso II: P = 10 N/m2, V1 = 5 m3, V2 = 45 limithara3
E botsitsoe :
Papiso ea boiteko (W) ba ts'ebetso ea I le ts'ebetso ea II?
Jawab :
Karabo e nepahetseng ke B.
6. Setšoantšo sa PV sa khase ea helium e fetang ts'ebetsong ea thermodynamic se bontšitsoe setšoantšong se ka tlase! Mosebetsi o entsoeng ke khase ea helium ts'ebetsong ea ABC ke…
A. 400 kJ
B. 500 kJ
C. 600 kJ
D. 800 kJ
E. 1000 kJ
Puisano:
Hoa tsebahala :
P1 = 2x105 N / limithara2
P2 = 1x105 N / limithara2
V1 = 5 m3
V2 = 15 m3
E botsitsoe :
Mosebetsi (W) ts'ebetsong ea ABC?
Jawab :
Mosebetsi o etsoa feela ha bophahamo ba khase bo eketseha. Ts'ebetsong ea AB, bophahamo ba khase bo lula bo tsitsitse, kahoo ha ho mosebetsi o etsoang ke khase ea helium. Ts'ebetsong ea BC, bophahamo ba khase boa eketseha, kahoo mosebetsi o etsoa ke khase ea helium.
