Lipotso tsa mohlala oa khoebo

Mehlala e 9 ea Lipotso tsa Khoebo

1. Matla a di-Newton tse 20 a sebediswa bolokong ho fihlela boloko bo tsamaya sebaka sa dimithara tse 2. Mosebetsi o etswang ke matla a F bolokong ke…
Fisiks-1-khoeboPuisano
Hoa tsebahala :
Matla (F) = 20 N
Ho falla (ma) = limithara tse 2
Angle = 0 (lehlakore la matla le tšoana le lehlakore la ho falla kapa lehlakore la matla le tsamaisana le lehlakore la ho falla hoo sekhutlo se entsoeng ke matla le ho falla e leng lefela)
E botsitsoe : Boiteko (W)
Jawab :
Fisiks-2-khoeboCatatan :
Haeba tataiso ea matla e tšoana le tataiso ea ho falla, bala mosebetsi u sebelisa foromo W = F s, ntle le ho hloka ho eketsa cos tit.

2. Ntho e eme e sa sisinyehe holim'a bokaholimo bo boreleli ba fatše. Matla F = 10 N a sebelisoa nthong eo, a etsa sekhutlo sa 30o kgahlanong le bokaholimo ba mokatong. Haeba ntho e tsamaya mithara e le 1, ke mosebetsi o mokae o etswang ke matla a F hodima ntho eo?
Fisiks-3-khoeboPuisano
Hoa tsebahala :
Matla (F) = 10 Newton
Matla a lebileng ho falla (Fx) = F cos 30o = (10)(0,5√3) = 5√3 Li-Newton
Ho falla (ma) = limithara tse 1
E botsitsoe : boiteko (W) ?
Jawab :
W = Fx s = (5√3)(1) = 5√3 Joule

3. Ntho e boima ba 1 kg e oela ka bolokolohi ho tloha bophahamong ba limithara tse 2. Haeba lebelo le bakoang ke matla a khoheli e le 10 m/s2, fumana mosebetsi o etsoang ke matla a khoheli nthong eo!
Puisano
Hoa tsebahala :
Boima ba ntho (m) = 1 kg
Bophahamo (h) = limithara tse 2
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2
E botsitsoe : Mosebetsi o etsoang ke matla a khoheli nthong (W)
Jawab :
Tsela eo matla a khoheli kapa boima ba 'mele (w) bo shebileng tlase ka ho otloloha, tsela eo ho falla ha ntho (s) ho eona le eona e shebileng tlase ka ho otloloha e le hore matla a khoheli a be ka lehlakoreng le le leng le tsela eo ntho e fallang ka eona.
W = F s = wh = mgh
W = (1)(10)(2) = 20 Joule

4. Seliba se fanyehiloe ka boima ba 1 kg e le hore seliba se be le keketseho ea bolelele ba 2 cm. Haeba lebelo le bakoang ke matla a khoheli e le 10 m/s2, fumana (a) sekgahla sa selemo (b) mosebetsi o etswang ke selemo hodima mojaro
Puisano
Hoa tsebahala :
Boima (m) = 1 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2
Keketseho ea bolelele ba selemo (x) = 2 cm = 0,02 metres
E botsitsoe : kamehla ea selemo le mosebetsi o etsoang ke matla a selemo
Jawab :
(a) Sephetho sa selemo
Foromo ea molao oa Hooke :
F = k x.
Fetola foromo ena ho bala botsitso ba selemo:
k = F / x = w / x = mg / x
k = (1)(10) / 0,02 = 10 / 0,02
k = 500 Newton/mithara
(b) Mosebetsi o entsoeng ke lebotho la selemo
W = – ½ kx2
W = – ½ (500)(0,02)2
W = – (250)(0,0004)
W = -0,1 Joule
Mosebetsi o etsoang ke matla a selemo hodima mojaro o mobe hobane tataiso ya matla a selemo e fapane le tataiso ya ho falla ha mojaro.

5. Lebokose le ntseng le le hodima mokatong le potlakiswa ka matla a 10 N hoo lebokose le tsamayang sebaka sa dimithara tse 2. Haeba matla a sutumetsang a le ka lehlakoreng le le leng le ho falla ha lebokose mme lebokose le sebetswa ke matla a kinetic friction a 2 Newtons, jwale mosebetsi o felletseng o entsweng lebokoseng ke...
Puisano
Fisiks-4-khoeboHoa tsebahala :
Matla (F) = 10 Newton
Matla a khohlano a Kinetic (F)k) = 2 Newton
Ho falla (ma) = limithara tse 2
E botsitsoe Boiteko bohle (W)kakaretso)
Jawab :
Mosebetsi o etsoang ka likhoka (F):
W1 = F s cos 0 = (10)(2)(1) = 20 Joule
Mosebetsi o etsoang ke matla a kinetic friction (F)k):
W2 =Fk s = (2)(2)(cos 180) = (2)(2)(-1) = -4 Li-joule
Boiteko bohle ke:
Wkakaretso = W.1 - W2
Wkakaretso = 20 - 4
Wkakaretso = 16 Joule

6. Ntho e boima ba 5 kg e bophahamo ba limithara tse 10 ka holim'a lefatše. Potlako e bakoang ke matla a khoheli ke 10 m/s -2 . Mosebetsi o hlokahalang ho tsamaisa ntho eo bophahamong ba limithara tse 15 ka holim'a lefatše ke...

A. . 75 Joule

B. . 250 Joule

C. . 500 Joule

D. . 750 Joule

E. 1.250 Joule

Puisano

Hoa tsebahala hore:

Boima ba ntho (m) = 5 kg

Bophahamo (h) = limithara tse 10

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2

Potso: Boiteko ba ho suthisetsa ntho bophahamong ba limithara tse 15

Karabo:

Boiteko ba ho tsamaisa ntho bonyane bo lekana le matla a khoheli a sebetsang nthong eo.

Foromo ea mosebetsi o entsoeng ka matla a khoheli:

W = wh = mgh

Tlhaloso: W = boiteko, w = matla a khoheli, h = bophahamo, m ​​= boima, g = ho potlaka ha matla a khoheli

Foromo ea mosebetsi o entsoeng ke:

W = wh = mgh = (5 kg)(10 m/s 2 )(10 m) = 500 kg m 2 /s 2 = 500 Joule

Karabo e nepahetseng ke C.

7. Ntho e boima ba 2 kg e tsamaya hodima bokahodimo bo boreledi ka lebelo la 2 m/s –1 . Metsotsoana e mmalwa hamorao, ntho e tsamaya ka lebelo la 5 m/s –1 . Mosebetsi o entsweng hodima ntho nakong ena ya nako ke…

A. 4 Joule

B. 9 Joule

C. 15 Joule

D. 21 Joule

E. 25 Joule

Puisano

Hoa tsebahala hore:

Boima ba ntho (m) = 2 kg

Lebelo la pele (v o ) = 2 ms –1

Lebelo la ho qetela (v t ) = 5 ms –1

Potso: Mosebetsi o entsoeng nthong nakong ea khefu ea nako

Karabo:

Theorem ea matla a kinetic ea mosebetsi e bolela hore mosebetsi oohle o entsoeng nthong o lekana le phetoho ea matla a kinetic a ntho.

W = ΔEK = EK 2 – EK 1 = 1/2 mv t 2 – 1/2 mv o 2 = 1/2 m (v t 2 – v o 2 ) = 1/2 (2) (5 2 -2 2 ) = (1) (25-4) = 21 Joules

8. Tafole e boima ba 10 kg qalong e phomola fatshe e boreleli, e sutumelletsoa metsotsoana e 3 mme e tsamaya ka mola o otlolohileng ka lebelo la 2 ms −2 . Bongata ba mosebetsi o entsweng ke…

A. 20 Joule

B. 30 Joule

C. 60 Joule

D. 180 Joule

E. 360 Joule

Puisano

Hoa tsebahala hore :

Boima (m) = 10 kg

Lebelo la pele (vo o ) = 0 (qalong tafole ha e eme)

Nako ea ho arohana (t) = metsotsoana e 3

Ho potlaka (a) = 2 m/s 2

Botsitse : boiteko (W)?

Karabo :

Taba ea pele, bala sebaka se tsamailoeng u sebelisa foromo ea GLBB:

s = vo ot + ½ ho 2 = (0)(3) + ½ (2)(3) 2

s = 0 + (1)(9) = 9

Mosebetsi o entsoeng tafoleng:

W = F s = (ma)(s) = (10)(2)(9) = 180 Joule

Karabo e nepahetseng ke D.

9. Boloko bo boima ba 1,5 kg bo sutumelletsoa holimo ke matla a sa fetoheng F = 15 N sebakeng se sekametseng joalo ka ha ho bontšitsoe setšoantšong. Nka hore ho potlaka ka lebaka la matla a khoheli (g) ke 10 ms -2 'me khohlano pakeng tsa boloko le sefofane se sekametseng ke lefela. Mosebetsi oohle o entsoeng holim'a boloko ke…

A. 15 JPuisano ea khoebo (mosebetsi) 1

B. 30 J

C. 35 J

D. 45 J

E. 50 J

Puisano

Hoa tsebahala hore :

Boima ba boloko (m) = 1,5 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2

Boima ba boloko (w) = mg = (1,5)(10) = 15 Newton

Matla a ho sututsa (F) = 15 Newton

Potso : mosebetsi oohle o entsoeng bolokong (W)?

Karabo :

Ho na le matla a mabedi a sebetsang hodima boloko; matla a bapileng le ho falla ha boloko, e leng matla a ho sututsa (F) le boima ba boloko bo bapileng le bokahodimo ba sefofane se sekametseng (w x ).

Mosebetsi o etsoang ke matla a sututsang ke:

W 1 = F s = (15 N)(2 m) = 30 N m = 30 Joule

Mosebetsi o entsoeng ke matla a khoheli:

W 2 = w x s = (w sin 30 o )(2 m) = (15 N)(1/2)(2 m) = 15 N m = 15 Joule

Kakaretso ea mosebetsi o entsoeng bolokong:

Kakaretso ea W = W 1 – W 2 = 30 J – 15 J = 15 Joule

Karabo e nepahetseng ke A.

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