Physics

Dhibaatooyinka lagu xalliyay Dhaqdhaqaaqa Toosan - walxaha si xor ah u dhacaya

1. Shay ka soo dhacay dusha sare ee buur. Waxaa la arkayaa inuu dhulka ku dhacayo 3 ilbiriqsi ka dib. Go'aami xawaaraha uu ku socdo wax yar ka hor inta uusan dhulka ku dhicin. Dardargelinta cufisjiidadka waa 10 m/s ^2. Iska ilow iska caabbinta biyaha.

La yaqaan:

Xawaaraha bilowga ah (vo _o ) = 0 (shay la tuuray)

Muddada (t) = 3 ilbiriqsi

Dardargelinta cufisjiidadka (g) = 10 m/s ²

La Doonayo: Xawaaraha kama dambaysta ah (v _t )

Xalka:

Dardargelinta cufisjiidadka dhulka dushiisa, baaxaddiisu waa 9.8 m/s ^2. Si aan u fududeyno xisaabinta, waxaan isticmaalnaa 10 m/s ².

10 m/s ² ama 10 m/s / 1 ilbiriqsi, macnaheedu waa in xawaaruhu si toosan u kordho waqtiga 10 m/s ilbiriqsi kasta.

Ka dib 1 ilbiriqsi, xawaaraha shayga = 10 m/s

2 ilbiriqsi ka dib, xawaaraha shayga = 20 m/s

3 ilbiriqsi ka dib, xawaaraha shayga = 30 m/s.

Waxaan sidoo kale u isticmaali karnaa isla'egyada kinematic-ka dhaqdhaqaaqa xawaare joogto ah , sida hoos ku cad.

v _t = v _o + at

s = v _o t + ½ marka la gaaro ²

v _t ² = v _o ² + 2 sida

Hoos u dhaca xorta ah ma laha xawaare bilow ah (v _o = 0), markaa isla'egta kor ku xusan waa la bedeli karaa sida hoos ku cad:

Isle'egta dhaqdhaqaaqa xorta ah ee dhacaya :

v _t = gt ………… 1

h = ½ gt ² ………… 2

v _t ² = 2 gh ………….. 3

v _t = gt

v _t = (10)(3)

v _t = 30 m/s

Xawaaraha kama dambaysta ah waa 30 m/s

2. Jidhku si xor ah ayuu uga dhacaa nasashada, isagoo ka soo dhacaya dherer dhan 25 m. Soo hel (a) Xawaaraha uu dhulka ku dhufto. (b) Waqtiga ay qaadato in dhulka la gaaro.

Xawaaraha ay sabab u tahay cufisjiidadka dhulka dushiisa waa 10 m/s ².

La yaqaan:

Dhererka (h) = 5 mitir

Dardargelinta cufisjiidadka (g) = 10 m/s ²

La doonayo:

(a) Xawaaraha kama dambaysta ah (v _t )

(b) Muddada (t)

Xalka:

Isle'egta dayrta xorta ah:

v _t = gt

h = ½ gt ²

v _t ² = 2 gh

(a) Xawaaraha kama dambaysta ah (v _t )

v _t ² = 2 gh = 2(10)(5) = 100

v _t = 10 m/s

(b) Muddada (t)

h = ½ gt ²

5 = ½ (10) t ²

5 = 5 t ²

t ² = 5/5 = 1

t = 1 ilbiriqsi

3. Kubad ayaa ka soo dhacday meel sare. Soo hel (a) Dardargelin (b) Masaafada ka dib 3 ilbiriqsi (c) Waqtiga hawada ku jira haddii xawaaraha kama dambaysta ahi yahay 20 m/s. Dardargelinta ay sabab u tahay cufisjiidadka = 10 m/s ²

La yaqaan :

Dardargelinta cufisjiidadka (g) = 10 m/s ²

La doonayo:

(a) Dardargelinta (a)

(b) Masaafada ama dhererka (h) haddii waqtigu dhaafay (t) = 3 ilbiriqsi

(c) Muddada waqtiga (t) haddii v _t = 20 m/s

Xalka:

Isle'egta dayrta xorta ah:

v _t = gt

h = ½ gt ²

v _t ² = 2 gh

(a) Dardargelinta (a)

Dardargelinta = dardargelinta cufisjiidadka awgeed = 10 m/s ^2. Waxay la macno tahay kororka xawaaraha 10 m/s ilbiriqsikiiba.

(b) Masaafada ama dhererka (h) ka dib t = 3 ilbiriqsi

h = ½ gt ² = ½ (10)(3) ² = (5)(9) = 45 mitir

(c) Waqtiga dhaafay (t) haddii v _t = 20 m/s

v _t = gt

20 = (10) t

t = 20 / 10 = 2 ilbiriqsi

[wpdm_package id='511′]

[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay Dhaqdhaqaaqa Toosan - Dardargelin joogto ah

1. Gaarigu wuxuu xawaareynayaa nasashada ilaa 20 m/s 10 ilbiriqsi gudahood. Go'aami xawaaraha gaariga!

Solution

La yaqaan:

Xawaaraha bilowga ah (vo _o ) = 0 (nasasho)

Muddada (t) = 10 ilbiriqsi

Xawaaraha kama dambaysta ah (v _t ) = 20 m/s

La Doonayo : Dardargelin (a)

Xalka:

v _t = v _o + at

20 = 0 + (a)(10)

20 = 10 a

a = 20/10

a = 2 m/s ²

2. Gaari ayaa ka gaabinaya 30 m/s si uu u nasto 10 ilbiriqsi gudahood. Go'aami xawaaraha gaariga.

Solution

La yaqaan:

Xawaaraha bilowga ah (vo _o ) = 30 m/s

Xawaaraha kama dambaysta ah (v _t ) = 0

Muddada (t) = 10 ilbiriqsi

La Doonayo: dardargelinta (a)

Xalka:

v _t = v _o + at

0 = 30 + (a)(10)

– 30 = 10 a

a = – 30 / 10

a = -3 m/s ²

Calaamadda taban waxay u muuqataa sababtoo ah xawaaraha ugu dambeeya wuxuu ka yar yahay xawaaraha bilowga ah.

3. Gaarigu wuxuu bilaabmaa oo uu xawaareeyaa 4 m/s ² ilbiriqsi gudahood . Go'aami xawaaraha iyo masaafada 10 ilbiriqsi ka dib.

Solution

(a) Xawaaraha

Dardargelinta 4 m/s ² macnaheedu waa kordhinta xawaaraha 4 m/s 1 ilbiriqsi kasta. 2 ilbiriqsi ka dib, xawaaraha gaarigu waa 8 m/s. 10 ilbiriqsi ka dib, xawaaraha gaarigu waa 40 m/s.

(b) Masaafada

La yaqaan:

Xawaaraha bilowga ah (v _o ) = 0

Xawaaraha kama dambaysta ah (v _t ) = 40 m/s

Dardargelinta (a) = 4 m/s ²

La Raadinayo: Masaafada

Xalka:

s = vo _o t + ½ at ² = 0 + ½ (4)(10 ² ) = (2)(100) = 200 mitir

4. Gaadhigu wuxuu ku socdaa xawaare joogto ah 10 m/s, ka dibna wuxuu hoos u dhacaa xawaare joogto ah 2 m/s ^{2 ilaa nasasho. Go'aami waqtiga dhaafay iyo} masaafada gaariga ka hor nasashada.

La yaqaan:

Xawaaraha bilowga ah (vo _o ) = 10 m/s

Dardargelinta (a) = -2 m/s ² (Calaamadda taban ayaa soo muuqata sababtoo ah xawaaraha kama dambaysta ah wuxuu ka yar yahay xawaaraha bilowga ah)

Xawaaraha kama dambaysta ah (v _t ) = 0 (nasasho)

La Doonayo: Waqtiga iyo masaafada

Xalka:

(a) Muddada (t)

v _t = v _o + at

0 = 10 + (-2)(t)

0 = 10 – 2 t

10 = 2 t

t = 10 / 2 = 5 ilbiriqsi

(b) Masaafada

v _t ² = v _o ² + 2 sida

0 = 10 ² + 2(-2) s

0 = 100 – 4 ilbiriqsi

100 = 4 ilbiriqsi

s = 100 / 4 = 25 mitir

5. Gaadhigu wuxuu ku socdaa 40 m/s, wuxuu ku socdaa xawaare joogto ah 4 m/s ² ilaa uu nasto. Go'aami xawaaraha iyo masaafada ka dib marka uu hoos u dhaco 10 ilbiriqsi gudahood!

Solution

La yaqaan:

Xawaaraha bilowga ah (vo _o ) = 40 m/s

Dardargelinta (a) = -4 m/s ²

Muddada (t) = 10 ilbiriqsi

La doonayo: xawaaraha ugu dambeeya (v _t ) iyo masaafada (s)

Xalka:

(a) Xawaaraha kama dambaysta ah

v _t = v _o + at = 40 + (-4)(10) = 40 – 40 = 0 m/s

0 m/s macnaheedu waa nasashada gaariga.

(b) Masaafada

s = vo _o t + ½ at ² = (40)(10) + ½ (-4)(10 ² ) = 400 + (-2)(100) = 400 – 200 = 200 mitir

6. Go'aami masaafada 10 ilbiriqsi ka dib!

Solution

Masaafada: s = vt = (10-0)(5-0) = (10)(5) = 50 mitir

7. Go'aami masaafada 4 ilbiriqsi ka dib!

Solution

Masaafada = bedka labajibbaaran + bedka saddexagalka ah

Masaafada = (8-0)(8-0) + ½ (16-8)(8-0) = (8)(8) + ½ (8)(8) = 64 + 32 = 96 mitir

8. Go'aami masaafada gaariga 4 ilbiriqsi ka dib!

Solution

Masaafada = bedka saddex-xagalka ah = ½ (4-0)(8-0) = ½ (4)(8) = 16 mitir

9. Gaari ayaa 90 km/saacaddii ka gudbay gaari booliis ah oo istaagaya wadada dhinaceeda. Daqiiqad ka dib, gaariga booliisku wuxuu ku eryaday 0.8 m/s ^2. Intee in le'eg ayuu gaari booliisku gaarigu gaaray?

La yaqaan:

Xawaaraha gaariga (v) = 90 km/saacaddii = 90,000 mitir / 3600 ilbiriqsi = 25 mitir/ilbiriqsi

Muddada (t) = 1 daqiiqo = 60 ilbiriqsi

Dardargelinta gaariga booliiska (a) = 0.8 m/s ²

Xawaaraha bilowga ah ee gaariga booliiska (v _o ) = 0 m/s

La Raadinayo: Masaafada uu baabuur booliisku ku safray

Xalka:

Gaarigu wuxuu ku socdaa xawaare joogto ah. Masaafada uu baabuurku ku socdo:

Masaafada bilowga ah:

s = vt = (25)(60) = 1500 mitir

Masaafada kama dambaysta ah:

s = vt = (25)(t)

Wadarta masaafada = 1500 + 25 t

Gaariga booliiska ayaa si joogto ah u socda. Masaafada uu gaarigu maro:

s = vo _t + ½ at ² = (0)(t) + ½ (0.8)(t ² ) = 0 + 0.4 t ² = 0.4 t ²

Marka gaariga boolisku gaaro gaariga, masaafada uu gaariga boolisku maro waxay la mid tahay masaafada uu gaarigu maro.

Masaafada uu baabuurku maro = masaafada uu baabuurku maro

1500 + 25 t = 0.4 t ²

0.4 t ² – 25 t – 1500 = 0

Isticmaal qaacidada labajibbaaran:

Masaafada uu gaarigu ku safray:

s = 0.4 t ² = (0.4)(100 ² ) = (0.4)(10,000) = 4000 mitir s = 4 km

10. Gaadhigu wuxuu ku socdaa biriigyada 24 m/s oo joogto ah si uu u yeesho hoos u dhac joogto ah oo ah 0.952 m/s ^2. Go'aami xawaaraha gaadhiga ka dib masaafada 250 mitir.

La yaqaan:

Xawaaraha bilowga ah (vo _o ) = 24 m/s

Dardargelinta (a) = – 0.952 m/s ² ( taban ayaa lagu calaamadeeyay hoos u dhac )

Masaafada ( d ) = 250 mitir s

La Raadinayo: Xawaaraha gaariga ka dib 250 mitir ilbiriqsi

Xalka:

La yaqaan: xawaaraha bilowga ah (v_o), dardargelinta (A), masaafada (d), la rabay: xawaaraha ugu dambeeya (v_t) markaa isticmaal isla'egta v_t² =v_o² +2 ah d

v _t = xawaaraha kama dambaysta ah , v _o = xawaaraha bilowga ah , a = dardargelinta , d = masaafada

v _t ² = (24) ² + (2)(-0.952)(250)

v _t ² = 576 – 476

v _t ² = 100

v _t = √100

v _t = 10 m/s

[wpdm_package id='507′]

[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay Dhaqdhaqaaqa Toosan - Xawaaraha joogtada ah

1. Gaarigu wuxuu ku socdaa xawaare joogto ah 10 m/s. Go'aami masaafada ka dib 10 ilbiriqsi iyo 60 ilbiriqsi.

Solution

Xawaaraha joogtada ah ee 10 mitir/ilbiriqsi macnaheedu waa in gaarigu uu socdo 10 mitir 1 ilbiriqsi kasta.

2 ilbiriqsi ka dib, gaarigu wuxuu socdaa 20 mitir,

5 ilbiriqsi ka dib, gaarigu wuxuu socdaa 50 mitir,

10 ilbiriqsi ka dib, gaarigu wuxuu socday 100 mitir ,

60 ilbiriqsi ka dib, gaarigu wuxuu socday 600 mitir.

2. Gaarigu wuxuu ku socdaa waddo toosan xawaare joogto ah oo ah 72 km/saacaddii. Go'aami masaafada gaariga ka dib 2 daqiiqo iyo 5 daqiiqo.

Solution

72 km/saacaddii = (72)(1000 mitir) / 3600 ilbiriqsi = 72,000 / 3600 ilbiriqsi = 20 mitir/ilbiriqsi.

Xawaaraha joogtada ah ee 20 mitir/ilbiriqsi wuxuu la macno yahay in gaarigu uu socdo 20 mitir 1 ilbiriqsi kasta.

120 ilbiriqsi ama 2 daqiiqo ka dib, gaarigu wuxuu socdaa 20 mitir x 120 = 2400 mitir ,

300 ilbiriqsi ama 5 daqiiqo ka dib, gaarigu wuxuu socdaa 20 mitir x 300 = 6000 mitir.

3. Jidhku wuxuu ku socdaa waddo toosan 100 mitir 50 ilbiriqsi gudahood. Go'aami xawaaraha jirka.

Solution

100 mitir / 50 ilbiriqsi = 10 mitir / 5 ilbiriqsi = 2 mitir/ilbiriqsi.

4. Go'aami xawaaraha sida ku cad jaantuska hoose….

Solution

Xawaaraha = Masaafada / waqtiga dhaafay

Xawaaraha = 2 mitir / 1 ilbiriqsi = 4 mitir / 2 ilbiriqsi = 6 mitir / 3 ilbiriqsi = 8 mitir / 4 ilbiriqsi = 2 mitir/ilbiriqsi.

5. Baabuurta A iyo B waxay isku soo dhawaadaan wadooyinka is barbar socda. Marka masaafada u dhaxaysa labada baabuur ay tahay 100 mitir, baabuurka A wuxuu ku socdaa xawaare joogto ah oo ah 10 m/s, baabuurka B wuxuu ku socdaa xawaare joogto ah oo ah 40 m/s. Go'aami (a) masaafada baabuurka A ka hor inta uusan dhaafin baabuurka B (b) muddada u dhaxaysa baabuurka B wuxuu marayaa baabuurka A.

Solution

Gaariga A wuxuu ku socdaa xawaare joogto ah 10 mitir/ilbiriqsi, taasoo la micno ah in gaariga A uu u socdo ilaa 10 mitir 1 ilbiriqsi kasta. 2 ilbiriqsi ka dib, gaarigu wuxuu u socdaa ilaa 20 mitir.

Gaariga B wuxuu ku socdaa xawaare joogto ah 40 mitir/ilbiriqsi, taasoo la micno ah in gaariga B uu u socdo ilaa 40 mitir 1 ilbiriqsi kasta. 2 ilbiriqsi ka dib, gaariga B wuxuu u socdaa ilaa 80 mitir.

20 mitir + 80 mitir = 100 mitir.

(a) Masaafada gaariga A ka hor inta uusan dhaafin gaariga B waa 20 mitir. Masaafada gaariga B ka hor inta uusan dhaafin gaariga A waa 80 mitir.

(b) Muddada u dhaxaysa baabuurka B ka hor inta uusan dhaafin baabuurka A waa 2 ilbiriqsi. Muddada u dhaxaysa baabuurka A ka hor inta uusan dhaafin baabuurka B waa 2 ilbiriqsi

5. Haddii mitirka xawaaraha gaarigu uu muujiyo 108 km/saacaddii, go'aami masaafada uu gaarigu safray hal daqiiqo gudaheed.

Xalka:

Qalabka xawaaraha lagu cabbiro waa qalab lagu cabbiro xawaaraha. Xawaaraha gaarigu waa 108 km/saacaddii.
108 km / saac = (108) (1000 mitir) / 3600 ilbiriqsi = 30 mitir/ilbiriqsi.

1 daqiiqo = 60 ilbiriqsi

Xawaaraha gaariga 30 mitir/ilbiriqsi waxay la macno tahay in gaarigu uu u socdo ilaa 30 mitir hal ilbiriqsi gudaheed.

Ka dib 1 ilbiriqsi, gaarigu wuxuu u socdaa ilaa 1 x 30 mitir = 30 mitir.

Laba ilbiriqsi ka dib, gaarigu wuxuu u socdaa ilaa 2 x 30 mitir = 60 mitir.

Laba ilbiriqsi ka dib, gaarigu wuxuu u socdaa ilaa 60 x 30 mitir = 1800 mitir.

6. Tom ayaa kubbad toos ah u tuuray Andrew . Tom iyo Andrew waxay u kala fogaadeen ilaa 10.08 mitir . Kubadda si toosan ayaa loo tuurayaa waxayna u socotaa 20 m/ s (iska indha tir cufisjiidadka). Andrew wuxuu kubadda ku dhuftay 4.00 x 10 ^-3 ilbiriqsi ka dib markii kubadda la tuuray. Haddii qofka wax ku dhufta uu ku dhaqaaqo xawaare joogto ah oo ah 5.00 m/s, kubadda waxaa ku dhufanaya qofka wax ku dhufta ka dib marka qofka wax ku dhufta uu u dhaqaaqo ilaa…

La yaqaan:

Masaafada u dhaxaysa Tom iyo Andrew = 10.08 mitir

Xawaaraha kubadda (v) = 20 m/s

Muddada u dhaxaysa (t) = 4 x 10 ^-3 ilbiriqsi = 0.004 ilbiriqsi

Xawaaraha garaacaha (v) = 5 m / s

SE buska: Kubbada waxaa ku dhufta qofka wax ku dhufta ka dib markii kubbadu ay u dhaqaaqday ilaa…

Xalka:

Masaafada Kubadda:

s ₁ = vt = (20) (0.004) = 0.08 mitir

Masaafada uu ku socdo weeraryahanka:

s ₂ = vt = 5 t

Masaafada Kubadda + masaafada qofka wax ku dhuftay = masaafada u dhaxaysa Tom iyo Andrew.

0.08 + 5 t = 10.08

5 t = 10.08 – 0.08

5 t = 10

t = 10 / 5

t = 2 ilbiriqsi

Masaafada uu ku socdo weeraryahanka:

s ₂ = vt = 5 t = (5) (2) = 10 mitir

7. Ugaarsade gaarigiisa wata ayaa eryanaya deero. Gaarigu wuxuu ku socdaa 72 km/saacaddii deeradana waxay ku socotaa xawaare dhan 64.8 km/saacaddii. Marka masaafada u dhaxaysa gaariga iyo deerada ay tahay 2012 mitir, ugaadhsade wuxuu rasaas ku riday qorigiisa. Rasaasta qoriga waxay ka soo baxaysaa 200 m/s. Go'aami muddada deerada la tooganayo.

A. 0.5 ilbiriqsi

B. 1 ilbiriqsi

C. 1.25 ilbiriqsi

D. 1.5 ilbiriqsi

La yaqaan:

Xawaaraha gaariga (v _b ) = 72 km/saacaddii = (72)(1000 m) / 3600 s = 20 m/s

Xawaaraha deerada (v _r ) = 64.8 km/saacaddii = (64.8)(1000 m) / 3600 s = 64800 m / 3600 s = 18 m/s

Marka rasaasta la rido, masaafada u dhaxaysa gaariga iyo deerada (deerada) = 202 mitir

Xawaaraha dabka (v _p ) = 20 m/s + 200 m/s = 220 m/s

Hubka ay haystaan ​​ugaarsatada ku jira gaari ku socda xawaare dhan 20 m/s si xawaaraha gaariga loogu daro xawaaraha rasaasta.

La Raadinayo: Go'aami muddada deerada la tooganayo

Xalka:

Ka fikir baabuurta iyo deerada oo si joogto ah u socda.

Isle'egta: v = s / t ama s = vt

v = xawaare, s = masaafada, t = kala-goynta waqtiga

Masaafada = 202 + X _r = 202 + v _r t = 202 + 18 t

Masaafada = Y _p = v _p t = 220 t

Masaafada uu maro deerada = masaafada uu maro xabadu

202 + 18 t = 220 t

202 = 220 t – 18 t

202 = 202 t

t = 202 / 202

t = 1 ilbiriqsi

Jawaabta saxda ah waa B.

[wpdm_package id='507′]

[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka la xaliyay ee Dhaqdhaqaaqa Toosan - Xawaaraha celceliska iyo xawaaraha celceliska

1. Gaari ayaa ku socda waddo toosan oo dhanka bari ah 100 mitir 4 ilbiriqsi gudahood, ka dibna wuxuu aadayaa galbeedka 50 mitir 1 ilbiriqsi gudahood. Go'aami xawaaraha celceliska iyo xawaaraha celceliska.

Solution

Masaafada = 100 mitir + 50 mitir = 150 mitir

Barakac = 100 mitir – 50 mitir = 50 mitir, dhanka bari.

Waqtigii dhammaaday = 4 ilbiriqsi + 1 ilbiriqsi = 5 ilbiriqsi.

Xawaaraha celceliska = Masaafada / waqtiga dhaafay = 150 mitir / 5 ilbiriqsi = 30 mitir/ilbiriqsi.

Xawaaraha celceliska = Barakaca / waqtiga dhaafay = 50 mitir / 5 ilbiriqsi = 10 mitir/ilbiriqsi.

2. Qofku wuxuu ku socdaa 4 mitir bari 1 ilbiriqsi gudaheed, ka dibna wuxuu ku socdaa 3 mitir waqooyi 1 ilbiriqsi gudaheed. Go'aami celceliska xawaaraha iyo celceliska xawaaraha.

Solution

Masaafada = 4 mitir + 3 mitir = 7 mitir

Barakac = = mitir, dhanka waqooyi-bari.

Waqtigii dhammaaday = 1 ilbiriqsi + 1 ilbiriqsi = 2 ilbiriqsi.

Xawaaraha celceliska = masaafada / waqtiga dhaafay = 7 mitir / 2 ilbiriqsi = 3.5 mitir/ilbiriqsi

Xawaaraha celceliska = barokaca / waqtiga dhaafay = 5 mitir / 2 ilbiriqsi = 2.5 mitir/ilbiriqsi

3. Orodyahanku wuxuu ku wareegayaa waddo leydi ah oo dhererkeedu yahay = 50 mitir iyo ballackeeduna yahay 20 mitir. Ka dib markuu laba jeer ku wareego waddo leydi ah, orodyahanku wuxuu ku soo laabanayaa meeshii uu ka bilaabay. Haddii waqtigu dhaafay = 100 ilbiriqsi, go'aami xawaaraha celceliska iyo xawaaraha celceliska.

Solution

Wareegga leydi = 2(50 mitir) + 2(20 mitir) = 100 mitir + 40 mitir = 140 mitir.

Ku safrida leydi 2 jeer = 2 (140 mitir) = 280 mitir.

Masaafada = 280 mitir.

Barakac = 0 mitir . ( orodyahan dib ugu noqda barta bilowga)

Celceliska xawaaraha = masaafada / waqtiga dhaafay = 280 mitir / 100 ilbiriqsi = 2.8 mitir/ilbiriqsi.

Xawaaraha celceliska = barokaca / waqtiga soo dhaafay = 0 / 100 ilbiriqsi = 0.

[wpdm_package id='505′]

[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vectors - go'aami natiijada laba vectors iyadoo la adeegsanayo qaybaha vector-ka

1. F ₁ = 6 N, F ₂ = 10 N. Go'aami vector-ka natiijada.

Solution

F _1x = F ₁ cos 60 ^o = (6)(0.5) = 3 N ( togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x )

F _2x = F ₂ cos 30 ^o = (10)(0.5 √ 3) = 5 √ 3 = (5)(1.372) = -8.66 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F _1y = F ₁ sin 60 ^o = (6)(0.5 √ 3) = 3 √ 3 ​​= (3)(1.372) = 4.116 N ( togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y )

F _2y = F ₂ sin 30 ^o = (10)(0.5 ) = -5 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F _x = F _1x – F _2x = 3 – 8.66 = -5.66 N

F _y = F _1y - F _2y = 4.116 - 5 = -0.884 N

 

Natiijada labadan ciidan waa 5.7 N.

2. F ₁ = 4 N, F ₂ = 4 N, F ₃ = 8 N. Go'aami vector-ka natiijada.

Solution

F_1x =F₁ cs 60^o = (4)(0.5) = 2 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F _2x = -4 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F _3x = F ₃ cos 60 ^o = (8)(0.5) = 4 N ( togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x )

F_1y =F₁ aan lahayn 60^o = (4)(0.5)√3) = 2√3 N (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F _2y = 0

F_3y =F₃ aan lahayn 60^o = (8)(0.5)√3) = -4√3 N (taban) sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F _x = F _1x – F _2x + F _3x = 2 – 4 + 4 = 2 N

F_y =F_1y +F_2y - F_3y = 2√3 + 0 - 4√3 = -2√3 N

Natiijadu waa 5.7 N.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vectors - go'aami natiijada laba vectors iyadoo la adeegsanayo isleegyada cosines

1. F ₁ = 10 N iyo F ₂ = 20 N. Go'aami vector-ka natiijada.

2. A ₁ = 15 iyo A ₂ = 9. Xaglaha u dhexeeya labada vector waa 60 ^o . Go'aami vector-ka natiijada ka soo baxda.

Solution

3. v ₁ = 5 iyo v ₂ = 12. Xagalka u dhexeeya labada vector waa 90 ^o . Go'aami vector-ka natiijada ka soo baxda.

Solution

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vectors - go'aami natiijada laba vectors iyadoo la adeegsanayo aragtida Pythagorean

1. Go'aami natiijada labada fallaadhaha barokaca sida ku cad sawirka hoose.

2. Soo hel natiijada laba xoog , 12 N iyo 5 N.

3. Ardaygu wuxuu u lugeeyaa 4 mitir dhanka galbeed, ka dibna 6 mitir dhanka waqooyi iyo 4 mitir dhanka galbeed. Soo hel barokaca ardayga.

Solution

Barakaca waa 10 mitir , dhanka waqooyi-galbeed.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka la xalliyay ee ku jira vectors - go'aami qaybaha vector-ka

1. Xoogga 20 Newton wuxuu sameeyaa xagal 30 ^o ah oo leh dhidibka x. Soo hel labada qaybood ee x iyo y ee xoogga.

Solution

F _x = F cos 30 ^o = (20)(cos 30 ^o ) = (20)(0.5 √ 3 ) = 10 √ 3 Newtons

F _y = F dembi 30 ^o = (20) ( dembi 30 ^o ) = (20) (0.5) = 10 Newtons

2. F ₁ = 20 Newton wuxuu sameeyaa xagal 30 ^o ah oo leh dhidibka y iyo F ₂ = 30 Newton wuxuu sameeyaa xagal 60 ^o ah oo leh dhidibka -x. Soo hel labada qaybood ee x iyo y ee F ₁ iyo F ₂.

Solution

F _1x = F ₁ cos 60 ^o = (20)(cos 60 ^o ) = (20)(0.5) = -10 Newtons (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F _2x = F ₂ cos 60 ^o = (30)(cos 60 ^o ) = (30)(0.5) = -15 Newtons (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F_1y =F₁ dembi 60^o = (20)(dembi 60^o) = (20)(0.5)√3= 10√3 Newton (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F_2y =F₂ dembi 60^o = (30)(dembi 60^o) = (30)(0.5)√3) = -15√3 Newton (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

3. F ₁ = 2 N, F ₂ = 4 N, F ₃ = 6 N. Soo hel labada qaybood ee x iyo y ee F ₁ , F ₂ iyo F ₃!

Solution

F _1x = F ₁ cos 60 ^o = (2)(cos 60 ^o ) = (2)(0.5) = 1 Newtons (togan sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka x)

F_2x =F₂ cos 30^o = (4)(koos 30)^o) = (4)(0.5)√3) = -2√3 Newton (taban sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka -x)

F _3x = F ₃ cos 60 ^o = (6)(cos 60 ^o ) = (6)(0.5) = 3 Newtons (togan sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka x)

F_1y =F₁ dembi 60^o = (2)(dembi 60^o) = (2)(0.5)√3) = √3 Newton (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F _{2 y} = F ₂ sin 3 0 ^o = (4)(sin 30 ^o ) = (4)(0.5) = 2 Newtons (togan sababtoo ah waxay leedahay jiha isku mid ah oo leh dhidibka y)

F_3y =F₃ dembi 60^o = (6)(dembi 60^o) = (6)(0.5)√3) = -3√3 Newton (taban sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka -y)

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka la xalliyay ee ku jira vectors - go'aami natiijada ku jirta vector-ka xariiqda

1. Ardaygu wuxuu u socdaa waqooyi ilaa 10 mitir ka dibna koonfur ilaa 4 mitir. Barakaca ardayga waa…

Solution

R = 10 m – 4 m = 6 mitir

Baaxadda barokaca waa 6 mitir, jihada barokacana waa waqooyi.

2. F ₁ = 10 N, F ₂ = 15 N. Go'aami vector-ka natiijada…

Solution

R = 10 N + 15 N = 25 Newton

Cabbirka vektor-ka natiijada keenay waa 25 Newtons, jihada vektor-ka natiijada keenay waa bari ama midig.

3. F ₁ = 4 N, F ₂ = 8 N. Go'aami vector-ka natiijada…

Solution

R = 8 N – 4 N = 4 Newton

Cabbirka vektor-ka natiijada keenay waa 4 Newtons, jihada vektor-ka natiijada keenay waa bari ama midig.

4. F ₁ = 10, F ₂ = 15 N, F ₃ = 5 N. Go'aami vector-ka natiijada…

Solution

R = 10 N + 5 N – 15 N = 0

Cabbirka vektor-ka natiijada ka soo baxday waa 0.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah