Physics

Dhibaatooyinka lagu xalliyay Dhaqdhaqaaqa Toosan - walxaha si xor ah u dhacaya

1. Shay ka soo dhacay dusha sare ee buur. Waxaa la arkayaa inuu dhulka ku dhacayo 3 ilbiriqsi ka dib. Go'aami xawaaraha uu ku socdo kahor inta uusan dhulka ku dhicin. Dardargelinta cufisjiidadka waa 10 m/s²Iska ilow iska caabbinta hawada.

La yaqaan:

Xawaaraha bilowga ah (v)_o) = 0 (shay la tuuray)

Muddada waqtiga (t) = 3 ilbiriqsi

Dardargelinta cufisjiidadka (g) = 10 m/s²

La doonayo: Xawaaraha kama dambaysta ah (v)_t)

Xalka:

Xawaaraha uu ku socdo dhulka oo dhan, cufiskiisu waa 9.8 m/s²Si aan u fududeyno xisaabinta, waxaan isticmaalnaa 10 m/s².

10 m / s² ama 10 m/s / 1 ilbiriqsi, taasoo la micno ah in xawaaruhu si toosan u kordho waqtiga 10 m/s ilbiriqsi kasta.

Ka dib 1 ilbiriqsi, xawaaraha shayga = 10 m/s

2 ilbiriqsi ka dib, xawaaraha shayga = 20 m/s

3 ilbiriqsi ka dib, xawaaraha shayga = 30 m/s.

Waxaan sidoo kale u isticmaali karnaa isla'egyada kinematic-ka si aan u dhaqdhaqaaq xawaare joogto ah, sida ka muuqata hoosta.

v_t =v_o + at

s = v_o t + ½ at²

v_t² =v_o² + 2 dhidib

Hoos u dhaca xorta ah ma laha xawaare bilow ah (v)_o = 0), markaa isla'egta kor ku xusan waa la bedeli karaa sida hoos ku cad:

Isle'egta Dhaqdhaqaaq xor ah oo dhaca :

v_t = gt ………… 1

h = ½ gt² ………… 2

v_t² = 2 gh ………….. 3

v_t = gt

v_t = (10)(3)

v_t = 30m/s

Xawaaraha kama dambaysta ah waa 30 m/s

2. Jidhku si xor ah ayuu uga dhacaa nasashada, isagoo ka soo dhacaya dherer dhan 25 m. Soo hel (a) Xawaaraha uu dhulka ku dhufto. (b) Waqtiga ay qaadato in dhulka la gaaro.

Xawaaraha ay sabab u tahay cufisjiidadka dhulka waa 10 m/s².

La yaqaan:

Dhererka (h) = 5 mitir

Dardargelinta cufisjiidadka (g) = 10 m/s²

La doonayo:

(a) Xawaaraha kama dambaysta ah (v)_t)

(b) Muddada (t)

Xalka:

Isle'egta dayrta xorta ah:

v_t = gt

h = ½ gt²

v_t² = 2 gh

(a) Xawaaraha kama dambaysta ah (v)_t)

v_t² = 2 gh = 2(10)(5) = 100

v_t = 10m/s

(b) Muddada (t)

h = ½ gt²

5 = ½ (10) t²

5 = 5 t²

t² = 5/5 = 1

t = 1 ilbiriqsi

3. Kubad ayaa ka soo dhacday meel sare. Soo hel (a) Dardargelin (b) Masaafada ka dib 3 ilbiriqsi (c) Waqtiga hawada ku jira haddii xawaaraha kama dambaysta ahi yahay 20 m/s. Dardargelinta cufisjiidadka = 10 m/s²

Known :

Dardargelinta cufisjiidadka (g) = 10 m/s²

La doonayo:

(a) Dardargelinta (a)

(B) masaafada ama dherer (h) haddii waqtigu dhaafay (t) = 3 ilbiriqsi

(c) Muddada waqtiga (t) haddii v_t = 20m/s

Xalka:

Isle'egta dayrta xorta ah:

v_t = gt

h = ½ gt²

v_t² = 2 gh

(a) Dardargelinta (a)

Dardargelinta = dardargelinta cufisjiidadka awgeed = 10 m/s²Waxay la macno tahay kororka xawaaraha 10 m/s ilbiriqsikiiba.

(b) Masaafada ama dhererka (h) ka dib t = 3 ilbiriqsi

h = ½ gt² = ½ (10)(3)² = (5)(9) = 45 mitir

(c) Waqtiga dhacay (t) haddii v_t = 20m/s

v_t = gt

20 = (10) t

t = 20 / 10 = 2 ilbiriqsi

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[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay Dhaqdhaqaaqa Toosan - Dardargelin joogto ah

1. Gaarigu wuxuu xawaareynayaa nasashada ilaa 20 m/s 10 ilbiriqsi gudahood. Go'aami xawaaraha gaariga!

Solution

La yaqaan:

Xawaaraha bilowga ah (v)_o) = 0 (nasasho)

Muddada (t) = 10 ilbiriqsi

Xawaaraha kama dambaysta ah (v)_t) = 20 m/s

rabay : Dardargelinta (a)

Xalka:

v_t =v_o + at

20 = 0 + (a)(10)

20 = 10 a

a = 20/10

a = 2 m/s²

2. Gaari ayaa ka gaabinaya 30 m/s si uu u nasto 10 ilbiriqsi gudahood. Go'aami xawaaraha gaariga.

Solution

La yaqaan:

Xawaaraha bilowga ah (v)_o) = 30 m/s

Xawaaraha kama dambaysta ah (v)_t= 0

Muddada (t) = 10 ilbiriqsi

La doonayo: dardargelinta (a)

Xalka:

v_t =v_o + at

0 = 30 + (a)(10)

– 30 = 10 a

a = – 30 / 10

a = -3 m/s²

Calaamadda taban ayaa soo muuqata sababtoo ah kama dambaysta xawaare waa ka yar xawaaraha bilowga ah.

3. Gaarigu wuu bilaabmaa oo wuu xawaareeyaa xawaare joogto ah 4 m/s² in 1 ilbiriqsi. Go'aami xawaaraha iyo masaafada 10 ilbiriqsi kadib.

Solution

(a) Xawaaraha

Dardargelinta 4 m/s² macnaheedu waa kordhinta xawaaraha 4 m/s 1 ilbiriqsi kasta. 2 ilbiriqsi ka dib, xawaaraha gaarigu waa 8 m/s. 10 ilbiriqsi ka dib, xawaaraha gaarigu waa 40 m/s.

(b) Masaafada

La yaqaan:

Xawaaraha bilowga ah (v)_o= 0

Xawaaraha kama dambaysta ah (v)_t) = 40 m/s

Dardargelinta (a) = 4 m/s²

La doonayo: masaafada

Xalka:

s = v_o t + ½ at² = 0 + ½ (4)(10)²) = (2)(100) = 200 mitir

4. Gaadhigu wuxuu ku socdaa xawaare joogto ah 10 m/s, ka dibna wuu yareeyaa xawaare joogto ah 2 m/s² ilaa nasasho. Go'aami waqtiga dhaafay iyo gaariga masaafada ka hor nasashada.

La yaqaan:

Xawaaraha bilowga ah (v)_o) = 10 m/s

Dardargelinta (a) = -2 m/s² (Calaamadda taban waxay u muuqataa sababtoo ah xawaaraha kama dambaysta ah wuxuu ka yar yahay xawaaraha bilowga ah)

Xawaaraha kama dambaysta ah (v)_t) = 0 (nasasho)

La doonayo: Muddada iyo masaafada waqtiga

Xalka:

(a) Muddada (t)

v_t =v_o + at

0 = 10 + (-2)(t)

0 = 10 – 2 t

10 = 2 t

t = 10 / 2 = 5 ilbiriqsi

(b) Masaafada

v_t² =v_o² + 2 dhidib

= 0 10² + 2(-2) s

0 = 100 – 4 ilbiriqsi

100 = 4 ilbiriqsi

s = 100 / 4 = 25 mitir

5. Gaadhigu wuxuu ku socdaa 40 m/s, wuxuuna hoos u dhacaa xawaare joogto ah 4 m/s² ilaa inta nasashada. Go'aami xawaaraha iyo masaafada ka dib markaad yareyso 10 ilbiriqsi gudahood!

Solution

La yaqaan:

Xawaaraha bilowga ah (v)_o) = 40 m/s

Dardargelinta (a) = -4 m/s²

Muddada (t) = 10 ilbiriqsi

La doonayo: xawaaraha kama dambaysta ah (v)_t) iyo masaafada (yada)

Xalka:

(a) Xawaaraha kama dambaysta ah

v_t =v_o + at = 40 + (-4)(10) = 40 – 40 = 0 m/s

0 m/s macnaheedu waa nasashada gaariga.

(b) Masaafada

s = v_o t + ½ at² = (40)(10) + ½ (-4)(10)²) = 400 + (-2)(100) = 400 – 200 = 200 mitir

6. Go'aami masaafada 10 ilbiriqsi ka dib!

Solution

Masaafada: s = vt = (10-0)(5-0) = (10)(5) = 50 mitir

7. Go'aami masaafada 4 ilbiriqsi ka dib!

Solution

Masaafada = bedka labajibbaaran + bedka saddexagalka ah

Masaafada = (8-0)(8-0) + ½ (16-8)(8-0) = (8)(8) + ½ (8)(8) = 64 + 32 = 96 mitir

8. Go'aami masaafada gaariga 4 ilbiriqsi ka dib!

Solution

Masaafada = bedka saddex-xagalka ah = ½ (4-0)(8-0) = ½ (4)(8) = 16 mitir

9. Gaari ayaa 90 km/saacaddii ku socda gaari booliis ah oo istaagaya wadada dhinaceeda. Daqiiqad ka dib, gaariga booliisku wuu eryanayaa at 0.8 m / s²Inta uu gaadhiga booliisku gaadhiga gaadhoes gaariga?

La yaqaan:

Xawaaraha gaariga (v) = 90 km/saacaddii = 90,000 mitir / 3600 ilbiriqsi = 25 mitir/ilbiriqsi

Muddada (t) = 1 daqiiqo = 60 ilbiriqsi

Dardargelinta gaariga booliiska (a) = 0.8 m/s²

Xawaaraha bilowga ah ee gaariga booliiska (v_o) = 0 m/s

La doonayo: Masaafada uu baabuurku ku safray

Xalka:

Gaarigu wuxuu ku socdaa xawaare joogto ah. Masaafada uu baabuurku ku socdo:

Masaafada bilowga ah:

s = vt = (25)(60) = 1500 mitir

Masaafada kama dambaysta ah:

s = vt = (25)(t)

Wadarta masaafada = 1500 + 25 t

Gaariga booliiska ayaa si joogto ah u socda. Masaafada uu gaarigu maro:

s = v_o t + ½ at² = (0)(t) + ½ (0.8)(t)²) = 0 + 0.4 t² = 0.4 t²

Marka gaariga boolisku gaaro gaariga, masaafada uu gaariga boolisku maro waxay la mid tahay masaafada uu gaarigu maro.

Masaafada uu baabuurku ku safray = masaafada uu baabuur booliisku ku safray

1500 + 25 t = 0.4 t²

0.4 t² – 25 t – 1500 = 0

Isticmaal qaacidada labajibbaaran:

Masaafada uu gaarigu ku safray:

s = 0.4 t² = (0.4)(100)²) = (0.4)(10,000) = 4000 mitirs = 4 km

10. A baabuur dhaqaaqa 24 m/s si joogto ah biriiga si uu u yeesho hoos u dhac joogto ah oo ah 0.952 m/s². Go'aami xawaaraha gaariga aka dib masaafo dhan 250 meters.

La yaqaan:

Xawaaraha bilowga ah (v)_o) = 24 m/s

Dardar- (a) = – 0.952 m/s² (saxeexan taban sababtoo ah hoos u dhac)

masaafada (d) = 250 mitirs

La doonayo: Xawaaraha gaariga ka dib Mitirka 250s

Xalka:

La yaqaan: xawaaraha bilowga ah (v_o), dardargelinta (A), masaafada (d), la rabay: xawaaraha ugu dambeeya (v_t) markaa isticmaal isla'egta v_t² =v_o² +2 ah d

v_t = xawaaraha kama dambaysta ah,v_o = xawaaraha bilowga ah, a = dardargelinta, d = masaafada

v_t² = (24)² + (2)(-0.952)(250)

v_t² = 576 - 476

v_t² = 100

v_t = √100

v_t = 10m/s

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[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay Dhaqdhaqaaqa Toosan - Xawaaraha joogtada ah

1. Gaadhigu wuxuu ku socdaa xawaare joogto ah 10 m/s. Go'aami masaafada 10 ilbiriqsi iyo 60 ilbiriqsi kadib.

Solution

Xawaaraha joogtada ah ee 10 mitir/ilbiriqsi macnaheedu waa in gaarigu uu socdo 10 mitir 1 ilbiriqsi kasta.

2 ilbiriqsi ka dib, gaarigu wuxuu socdaa 20 mitir,

5 ilbiriqsi ka dib, gaarigu wuxuu socdaa 50 mitir,

10 ilbiriqsi ka dib, gaarigu wuxuu socdaa 100 mitir,

60 ilbiriqsi ka dib, gaarigu wuxuu socdaa 600 mitir.

2. Gaarigu wuxuu ku socdaa waddo toosan xawaare joogto ah oo ah 72 km/saacaddii. Go'aami masaafada gaariga ka dib 2 daqiiqo iyo 5 daqiiqo.

Solution

72 km/saacaddii = (72)(1000 mitir) / 3600 ilbiriqsi = 72,000 / 3600 ilbiriqsi = 20 mitir/ilbiriqsi.

Xawaaraha joogtada ah ee 20 mitir/ilbiriqsi wuxuu la macno yahay in gaarigu uu socdo 20 mitir 1 ilbiriqsi kasta.

120 ilbiriqsi ama 2 daqiiqo ka dib, gaarigu wuxuu socdaa 20 mitir x 120 = 2400 mitir,

300 ilbiriqsi ama 5 daqiiqo ka dib, gaarigu wuxuu socdaa 20 mitir x 300 = 6000 mitir.

3. Jidhku wuxuu ku socdaa waddo toosan 100 mitir 50 ilbiriqsi gudahood. Go'aami xawaaraha jirka.

Solution

100 mitir / 50 ilbiriqsi = 10 mitir / 5 ilbiriqsi = 2 mitir/ilbiriqsi.

4. Go'aami xawaaraha sida ku cad jaantuska hoose….

Solution

Xawaaraha = Masaafada / waqtiga dhaafay

Xawaaraha = 2 mitir / 1 ilbiriqsi = 4 mitir / 2 ilbiriqsi = 6 mitir / 3 ilbiriqsi = 8 mitir / 4 ilbiriqsi = 2 mitir/ilbiriqsi.

5. Baabuurta A iyo B waxay isku soo dhawaadaan waddooyin is barbar socda. Marka masaafada u dhaxaysa labada baabuur ay tahay 100 mitir, baabuurka A wuxuu ku socdaa xawaare joogto ah oo ah 10 m/s, baabuurka B wuxuu ku socdaa xawaare joogto ah oo ah 40 m/s. Go'aami (a) masaafada baabuurka A ka hor inta uusan dhaafin baabuurka B (b) muddada u dhaxaysa kahor inta uusan gaadhiga B dhaafin baabuurka A.

Solution

Gaariga A wuxuu ku socdaa xawaare joogto ah 10 mitir/ilbiriqsi, taasoo la micno ah in gaariga A uu u socdo ilaa 10 mitir 1 ilbiriqsi kasta. 2 ilbiriqsi ka dib, gaarigu wuxuu u socdaa ilaa 20 mitir.

Gaariga B wuxuu ku socdaa xawaare joogto ah 40 mitir/ilbiriqsi, taasoo la micno ah in gaariga B uu u socdo ilaa 40 mitir 1 ilbiriqsi kasta. 2 ilbiriqsi ka dib, gaariga B wuxuu u socdaa ilaa 80 mitir.

20 mitir + 80 mitir = 100 mitir.

(a) Masaafada gaariga A ka hor inta uusan dhaafin gaariga B waa 20 mitir. Masaafada gaariga B ka hor inta uusan dhaafin gaariga A waa 80 mitir.

(b) Muddada u dhaxaysa baabuurka B ka hor inta uusan dhaafin baabuurka A waa 2 ilbiriqsi. Muddada u dhaxaysa baabuurka A ka hor inta uusan dhaafin baabuurka B waa 2 ilbiriqsi

5. Haddii mitirka xawaaraha baabuur waxay muujinaysaa 108 km/saacaddii, go'aami masaafada uu gaarigu ku safray hal daqiiqo gudaheed.

Xalka:

Qalabka xawaaraha lagu cabbiro waa qalab lagu cabbiro xawaaraha. Xawaaraha gaarigu waa 108 km/saacaddii.
108 km / saac = (108) (1000 mitir) / 3600 ilbiriqsi = 30 mitir/ilbiriqsi.

1 daqiiqo = 60 ilbiriqsi

Xawaaraha gaariga 30 mitir/ilbiriqsi waxay la macno tahay in gaarigu uu u socdo ilaa 30 mitir hal ilbiriqsi gudaheed.

Ka dib 1 ilbiriqsi, gaarigu wuxuu u socdaa ilaa 1 x 30 mitir = 30 mitir.

Laba ilbiriqsi ka dib, gaarigu wuxuu u socdaa ilaa 2 x 30 mitir = 60 mitir.

Laba ilbiriqsi ka dib, gaarigu wuxuu u socdaa ilaa 60 x 30 mitir = 1800 mitir.

6. Tom tuuro a kubad toos ah Andrew. Tom iyo Andrew way wada joogaan u kala fog ilaa 10.08 metersKubadda waa la tuuray safka hore iyo dhaqdhaqaaqyo at 20 m/s (iska indha tir cufisjiidadka). Andrew dhacays kubadda 4.00 x 10^-3 ilbiriqsiyo ka dib markii kubadda la tuuray. garaace Dhaqaajiya si joogto ah xawaaraha xawaaraha 5.00 m/s, kubadda waxaa ku dhufta garaace ka dib markii ay Weerarku wuxuu u dhaqaaqaa ilaa…

La yaqaan:

Masaafada u dhaxaysa Tom iyo Andrew = 10.08 mitir

Xawaaraha kubadda (v) = 20 m/s

Muddada (t) = 4 x 10^-3 Ilbiriqsiyo = 0.004 ilbiriqood

Xawaaraha garaacaha (v) = 5 m / s

SE buska: Kubbada waxaa ku dhufta qofka wax ku dhufta ka dib markii kubbadu ay u dhaqaaqday ilaa…

Xalka:

Masaafada Kubadda:

s₁ = vt = (20)(0.004) = 0.08 mitir

Masaafada uu ku socdo weeraryahanka:

s₂ = vt = 5 t

Masaafada Kubadda + masaafada qofka wax ku dhuftay = masaafada u dhaxaysa Tom iyo Andrew.

0.08 + 5 t = 10.08

5 t = 10.08 – 0.08

5 t = 10

t = 10 / 5

t = 2 ilbiriqsi

Masaafada uu ku socdo weeraryahanka:

s₂ = vt = 5 t = (5) (2) = 10 mitir

7. Ugaarsade gaarigiisa wata ayaa eryanaya deero. Gaarigu wuxuu ku socdaa 72 km/saacaddii deeradana waxay ku socotaa xawaare dhan 64.8 km/saacaddii. Marka masaafada u dhaxaysa gaariga iyo deerada ay tahay 2012 mitir, ugaadhsade wuxuu rasaas ku riday qorigiisa. Rasaasta qoriga waxay ka soo baxaysaa 200 m/s. Go'aami muddada deerada la tooganayo.

A. 0.5 ilbiriqsi

B. 1 ilbiriqsi

C. 1.25 ilbiriqsi

D. 1.5 ilbiriqsi

La yaqaan:

Xawaaraha gaariga (v_b= 72 km/h = (72) (1000 m) / 3600 s = 20 m/s

Xawaaraha deerada (v_r= 64.8 km/h = (64.8) (1000 m) / 3600 s = 64800 m / 3600 s = 18 m/s

Marka rasaasta la rido, masaafada u dhaxaysa gaariga iyo deerada (s) = 202 mitir

Xawaaraha dabka (v_p) = 20 m/s + 200 m/s = 220 m/s

Hubka ay haystaan ​​ugaarsatada ku jira gaari ku socda xawaare dhan 20 m/s si xawaaraha gaariga loogu daro xawaaraha rasaasta.

SE buska: Go'aami muddada deerada la tallaalayo

Xalka:

Ka fikir baabuurta iyo deerada oo si joogto ah u socda.

Isle'egta: v = s / t ama s = vt

v = xawaare, s = masaafada, t = kala-goynta waqtiga

Masaafada = 202 + X_r = 202 + v_r t = 202 + 18 t

Masaafada = Y_p =v_p t = 220 t

Masaafada uu maro deerada = masaafada uu maro xabadu

202 + 18 t = 220 t

202 = 220 t – 18 t

202 = 202 t

t = 202 / 202

t = 1 ilbiriqsi

Jawaabta saxda ah waa B.

[wpdm_package id='507′]

[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay Dhaqdhaqaaqa Toosan - Xawaaraha celceliska iyo xawaaraha celceliska

1. Gaari ayaa ku socda waddo toosan oo dhanka bari ah 100 mitir 4 ilbiriqsi gudahood, ka dibna wuxuu aadayaa galbeedka 50 mitir 1 ilbiriqsi gudahood. Go'aami xawaaraha celceliska iyo xawaaraha celceliska.

Solution

Masaafada = 100 mitir + 50 mitir = 150 mitir

Barakaca = 100 mitir – 50 mitir = 50 mitir, dhanka bari.

Waqtiga dhacay = 4 ilbiriqsi + 1 ilbiriqsi = 5 ilbiriqsi.

Xawaaraha celceliska = Masaafada / waqtiga dhaafay = 150 mitir / 5 ilbiriqsi = 30 mitir/ilbiriqsi.

Xawaaraha celceliska = Barakac / waqti dhacay = 50 mitir / 5 ilbiriqsi = 10 mitir/ilbiriqsi.

2. Qofku wuxuu ku socdaa 4 mitir bari 1 ilbiriqsi gudaheed, ka dibna wuxuu ku socdaa 3 mitir waqooyi 1 ilbiriqsi gudaheed. Go'aami celceliska xawaaraha iyo celceliska xawaaraha.

Solution

Masaafada = 4 mitir + 3 mitir = 7 mitir

Barakac = = mitir, dhanka waqooyi-bari.

Waqtigii dhammaaday = 1 ilbiriqsi + 1 ilbiriqsi = 2 ilbiriqsi.

Xawaaraha celceliska = masaafada / waqtiga dhaafay = 7 mitir / 2 ilbiriqsi = 3.5 mitir/ilbiriqsi

Xawaaraha celceliska = barokaca / waqtiga dhaafay = 5 mitir / 2 ilbiriqsi = 2.5 mitir/ilbiriqsi

3. Orodyahan ayaa wareegaya Laydi leydi ah oo dhererkiisu yahay = 50 mitir iyo ballaciisuna yahay 20 mitir. Ka dib markaad laba jeer ku wareegto laydi leydi ah, orodyahanku wuxuu ku soo laabanayaa barta laga bilaabayo. Haddii waqtigu dhaafay = 100 ilbiriqsi, go'aami celceliska xawaaraha iyo celceliska xawaaraha.

Solution

Wareegga leydi = 2(50 mitir) + 2(20 mitir) = 100 mitir + 40 mitir = 140 mitir.

Ku safra leydi 2 jeer = 2(140 mitir) = 280 mitir.

Masaafada = 280 mitir.

Barakac = 0 mitir. (orodyahan ku noqda barta bilowga)

Celceliska xawaaraha = masaafada / waqtiga dhaafay = 280 mitir / 100 ilbiriqsi = 2.8 mitir/ilbiriqsi.

Xawaaraha celceliska = barokaca / waqtiga soo dhaafay = 0 / 100 ilbiriqsi = 0.

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[wpdm_package id='517′]

1. Masaafada iyo barakaca
2. Xawaaraha celceliska iyo xawaaraha celceliska
3. Xawaaraha joogtada ah
4. Dardargelin joogto ah
5. Dhaqdhaqaaq xor ah oo dhaca
6. Dhaqdhaqaaqa hoos u dhaca xilliga dayrta xorta ah
7. Dhaqdhaqaaqa kor iyo hoos ee dayrta xorta ah

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vector-yada - natiijada laba vectors oo isticmaalaya qaybaha vector-ka

1. F₁ = 6 N, F₂ = 10 N. Go'aami vektor-ka natiijada.

Solution

F_1x =F₁ cs 60^o = (6)(0.5) = 3 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F_2x =F₂ cs 30^o = (10)(0.5)√3) = 5√3 = (5)(1.372) = -8.66 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F_1y =F₁ aan lahayn 60^o = (6)(0.5)√3) = 3√3 = (3)(1.372) = 4.116 N (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F_2y =F₂ aan lahayn 30^o = (10)(0.5)) = -5 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F_x =F_1x - F_2x = 3 – 8.66 = -5.66 N

F_y =F_1y - F_2y = 4.116 – 5 = -0.884 N

 

Natiijada labadan ciidan waa 5.7 N.

2. F₁ = 4 N, F₂ = 4 N, F₃ = 8 N. Go'aami vektor-ka natiijada.

Solution

F_1x =F₁ cs 60^o = (4)(0.5) = 2 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F_2x = -4 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F_3x =F₃ cs 60^o = (8)(0.5) = 4 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F_1y =F₁ aan lahayn 60^o = (4)(0.5)√3) = 2√3 N (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F_2y = 0

F_3y =F₃ aan lahayn 60^o = (8)(0.5)√3) = -4√3 N (taban) sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F_x =F_1x - F_2x +F_3x = 2 – 4 + 4 = 2 N

F_y =F_1y +F_2y - F_3y = 2√3 + 0 - 4√3 = -2√3 N

Natiijadu waa 5.7 N.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vector-yada - go'aami natiijada laba fallaadho iyadoo la adeegsanayo isleegyada cosines

1. F₁ = 10 N iyo F₂ = 20 N. Go'aami vektor-ka natiijada.

2. A₁ = 15 iyo A₂ = 9. Xaglaha u dhexeeya labada vector waa 60^oGo'aami vektor-ka natiijada ka soo baxday.

Solution

3. gudaha₁ = 5 iyo v₂ = 12. Xaglaha u dhexeeya labada vector waa 90^oGo'aami vektor-ka natiijada ka soo baxday.

Solution

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vector-yada - go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean

1. Go'aami natiijada labada barakac vectors sida ku cad sawirka hoose.

2. Raadi natiijada laba xoog, 12 N iyo 5 N.

3. Arday ayaa u lugeynaya 4 mitir dhanka galbeed, ka dibna 6 mitir dhanka waqooyi iyo 4 mitir dhanka galbeed. Soo hel barokaca ardayga.

Solution

Barakaca waa 10 anigatan, waqooyi-galbeed.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vector-yada - go'aami qaybaha vektorka

1. Xoogga 20 Newtons wuxuu sameeyaa xagal 30 ah^o iyadoo la adeegsanayo dhidibka x. Soo hel labada qaybood ee x iyo y ee xoogga.

Solution

F_x = F cos 30^o = (20)(koos 30)^o) = (20)(0.5)√3= 10√3 Newton

F_y = F dembi 30^o = (20)(dembi 30^o) = (20)(0.5) = 10 Newton

2. F₁ = 20 Newtons waxay samaysaa xagal 30 ah^o oo leh dhidibka y iyo F₂ = 30 Newtons waxay samaysaa xagal 60 ah^o iyadoo la adeegsanayo dhidibka -x. Soo hel labada qaybood ee x iyo y ee F₁ iyo F₂.

Solution

F_1x =F₁ cos 60^o = (20)(koos 60)^o) = (20)(0.5) = -10 Newtons (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F_2x =F₂ cos 60^o = (30)(koos 60)^o) = (30)(0.5) = -15 Newtons (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F_1y =F₁ dembi 60^o = (20)(dembi 60^o) = (20)(0.5)√3= 10√3 Newton (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F_2y =F₂ dembi 60^o = (30)(dembi 60^o) = (30)(0.5)√3) = -15√3 Newton (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

3. F₁ = 2 N, F₂ = 4 N, F₃ = 6 N. Soo hel labada qaybood ee x iyo y ee F₁, F₂ iyo F₃!

Solution

F_1x =F₁ cos 60^o = (2)(koos 60)^o) = (2)(0.5) = 1 Newton (togan sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka x)

F_2x =F₂ cos 30^o = (4)(koos 30)^o) = (4)(0.5)√3) = -2√3 Newton (taban sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka -x)

F_3x =F₃ cos 60^o = (6)(koos 60)^o) = (6)(0.5) = 3 Newton (togan sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka x)

F_1y =F₁ dembi 60^o = (2)(dembi 60^o) = (2)(0.5)√3) = √3 Newton (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F_2y =F₂ aan lahayn 30^o = (4)(dembi 30^o) = (4)(0.5) = 2 Newtons (togan sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka y)

F_3y =F₃ dembi 60^o = (6)(dembi 60^o) = (6)(0.5)√3) = -3√3 Newton (taban sababtoo ah waxay leedahay jiho isku mid ah oo leh dhidibka -y)

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah

Dhibaatooyinka lagu xalliyay vector-yada - natiijada vector-ka xariiqda

1. Arday ayaa u lugeeya waqooyi ilaa 10 mitir ka dibna dhanka koonfureed ilaa 4 mitir. Barakaca ardayga waa…

Solution

R = 10 m – 4 m = 6 mitir

Cabbirka barakac waa 6 mitir, jihada barokaca waa waqooyi.

2. F₁ = 10 N, F₂ = 15 N. Go'aami vector-ka natiijada…

Solution

R = 10 N + 15 N = 25 Newton

Cabbirka vektor-ka natiijada keenay waa 25 Newtons, jihada vektor-ka natiijada keenay waa bari ama midig.

3. F₁ = 4 N, F₂ = 8 N. Go'aami vector-ka natiijada…

Solution

R = 8 N – 4 N = 4 Newton

Cabbirka vektor-ka natiijada keenay waa 4 Newtons, jihada vektor-ka natiijada keenay waa bari ama midig.

4. F₁ = 10, F₂ = 15 N, F₃ = 5 N. Go'aami vector-ka natiijada…

Solution

R = 10 N + 5 N – 15 N = 0

Cabbirka vektor-ka natiijada ka soo baxday waa 0.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Go'aami natiijada vektor xariiq ah
2. Go'aami qaybaha vektorka
3. Go'aaminta natiijada laba fallaadho iyadoo la adeegsanayo aragtida Pythagorean
4. Go'aami natiijada laba fallaadho iyadoo la adeegsanayo isle'egta cosines
5. Go'aami natiijada laba vectors adoo isticmaalaya qaybaha vectors-ka

Akhri wax dheeraad ah