Go'aami natiijada laba vektor iyadoo la adeegsanayo qaybaha vektorka

Dhibaatooyinka lagu xalliyay vector-yada - natiijada laba vectors oo isticmaalaya qaybaha vector-ka

1. F₁ = 6 N, F₂ = 10 N. Go'aami vektor-ka natiijada.

Solution

F_1x =F₁ cs 60^o = (6)(0.5) = 3 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F_2x =F₂ cs 30^o = (10)(0.5)√3) = 5√3 = (5)(1.372) = -8.66 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F_1y =F₁ aan lahayn 60^o = (6)(0.5)√3) = 3√3 = (3)(1.372) = 4.116 N (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F_2y =F₂ aan lahayn 30^o = (10)(0.5)) = -5 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F_x =F_1x - F_2x = 3 – 8.66 = -5.66 N

F_y =F_1y - F_2y = 4.116 – 5 = -0.884 N

Natiijada labadan ciidan waa 5.7 N.

2. F₁ = 4 N, F₂ = 4 N, F₃ = 8 N. Go'aami vektor-ka natiijada.

Solution

F_1x =F₁ cs 60^o = (4)(0.5) = 2 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F_2x = -4 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F_3x =F₃ cs 60^o = (8)(0.5) = 4 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F_1y =F₁ aan lahayn 60^o = (4)(0.5)√3) = 2√3 N (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F_2y = 0

F_3y =F₃ aan lahayn 60^o = (8)(0.5)√3) = -4√3 N (taban) sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F_x =F_1x - F_2x +F_3x = 2 – 4 + 4 = 2 N

F_y =F_1y +F_2y - F_3y = 2√3 + 0 - 4√3 = -2√3 N

Natiijadu waa 5.7 N.

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