Go'aami natiijada laba vektor iyadoo la adeegsanayo qaybaha vektorka

Dhibaatooyinka lagu xalliyay vectors - go'aami natiijada laba vectors iyadoo la adeegsanayo qaybaha vector-ka

1. F ₁ = 6 N, F ₂ = 10 N. Go'aami vector-ka natiijada.

Solution

F _1x = F ₁ cos 60 ^o = (6)(0.5) = 3 N ( togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x )

F _2x = F ₂ cos 30 ^o = (10)(0.5 √ 3) = 5 √ 3 = (5)(1.372) = -8.66 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F _1y = F ₁ sin 60 ^o = (6)(0.5 √ 3) = 3 √ 3 ​​= (3)(1.372) = 4.116 N ( togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y )

F _2y = F ₂ sin 30 ^o = (10)(0.5 ) = -5 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F _x = F _1x – F _2x = 3 – 8.66 = -5.66 N

F _y = F _1y - F _2y = 4.116 - 5 = -0.884 N

Natiijada labadan ciidan waa 5.7 N.

2. F ₁ = 4 N, F ₂ = 4 N, F ₃ = 8 N. Go'aami vector-ka natiijada.

Solution

F_1x =F₁ cs 60^o = (4)(0.5) = 2 N (togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x)

F _2x = -4 N (taban sababtoo ah waxay leedahay jiho la mid ah dhidibka -x)

F _3x = F ₃ cos 60 ^o = (8)(0.5) = 4 N ( togan sababtoo ah waxay leedahay jiho la mid ah dhidibka x )

F_1y =F₁ aan lahayn 60^o = (4)(0.5)√3) = 2√3 N (togan sababtoo ah waxay leedahay jiha la mid ah dhidibka y)

F _2y = 0

F_3y =F₃ aan lahayn 60^o = (8)(0.5)√3) = -4√3 N (taban) sababtoo ah waxay leedahay jiho la mid ah dhidibka -y)

F _x = F _1x – F _2x + F _3x = 2 – 4 + 4 = 2 N

F_y =F_1y +F_2y - F_3y = 2√3 + 0 - 4√3 = -2√3 N

Natiijadu waa 5.7 N.

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