Su'aalaha Tusaalaha ah ee Sharciga Coulomb

10 Tusaalooyin oo ka mid ah Sharciga Coulomb

1. Laba dallac ayaa loo habeeyey sida ku cad jaantuska hoose. Dallaca A waa +8 micro Coulombs halka dallacaadda B ay tahay -5 micro Coulombs. Cabbirka xoogga Coulomb ee ku shaqeeya labada dallac waa… (k = 9 x 10 ⁹ Nm ² C ⁻² , 1 micro Coulombs = 10 ⁻⁶ C)

Dood
Waa la garanayaa :

La weydiiyay : Baaxadda awoodda korontada ee labada dacwadoodba ku shaqeysa
Jawab :

Qaacidada sharciga ee Coulomb :

Baaxadda xoogga korontada ee ku shaqeeya labada dacwadood:

2. Dalacaadda korontada P = +10 micro Coulombs iyo dalacaadda korontada Q = +20 micro Coulombs ayaa loo kala saaray sida ku cad sawirka. Cabbirka xoogga Coulomb ee ku shaqeeya labada dalacadood waa…

Dood
Waa la garanayaa :

La weydiiyay Baaxadda ciidanka Coulomb ee labada dacwadoodba ku jira
Jawab :

Baaxadda xoogga Coulomb ama xoogga korontada ee labada dallacba ku shaqeeya waa 125 Newtons.

3. Saddex dallacaad koronto ayaa si gaar ah loo dhigay sida sawirka ka muuqata! Dallacaad A = -5 micro Coulombs, dallacaad B = +10 micro Coulombs, iyo dallacaad C = -12 micro Coulombs. Cabbirka iyo jihada xoogga korontada ee dallacaad B waa…

Dood
Waa la garanayaa :

La weydiiyay : Cabbirka iyo jihada xoogga korontada ee ku jira dallacaadda B
Jawab :
Xoogga korontada ee ku jira dallacaadda B waa natiijada xoogga korontada ee u dhexeeya dallacaadaha A iyo B iyo xoogga korontada ee u dhexeeya dallacaadaha B iyo C.
Xoogga korontada ee u dhexeeya dallacaadaha A iyo B :

Kharash A waa taban, kharash B-na waa togan, sidaa darteed jihada xoogga Coulomb waxay u socotaa kharash A waxayna ka fog tahay kharash B (bidixda).
Xoogga korontada ee u dhexeeya dallacaadaha B iyo C :

Dalac B waa togan, dalac C-na waa taban, sidaa darteed jihada xoogga Coulomb waxay u socotaa dalac C iyo meel ka fog dalac B (midigta).
Koronto ka dhalatay oo ku jirta dallac B :
Jihada F_AB bidix iyo jihada F_BC dhanka midig.
F_B =F_AB - F_BC = 675 N – 125 N = 550 Newtons.
Jihada korontada ee ka dhalatay dallacaadda B (F)_B) = jihada xoogga korontada F_AB, taas oo ah dhanka C (midigta).

4. Dalacadaha korontada +Q ₁ = 10 micro Coulombs, +Q ₂ = 50 micro Coulombs iyo Q ₃ waa la kala saaray sida ku cad sawirka. Si xoogga korontada ee ku shaqeeya dalacaadda Q ₂ = eber markaa dalacaadda Q ₃ waa…

Dood
Waa la garanayaa :
Kharash 1 (q₁) = +10 μC = +10 x 10^-6 Coulomb
Kharash 2 (q₂) = +50 μC = +50 x 10^-6 Coulomb
Masaafada u dhaxaysa kharashyada 1 iyo 2 (r₁₂) = 2 cm = 0,02 m = 2 x 10^-2 m
Masaafada u dhaxaysa kharashyada 2 iyo 3 (r₂₃) = 6 cm = 0,06 m = 6 x 10^-2 m
Awoodda korantada ee ka dhalatay ee ku jirta charge 2 (F)₂= 0
La weydiiyay : khidmad 3 (q₃)
Jawab :
Xoogga korontada ee ku jira 2 waa natiijada ka dhalata xoogga korontada ee u dhexeeya 1 iyo 2 iyo xoogga korontada ee u dhexeeya 2 iyo 3.
Xoogga korontada ee u dhexeeya dallacaadaha 1 iyo 2 :

Kharash 1 waa togan yahay, kharash 2na waa togan yahay, marka jihada waa F₁₂ waxay u socotaa kharashka 3 (midigta).
Xoogga korontada ee u dhexeeya dallacaadaha 2 iyo 3 :

Kharash 2 waa togan yahay, kharash 3na waa togan yahay, marka jihada waa F₂₃ waxay u socotaa khidmadda 1 (bidixda).
Korontada ka dhalatay ee la dallacay 2 = 0 :
Jihada F₁₂ dhanka midig iyo jihada F₂₃ dhanka bidix.

5. Sawirka dhinaca, xoogga carada leh ee ay la kulmeen labada dabadood waa 144 N, marka masaafada u dhaxaysa labada dabadood waa… (1 μC = 10 ^-6 C iyo k = 9.10 ⁹ Nm ² .C ^-2 )

A. 4 cm

B. 5 cm

C. 8 cm

D. 10 cm

E. 12 cm

Dood

Waa la ogyahay in:

Xoogga korontada (F ₁₂ ) = 144 N

Dalacaadda 1 (q ₁ ) = 10 μC = 10 x 10 ^-6 C

Dalacaadda 2 (q ₂ ) = 4 μC = 4 x 10 ^-6 C

Joogtada Coulomb (k) = 9 x 10 ⁹ Nm ² .C ^-2

C = Coulomb, N = Newton, m = mitir

Su'aal: Masaafada u dhaxaysa labada dallac (r)

Jawaab:

Qaacidada sharciga ee Coulomb:

Sharaxaad: F = xoog koronto, k = Joogtada Coulomb, q = dallacaadda korontada, r = masaafada u dhaxaysa labada dallacaadda korontada.

Masaafada u dhaxaysa labada dallac (r) = 5 x 10 ^-2 mitir = 5 x 10 ^-2 x 10 ² sentimitir = 5 sentimitir.

Jawaabta saxda ah waa B.

6. Laba dallac koronto ayaa sida ka muuqata sawirka hoose. Haddii xoogga Coulomb ee labada dallac ay la kulmaan uu yahay 3,6 N, markaa masaafada u dhaxaysa labada dallac waa… (1 μC = 10 ^-6 C iyo k = 9.10 ⁹ Nm ² .C ^-2 )

A. 30,0 cm

B. 27,0 cm

C. 9,0 cm

D. 3,0 cm

E. 0,3 cm

E. 12 cm

Dood

Waa la ogyahay in:

Xoogga korontada (F ₁₂ ) = 3,6 N

Dalacaadda 1 (q ₁ ) = 9 μC = 9 x 10 ^-6 C

Dalacaadda 2 (q ₂ ) = 4 μC = 4 x 10 ^-6 C

Joogtada Coulomb (k) = 9 x 10 ⁹ Nm ² .C ^-2

C = Coulomb, N = Newton, m = mitir

Su'aal: Masaafada u dhaxaysa labada dallac (r)

Jawaab:

Qaacidada sharciga ee Coulomb:

Sharaxaad: F = xoog koronto, k = Joogtada Coulomb, q = dallacaadda korontada, r = masaafada u dhaxaysa labada dallacaadda korontada.

Masaafada u dhaxaysa labada dallac (r) = 0,3 mitir = 0,3 x 100 sentimitir = 30 sentimitir.

Jawaabta saxda ah waa A.

7. Saddexda dhibcood ee dallacaadda waxay ku yaalliin geesaha saddexagalka, sida ku cad sawirka. Cabbirka xoogga Coulomb ee barta A waa… (k = 9.10 ⁹ Nm ² .C ^-2 ; 1 μ = 10 ^-6 )

A. 10 N

B. 60 N

C. 90 N

D. 90 √2 N

E. 100 √2 N

Dood

Waa la ogyahay in:

Dalac A (q _A ) = -2 μC = -2 x 10 ^-6 C

Dalacaadda B (q _B ) = 8 μC = 8 x 10 ^-6 C

Dalacaadda C (q _C ) = 4,5 μC = 4,5 x 10 ^-6 C

Joogtada Coulomb (k) = 9 x 10 ⁹ Nm ² .C ^-2

Masaafada u dhaxaysa khidmadaha A iyo B (r _AB ) = 4 cm = 4 x 10 ^-2 mitir

Masaafada u dhaxaysa dallacaadaha A iyo C (r _AC ) = 3 cm = 3 x 10 ^-2 mitir

C = Coulomb, N = Newton, m = mitir

Su'aal: Awoodda korontada ee barta A

Jawaab:

Qaacidada sharciga ee Coulomb:

Sharaxaad: F = xoog koronto, k = Joogtada Coulomb, q = dallacaadda korontada, r = masaafada u dhaxaysa labada dallacaadda korontada.

Xoogga korontada ee barta A:

F _AB iyo F _AC waxay sameeyaan xagal qumman sidaa darteed xoogga natiijada waxaa lagu xisaabiyaa qaacidada Pythagorean.

Jawaabta saxda ah waa D.

8. Laba shay oo leh koronto Q₁ iyo Q₂ masaafada r cm, waxay abuurtaa xoog diidmo ah oo ah 10 N. Kadibna dallacaadda Q₁ loo wareejiyay si xoogga soo baxa uu noqdo 40 N. Joogtada k = 9 x 10⁹ Nm².C^-2, ka dibna kharashka Q₁ waa in la dhaqaajiyaa…

A. 1/2 r meel u jirta Q ₂

B. 1/2 r ayaa soo dhawaaday _Q2

C. 1 r wuxuu ka guurayaa Q ₂

D. 2 r waxay ku dhowdahay _Q2

E. 2 r wuxuu ka guurayaa Q ₂

Dood

Waa la ogyahay in:

Masaafada u dhaxaysa Q ₁ iyo Q ₂ = r cm

Xoogga wax ka celiya (F) = 10 N

Haddii dallacaadda Q1 _la beddelo, xoogga diida (F) = 40 N

Joogto ah (k) = 9 x 10 ⁹ Nm ² .C ^-2

Su'aal: khidmadda Q _1aad waa in la raro...

Jawaab:

Qaacidada xoogga korontada:

F = k Q ₁ Q ₂ / r ²

Masaafada (r) waxay si liddi ku ah ugu dhigantaa xoogga (F). Taas macnaheedu waa haddii xooggu ka weyn yahay, masaafada u dhaxaysa dallacaadaha way yaraan doontaa. Markaa, dallacaadda Q1 _waa in loo dhaqaajiyaa meel u dhow dallacaadda _Q2.

Jawaabta saxda ah waa B.

9. Koronto + q₃ = 20 μC, +q₂ = 10 μC iyo q₁ sida sawirka ka muuqata. Si ciidanka Coulomb ay u fuliyaan dacwadda q₂ = eber ka dibna kharashka q₁ waa…
A. +2 μC
B. –2 μC
C. +5 μC
D. –5 μC
E. +8 μC
Dood:
Waa la garanayaa :
+q₃ = 20 μC
+q₂ = 10 μC
La weydiiyay :
q₁ = ?
Jawab :
Kharashka ku baxaya q₂ shaqaalaha F₂₃ iyo F₂₁, halkaas oo F₂₃ bidixda ayaa loo jiheeyay. Si xooggii ka dhashay uu u shaqeeyo q₂ waxay la mid tahay eber marka loo eego q₁ waa inay noqotaa mid togan si xoogga F uu u noqdo mid togan₂₁ dhanka midig u socda.
Kharashka q₁ = +5 μC.
Jawaabta saxda ah waa C.

10. Saddex dallacaad koronto + q ₁ = 5 μC, + q ₂ = 10 μC iyo + q ₃ = 10 μC ayaa ku jira xariiq. Haddii a = 10 cm markaas baaxadda iyo jihada xoogga korontada ee ku shaqeeya dallacaad q ₂ waa… (k = 9 x 10 ⁹ Nm ² C ^-2 )

A. 7,5 N dhanka q₁
B. 11,25 N dhanka q₂
C. 15 N dhanka q₁
D. 22,5 N dhanka q₁
E. 78,75 N dhanka q₁
Dood:
Waa la garanayaa :
q₁= 5 μC, q₂ = 10 μC iyo q₃ = 10 μC
a = 0,1 m

La weydiiyay :
Baaxadda iyo jihada xoogga Coulomb ee ka dhashay q₂ ?
Jawab :
Waxaa jira laba ciidan oo Coulomb ah oo ku howlan q₂, oo ay ku jiraan F₂₁ iyo F₂₃, halkaas oo jihooyinka labadan awoodood ay iska soo horjeedaan. q₁ togan iyo q₂ togan si xoog F uu u noqdo mid wanaagsan₂₁ u socota dhanka midig (dhinaca q)₃) q₂ togan iyo q₃ togan si xoog F uu u noqdo mid wanaagsan₂₃ u soco dhanka bidix (dhinaca q)₁).

Baaxadda xoogga korontada ee ka dhashay = 90 N – 11,25 N = 78,75 N.
Jihada xoogga ka dhashay waxay la mid tahay jihada xoogga F₂₃, dhanka q₁.
Jawaabta saxda ah waa E.