Tusaale ahaan su'aalaha goobta korantada

1. Barta A waxay ku taal masaafo dhan 5 cm marka loo eego dallacaadda +10 micro Coulombs. Cabbirka iyo jihada goobta korantada ee barta A waa… (k = 9 x 10⁹ Nm²C^-2, 1 micro Coulomb = 10^-6 C)
Dood
Waa la garanayaa :

La weydiiyay : Cabbirka iyo jihada goobta korantada ee barta A
Jawab :

Jihada goobta korantada ee barta A :
Dareeraha korontadu waa mid togan, sidaa darteed jihada goobta korontadu waa mid ka fog dareeraha korontada oo ka fog barta A.

2. Masaafada u dhaxaysa barta P iyo dallacaadda -20 micro Coulombs waa 10 cm. Go'aami xoogga goobta korantada iyo jihada goobta korontada ee barta P.
Dood
Waa la garanayaa :

La weydiiyay : Cabbirka iyo jihada goobta korantada ee barta P
Jawab :

Jihada goobta korantada ee barta A :
Dareeraha korontadu waa taban, sidaa darteed jihada goobta korontadu waxay u jeeddaa dareeraha korontada waxayna ka fog tahay barta P.

3. Laba dallac koronto ayaa kala fogaada masaafada 40 cm. Xoogga goobta korontada iyo jihada goobta korontada ee barta ku taal bartamaha labada dallac ayaa ah…

Dood
Ka soo qaad in barta ku taal bartamaha labada dacwadood ay tahay barta P.
Waa la garanayaa :

La weydiiyay : baaxadda iyo jihada goobta korontada ee barta ku taal bartamaha labada dallacaad (dhibicda P)
Jawab :
Goobta korantada ee ay soo saarto dallacaadda A barta P :

Dalac A waa taban sidaa darteed jihada goobta korontada waxay u socotaa dalac A (bidixda).
Goobta korantada ee ay soo saarto dallacaadda B ee barta P :

Dalac B waa togan sidaa darteed jihada goobta korontada waxay ka fog tahay dalac B (bidixda).
Goobta korantada ee natiijada ka dhalatay barta A :
E_A iyo E_B sidaas darteed waxaa la isku daraa isla jihadaas.
E = E_A +E_B
E = (4,5 x 10⁵) + (9 x 10⁵)
E = 13,5 x 10⁵ N / C
Jihada goobta korontada waxay u socotaa dhanka dallacaadda A iyo dhanka dallacaadda B (dhinaca bidix).

4. Xoogga goobta korontada waa eber meel fog oo ka mid ah…

Dood
Dalacaadda A waa togan, dalacaadda B-na waa togan, sidaa darteed xoogga goobta korontadu waa eber, oo ku yaal bartamaha labada dallac. Bal qiyaas meesha xoogga goobta korontadu yahay eber waa barta P.
Waa la garanayaa :

La weydiiyay : eber xoog oo goobta korontada ah ayaa ku taal meel fog oo ka mid ah…
Jawab :
Goobta korantada ee ay soo saarto dallacaadda A barta P :

Kharash A waa togan sidaa darteed jihada goobta korantada ee uu abuuray kharajka A ee barta P waa ka fog tahay kharajka A (midigta).
Goobta korantada ee ay soo saarto dallacaadda B ee barta P :

Dalac B waa togan sidaa darteed jihada goobta korantada ee uu abuuray dalac B ee barta P waa ka fog tahay dalac B (bidixda).
Goobta korantada ee natiijada ka dhalatay barta P = 0 :
E_A iyo E_B jihada ka soo horjeeda.
E_A - E_B = 0
E_A =E_B

Isticmaal qaacidada ABC si aad u go'aamiso qiimaha a.

Xoogga goobta korantada eber ah wuxuu ku yaal meel 8 cm u jirta dallacaadda A ama 12 cm u jirta dallacaadda B.

5. Masaafada u dhaxaysa laba dallac A iyo B waa 3 mitir. Barta O waxay u dhaxaysaa labada dallac waxayna u jirtaa 2 mitir dallac B. q_A = –300 μC iyo q_B = 600 μC. k = 9 × 10⁹ N m² C^-2Xoogga goobta korantada ee barta O waxaa saameeya kharashka q_A iyo q_B waa…
A. 9 × 10⁵ N / C
B. 18 × 10⁵ N / C
C. 52 × 10⁵ N / C
D. 60 × 10⁵ N / C
E. 81 × 10⁵ N / C

Dood:
Waa la garanayaa :
q_A = –300 μC, q_B = 600 μC, k = k = 9 × 10⁹ N m² C^-2
La weydiiyay :
Waa maxay xoogga goobta korantada (E) ee barta O?
Jawab :
Xoogga goobta ee ka dhashay:
E = E_A +E_B
E = (2700 x 10³ Ma jiro) + (5400 x 10³ Ma jiro)
E = 8100 x 10³ N / C
E = 81 x 10⁵ N / C
Jawaabta saxda ah waa E.

6. Laba dacwadood midkiiba q₁ = -20 μC iyo q₂ = -40 μC. Haddii barta P ay tahay 20 cm laga bilaabo q.₂ Xoogga goobta korantada ee ka dhalatay waa eber, ka dibna qiimaha x waa…
A. 11 cm
B. 12 cm
C. 13 cm
D. 14 cm
E. 15 cm

Dood:
Waa la garanayaa :
q₁ = -20 μC, q₂ = -40 μC, r₂ = 0,2 m, r₁ =x
La weydiiyay :
Masaafada barta P laga bilaabo q₁ (x)?
Jawab :
Xoogga goobta korantada ee ka dhalatay waa eber barta P:
Jawaabta saxda ah waa D.

7. TDuck A wuxuu ku yaal bartamaha laba dallacaad oo isku cabbir ah laakiin noocyo kala duwan oo kala fog. Cabbirka xoogga goobta korantada ee barta A waqtigaas waa 36 NC^-1Haddii dhibicda A loo wareejiyo ¼ meel u dhow mid ka mid ah dallacyada, markaa baaxadda xoogga goobta korantada ee dhibicda A ka dib marka la wareejiyo waa ....

A. 100 NC^-1

B. 96 NC^-1

C. 80 NC^-1

D. 60 NC^-1

E. 16 NC^-1

Dood

Waa la ogyahay in :

Kharash 1 (q₁) = +Q

Kharash 2 (q₂) = -Q

Masaafada u dhaxaysa kharashka 1 iyo dhibicda A (r)_1A) = ½ a

Masaafada u dhaxaysa kharashka 2 iyo dhibicda A (r)_2A) = ½ a

Xoogga goobta korantada ee barta A (E)_A) = 36 NC^-1

La weydiiyay : Haddii dhibicda A loo wareejiyo ¼ meel u dhow mid ka mid ah dallacyada, markaa xoogga goobta korantada ee dhibicda A waa…

Jawaab :

Tahap 1.

Si aad u xisaabiso xoogga goobta korantada ee barta A, u qaado in uu jiro dallac tijaabo oo togan meeshaas. Joogitaanka dallac tijaabo oo togan wuxuu saameeyaa jihada goobta korontada.

Goobta korantada ee ay soo saarto kharashka + Q ee barta A :

Dalacaadda tijaabada waa togan tahay, dalacaadda 1aadna waa togan tahay, sidaa darteed jihada goobta korontada waxay u jeeddaa dalacaadda 2aad.

Goobta korantada ee ay soo saarto charge-ka -Q barta A :

Dalacaadda tijaabada waa togan tahay, dalacaadda 2-na waa taban tahay, sidaa darteed jihada goobta korontada waxay u jeeddaa dalacaadda 2-aad.

Goobta korantada ee natiijada ka dhalatay barta A :

Marxaladda 2aad.

Haddii dhibicda A loo wareejiyo meel u dhow dallacaadda 1 markaas:

Masaafada u dhaxaysa kharashka 1 iyo dhibicda A (r)_1A) = ¼ a

Masaafada u dhaxaysa kharashka 2 iyo dhibicda A (r)_2A) = ¾ a

Goobta korantada ee ay soo saarto kharashka + Q ee barta A :

Dalacaadda tijaabada waa togan tahay, dalacaadda 1aadna waa togan tahay, sidaa darteed jihada goobta korontada waxay u jeeddaa dalacaadda 2aad.

Goobta korantada ee ay soo saarto charge-ka -Q barta A :

Dalacaadda tijaabada waa togan tahay, dalacaadda 2-na waa taban tahay, sidaa darteed jihada goobta korontada waxay u jeeddaa dalacaadda 2-aad.

Goobta korantada ee natiijada ka dhalatay barta A :

Jawaabta saxda ah waa C.

8. Laba walxood midkiiba wuxuu leeyahay kharash q_A = 1 μC iyo q_B = 4 μC waxaa la dhigaa meel 4 cm u jirta (k = 9 x 10⁹ N m² C^-2) Xoogga goobta korantada ee ku taal bartamaha q_A iyo q_B waa…

A. 6,75 x 10⁷ NC^-1

B. 4,50 x 10⁷ NC^-1

C. 4,20 x 10⁷ NC^-1

D. 3,60 x 10⁷ NC^-1

E. 2,25 x 10⁷ NC^-1

Dood

Waa la ogyahay in :

Dalac A (q)_A) = 1 μC = 1 x 10^-6 C

Dalac B (q)_B) = 4 μC = 4 x 10^-6 C

k = 9 x 10 ⁹ N m ² C ⁻²

Masaafada u dhaxaysa khidmadaha A iyo B (r)_AB) = 4 cm = 0,04 mitir

Masaafada u dhaxaysa charge A iyo bartamaha barta (r)_A) = 0,02 mitir

Masaafada u dhaxaysa charge B iyo barta dhexe (r)_B) = 0,02 mitir

La weydiiyay : Xoogga goobta korantada ee bartamaha q_A iyo q_B waa…

Jawaab :

Si loo xisaabiyo xoogga goobta korantada ee bartamaha q_A iyo q_B , iyadoo la malaynayo in uu jiro kharash tijaabo oo togan oo ku yaal bartamaha labada kharash. Joogitaanka kharash tijaabo oo togan wuxuu saameeyaa jihada goobta korantada.

Goobta korantada ee ay soo saarto dallacaadda A ee bartamaha :

Dalacaadda tijaabada waa togan, dalacaadda A-na waa togan, sidaa darteed jihada goobta korontada waxay u jeeddaa dalacaadda B.

Goobta korantada ee ay soo saarto dallacaadda B ee bartamaha :

Dalacaadda tijaabada waa togan tahay, dalacaadda B-na waa togan tahay, sidaa darteed jihada goobta korontada waxay u jeeddaa dalacaadda A.

Goobta korantada ee ka dhalatay barta dhexe :

E_A iyo E_B jihada ka soo horjeeda.

E = E_B - E_A = 9x10⁷ - 2,25 x 10⁷ = 6,75x10⁷ NC^-1

Jawaabta saxda ah waa A.

9. Fiiri sawirka laba dalac oo hoose! Xaggee bay ku taal barta P si xoogga goobta korantada ee barta P uu ula mid noqdo eber? (k = 9 x 10⁹ Nm²C^-2, 1 μC = 10^-6 C)

A. midig bartamaha Q₁ iyo Q₂

B. 6 cm dhanka midig ee Q₂

C. 6 cm dhanka bidix ee Q₁

D. 2 cm dhanka midig ee Q₂

E. 2 cm dhanka bidix ee Q₁

Dood

Si aad u xisaabiso xoogga goobta korantada ee barta P, u qaado in ay jirto dallac tijaabo oo togan oo ku yaal barta P. Q₁ togan iyo Q₂ taban, sidaa darteed dhibicda P waa inay ku taal dhinaca midig ee Q₂ ama dhanka bidix ee Q₁. Haddii dhibicda P ay bidixda ka tahay Q₁; goobta korantada ee ay soo saarto dhibicda Q₁ barta P jihada waxay u socotaa bidix (ka fog Q)₁) iyo goobta korontada ee Q-da laga soo saaray₂ barta P jihada waxay u socotaa dhanka midig (dhinaca Q)₁Maadaama jihada garoonka korontadu ay ka soo horjeeddo, labadooduba way isdhaafsadaan si xoogga goobta korontadu ee barta P uu noqdo eber.

Waa la ogyahay in :

Q ₁ = +9 μC = +9 x 10 ⁻⁶ C

Q ₂ = -4 μC = -4 x 10 ⁻⁶ C

k = 9 x 10 ⁹ Nm ² C ⁻²

Masaafada u dhaxaysa dallacaadda 1 iyo dallacaadda 2 = 3 cm

Masaafada u dhaxaysa Q₁ iyo dhibic P (r)_1P) = a

Masaafada u dhaxaysa Q₂ iyo dhibic P (r)_2P) = 3 cm + a

La weydiiyay : Xaggee bay ku taal barta P si xoogga goobta korantada ee barta P uu ula mid noqdo eber?

Jawaab :

Barta P waxay bidixda ka xigtaa Q₁.

Goobta korantada ee natiijada ka dhalatay barta A :

Isticmaal qaacidada ABC si aad u go'aamiso qiimaha a.

10. Fiiri sawirka soo socda! Lacag q₃ meel fog oo 5 cm u jirta q₂, ka dibna xoogga goobta korantada ee dallacaadda q₃ waa… (1 µC = 10^-6 C)

A. 4,6 x 10⁷ NC^-1

B. 3,6 x 10⁷ NC^-1

C. 1,6 x 10⁷ NC^-1

D. 1,4 x 10⁷ NC^-1

E. 1,3 x 10⁷ NC^-1

Dood

Kharashka q₃ meel fog oo 5 cm u jirta q₂, taasoo la micno ah in aan loo jeedin dhanka bidix ee q₂ laakiin dhinaca midig q₂Haddii dhinaca bidix uu ku yaal q₂ markaas goobta korontada ee ka dhalata waa eber. Tani waa sababta oo ah masaafada u dhaxaysa dallacaadaha q₃ oo leh kharash q₁ iyo q₂ waa 5 cm, baaxadda kharashkana waa q₁ la mid ah qiimaha q₂.

Sababtoo ah kharashka q₃ togan ka dibna jihada garoonka korontada kharashka ku baxaya q₃ dhanka qiimaha taban q₂ (E₂) iyo ka fog qiimaha togan q₁ (E₁) Goobta korantada ee ka dhalata waa wadarta awoodaha goobta korantada E₁ iyo E₂.

Waa la ogyahay in :

Kharashka q₁ = 5 µC = 5 x 10^-6 Coulomb

Kharashka q₂ = 5 µC = -5 x 10^-6 Coulomb

Masaafada u dhaxaysa khidmadaha q₁ iyo kharashka q₃ (r₁) = 15 cm = 0,15 m = 15 x 10^-2 meter

Masaafada u dhaxaysa khidmadaha q₂ iyo kharashka q₃ (r₂) = 5 cm = 0,05 m = 5 x 10^-2 meter

k = 9 x 10 ⁹ N m ² C ^-2

La weydiiyay Awoodda goobta korantada ee dallacaadda q₃

Jawaab :

Xoogga goobta korontada 1

E ₁ = kq ₁ / r ₁ ²

E ₁ = (9 x 10 ⁹ )(5 x 10 ^-6 ) / (15 x 10 ^-2 ) ²

E ₁ = (45 x 10 ³ ) / (225 x 10 ^-4 )

E ₁ = 0,2 x 10 ⁷ N/C

Xoogga goobta korontada 2

E ₂ = kq ₂ / r ₂ ²

E ₂ = (9 x 10 ⁹ )(5 x 10 ^-6 ) / (5 x 10 ^-2 ) ²

E ₂ = (45 x 10 ³ ) / (25 x 10 ^-4 )

E ₂ = 1,8 x 10 ⁷ N/C

Xoogga garoonka korantada ee ka dhashay

Xoogga goobta korantada ee ka dhalatay qiimaha q₃ waa:

E = E ₂ – E ₁ = (1,8 x 10 ⁷ ) – (0,2 x 10 ⁷ ) = 1,6 x 10 ⁷ N/C

Jihada goobta korontada waxay u socotaa dhanka bidix ama dhanka E.₂.

Jawaabta saxda ah waa C.

11. Laba dallacaad koronto ayaa loo kala saaray sida ku cad sawirka. Xoogga goobta korantada ee barta P waa… (k = 9 x 10⁹ N m² C^-2)

A. 9,0 x 10⁹ NC^-1

B. 4,5 x 10⁹ NC^-1

C. 3,6 x 10⁹ NC^-1

D. 5,4 x 10⁹ NC^-1

E. 4,5 x 10⁹ NC^-1

Dood

Waa la ogyahay in :

Kharashka q_A = +2,5 C

Kharashka q_B = -2 C

Masaafada u dhaxaysa khidmadaha q_A iyo dhibic P (r)_A) = 5 m

Masaafada u dhaxaysa khidmadaha q_B iyo dhibic P (r)_B) = 2 m

k = 9 x 10 ⁹ N m ² C ^-2

La weydiiyay Xoogga goobta korontada ee barta P

Jawaab :

Xoogga goobta korontada A

E _A = kq _A / r _A ²

E _A = (9 x 10 ⁹ ) (2,5) / (5) ²

E _A = (22,5 x 10 ⁹ ) / 25

EA = 0,9 x 10 ^{9 N} _/ C

Xoogga goobta korontada B

E _B = kq _B / r _B ²

E _B = (9 x 10 ⁹ )(2) / (2) ²

E _B = (18 x 10 ⁹ ) / 4

E_B = 4,5x10⁹ N / C

Xoogga garoonka korantada ee ka dhashay

Xoogga goobta korantada ee ka dhalatay barta P waa:

E = E_B - E_A = (4,5 – 0,9) x 10⁹ = 3,6x10⁹ N / C

Jihada goobta korontada waxay u socotaa dhanka bidix ama dhanka E._B.

Jawaabta saxda ah waa C.

12. Laba dallacaad koronto midkiiba wuxuu leeyahay dallac Q₁ = -40 µC iyo Q₂ = +5 µC waxay ku taal booska sida ku cad sawirka (k = 9 x 10⁹ Nm².C^-2 iyo 1 µC = 10^-6 C), xoogga goobta korantada ee barta P waa…

A. 2,25 x 10⁶ NC^-1

B. 2,45 x 10⁶ NC^-1

C. 5,25 x 10⁶ NC^-1

D. 6,75 x 10⁶ NC^-1

E. 9,00 x 10⁶ NC^-1

Dood

Waa la ogyahay in :

Kharashka q₁ = -40 µC = -40 x 10^-6 C

Kharashka q₂ = +5 µC = +5 x 10^-6 C

Masaafada u dhaxaysa khidmadaha q₁ iyo dhibic P (r)₁) = 40 cm = 0,4 m = 4 x 10^-1 m

Masaafada u dhaxaysa khidmadaha q₂ iyo dhibic P (r)₂) = 10 cm = 0,1 = 1 x 10^-1 m

k = 9 x 10 ⁹ N m ² C ^-2

La weydiiyay Xoogga goobta korontada ee barta P

Jawaab :

Xoogga goobta korontada 1

E ₁ = kq ₁ / r ₁ ²

E ₁ = (9 x 10 ⁹ )(40 x 10 ^-6 ) / (4 x 10 ^-1 ) ²

E ₁ = (360 x 10 ³ ) / (16 x 10 ^-2 )

E ₁ = 22,5 x 10 ⁵ N/C

Xoogga goobta korontada 2

E ₂ = kq ₂ / r ₂ ²

E ₂ = (9 x 10 ⁹ )(5 x 10 ^-6 ) / (1 x 10 ^-1 ) ²

E ₂ = (45 x 10 ³ ) / 1 x 10 ^-2

E ₂ = 45 x 10 ⁵ N/C

Xoogga garoonka korantada ee ka dhashay

Xoogga goobta korantada ee ka dhalatay barta P waa:

E = E₂ - E₁ = (45 – 22,5) x 10⁵ = 22,5x10⁵ N / C

E = 2,25 x 10 ⁶ N/C

Jihada goobta korontadu waxay u jirtaa dhanka midig ama dhanka E.₂.

Jawaabta saxda ah waa A.

13. Sawirka dacwadda soo socda, kaas oo muujinaya khadadka xoogga ee laba dacwadood oo isku dhow ayaa...

Dood

Xariiqyada goobta korontada, ama khadadka xoogga, waxaa laga soo qaataa dallac togan ilaa dallac taban. Haddii dallac togan iyo mid taban la isku soo dhaweeyo, xarriiqyada xoogga waxay u muuqdaan sida jawaabta A.

Jawaabta saxda ah waa A.

8. Laba dallacaad koronto ayaa la isugu soo dhawaaday xariiq isku xiran, taasoo keentay khadadka goobta korontada. Sawirka saxda ah waa…

Dood

Jawaabta saxda ah waa D.

9. Khadadka saxda ah ee xoogga u dhexeeya laba dacwadood waa…

Dood

Jawaabta saxda ah waa D.

14. Bal eeg sawirka soo socda ee laba dhibcood oo la isku dayay!

Xaggee bay ku taal barta P si xoogga goobta korantada ee barta P uu ula mid noqdo eber?

(k = 9.10⁹ Nm².C^-2, 1 µC = 10^-6 C)

A. 1 cm dhanka midig ee q₁

B. 1 cm dhanka midig ee q₂

C. ½ cm dhanka midig ee q₂

D. ½ cm dhanka bidix ee q₁

E. ½ cm dhanka midig ee q₁

Dood

Waa la ogyahay in:

Kharash 1 (q₁) = -9 µC = -9.10^-6 Coulomb

Kharash 2 (q₂) = 1 µC = 1.10^-6 Coulomb

Masaafada u dhaxaysa q₁ iyo q₂ (r₁₂) = 1cm

k = 9.10 ⁹ Nm ² .C ^-2

La weydiiyay: Xaggee bay ku taal barta P si xoogga goobta korantada ee barta P uu ula mid noqdo eber?

Jawaab:

E₁ = xoogga goobta korantada ee uu dhaliyo q₁ barta P

Jihada E₁ dhanka q₁ sababtoo ah q₁ calaamad taban

E₂ = xoogga goobta korantada ee uu dhaliyo q₂ barta P

Jihada E₂ ka fogow q₂ sababtoo ah q₂ calaamad togan

r₁ = masaafada u dhaxaysa P iyo q₁ = x + 1

r₂ = masaafada u dhaxaysa P iyo q₂ =x

Xoogga goobta korantada ee barta P waxay la mid tahay eber:

Isticmaal qaacidada ABC:

Masaafada u dhaxaysa P iyo q₂ = x = 0,5 cm.

Barta P waa 0,5 cm dhanka midig ee q₂ ama 0,25 cm dhanka bidix ee q₁.

Jawaabta saxda ah waa C.

15 PFiiro gaar ah u yeelo labada dacwadood ee ku yaal meel fog oo hoose!

Haddii xoogga goobta korantada ee barta P uu yahay k Q/x², markaa qiimaha x waa….

A. 1/3 a

B. 2/3 a

C. a

D. 3/2 a

E. 2a

Dood

Waa la ogyahay in:

EP = k Q / _x ²

La weydiiyay: qiimaha x

Jawaab:

Isticmaal qaacidada ABC:

Jawaabta saxda ah waa A.

16. Su'aalaha Imtixaanka Qaranka ee Fiisigiska SMA/MA U-ZC-2013/2014 No. 27

Bal eeg sawirka soo socda ee laba dhibcood oo la isku dayay!

Xaggee bay ku taal barta P si xoogga goobta korantada ee barta P uu ula mid noqdo eber?
(k = 9.10⁹ Nm².C^-2, 1 µC = 10^-6 C)

1. 1 cm dhanka midig ee q₁
2. 1 cm dhanka midig ee q₂
3. ½ cm dhanka midig ee q₂
4. ½ cm dhanka bidix ee q₁
5. ½ cm dhanka midig ee q₁

Dood
Waa la ogyahay in:
Kharash 1 (q₁) = -9 µC = -9.10^-6 Coulomb
Kharash 2 (q₂) = 1 µC = 1.10^-6 Coulomb
Masaafada u dhaxaysa q₁ iyo q₂ (r₁₂) = 1cm
k = 9.10⁹ Nm².C^-2
La weydiiyay: Xaggee bay ku taal barta P si xoogga goobta korantada ee barta P uu ula mid noqdo eber?
Jawaab:

E₁ = xoogga goobta korantada ee uu dhaliyo q₁ barta P
Jihada E₁ dhanka q₁ sababtoo ah q₁ calaamad taban
E₂ = xoogga goobta korantada ee uu dhaliyo q₂ barta P
Jihada E₂ ka fogow q₂ sababtoo ah q₂ calaamad togan
r₁ = masaafada u dhaxaysa P iyo q₁ = x + 1
r₂ = masaafada u dhaxaysa P iyo q₂ =x

Xoogga goobta korontada 1:
Xoogga goobta korontada 2:

Xoogga goobta korantada ee barta P waxay la mid tahay eber:
a = 8, b = -2, c = -1
Isticmaal qaacidada ABC:

Masaafada u dhaxaysa P iyo q₂ = x = 0,5 cm.
Barta P waa 0,5 cm dhanka midig ee q₂ ama 0,25 cm dhanka bidix ee q₁.

Jawaabta saxda ah waa C.

17. Su'aalaha Imtixaanka Qaranka ee Fiisigiska SMA/MA U-ZC-2013/2014 No. 27

Ka fiirso laba kharash oo ku yaal meel fog oo hoos ku yaal!
Haddii xoogga goobta korantada ee barta P uu yahay k Q/x², markaa qiimaha x waa….

1. 1/3 y
2. 2/3 y
3. a
4. 3/2 y
5. 2a

Dood
Waa la ogyahay in:
E_P = k Q / x²
La weydiiyay: qiimaha x
Jawaab:
E₁ = xoogga goobta korantada ee barta P iyadoo loo eegayo dallacaadda -Q
r₁ = masaafada u dhaxaysa kharashka –Q iyo barta P = x
E₂ = xoogga goobta korantada ee barta P iyadoo la dallacayo +32Q
r₂ = masaafada u dhaxaysa kharashka +32Q iyo dhibicda P = a + x

Isticmaal qaacidada ABC:

Jawaabta saxda ah waa A.