Foiaina o faʻafitauli i vectors - fuafua vaega vectors
1. O le malosi e 20 Newton e faia ai se tulimanu e 30 o ma le x-axis. Saili vaega x ma le y o le malosi.
fofo
F x = F cos 30 o = (20)(cos 30 o ) = (20)(0.5 √ 3 ) = 10 √ 3 Newtons
F y = F agasala 30 o = (20)(agasala 30 o ) = (20)(0.5) = 10 Newtons
2. F 1 = 20 E faia e Newton se tulimanu e 30 o ma le y axis ma le F 2 = 30 E faia e Newton se tulimanu e 60 o ma le -x axis. Saili vaega x ma le y o le F 1 ma le F 2.
fofo
F 1x = F 1 cos 60 o = (20)(cos 60 o ) = (20)(0.5) = -10 Newtons (leaga auā e tutusa lona itu ma le -x axis)
F 2x = F 2 cos 60 o = (30)(cos 60 o ) = (30)(0.5) = -15 Newtons (leaga auā e tutusa lona itu ma le -x axis)
F1y =F1 agasala 60o = (20)(sin 60o) = (20)(0.5√3) = 10√3 Newton (lelei auā e tutusa lona itu ma le y axis)
F2y =F2 agasala 60o = (30)(sin 60o) = (30)(0.5√3) = -15√3 Newton (leaga ona e tutusa lona itu ma le -y axis)
3. F 1 = 2 N, F 2 = 4 N, F 3 = 6 N. Saili vaega uma e lua o le x ma le y o le F 1 , F 2 ma le F 3!
fofo
F 1x = F 1 cos 60 o = (2)(cos 60 o ) = (2)(0.5) = 1 Newtons (lelei auā e tutusa lona itu ma le x axis)
F2x =F2 cos 30o = (4)(cos 30o) = (4)(0.5√3) = -2√3 Newton (leaga ona e tutusa lona itu ma le -x axis)
F 3x = F 3 cos 60 o = (6)(cos 60 o ) = (6)(0.5) = 3 Newtons (lelei auā e tutusa lona itu ma le x axis)
F1y =F1 agasala 60o = (2)(sin 60o) = (2)(0.5√3) = √3 Newton (lelei auā e tutusa lona itu ma le y axis)
F 2 y = F 2 sin 3 0 o = (4)(sin 30 o ) = (4)(0.5) = 2 Newtons (lelei auā e tutusa lona itu ma le y axis)
F3y =F3 agasala 60o = (6)(sin 60o) = (6)(0.5√3) = -3√3 Newton (leaga ona e tutusa lona itu ma le -y axis)
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