 # Properties of image formed by diverging lens

Article about Properties of image formed by diverging lens

The object distance is smaller than the focal length of the concave lens (do > f)

Based on the calculation of the image formation by the concave lens, it can be concluded that if the object distance (do) is smaller than the focal length (f), then the image properties are:

– Virtual means the beam of light does not pass through the image

– Upright

– The farther the object from the concave lens, the smaller the image size

– The farther the object from the concave lens, the farther the image from the concave lens

The object distance is greater than the focal length of the concave lens (do > f)

Based on the calculation of the image formation by the concave lens, can conclude that if the object distance (do) is greater than the focal length (f) then the image properties are:

– Virtual means the beam of light does not pass through the image

– Upright

– The farther the object from the concave lens, the smaller the image size

– The farther the object from the concave lens, the farther the image from the concave lens

The object distance is equal to the focal length of the concave lens (do = f)

Based on the calculation of the image formation of the concave lens, can conclude that if the object distance (do) equals the focal length (f) of the concave lens then the image properties are:

– Virtual means the beam of light does not pass through the image

– Upright

– Minimized (the image size ½ times the object size)

– The image distance is smaller than the object distance (the image distance ½ times smaller than the object distance)

1. Question: What type of image is formed by a diverging lens? Answer: A diverging lens always forms a virtual, upright, and reduced image.
2. Question: How does the position of the object affect the size of the image formed by a diverging lens? Answer: Regardless of the object’s position, a diverging lens will always form a reduced image.
3. Question: Where is the image formed by a diverging lens located with respect to the lens? Answer: The image formed by a diverging lens is located on the same side as the object, within the focal length of the lens.
4. Question: How does the focal length of a diverging lens influence the position and size of the image? Answer: The focal length of a diverging lens doesn’t change the fact that the image is virtual, upright, and reduced, but a lens with a shorter focal length will produce a smaller image closer to the lens, compared to a lens with a longer focal length.
5. Question: Can a diverging lens ever produce a real image? Answer: No, a diverging lens cannot produce a real image. It always forms a virtual image.
6. Question: How does changing the object distance affect the position of the image formed by a diverging lens? Answer: As the object moves further away from the lens, the image formed by a diverging lens also moves further away from the lens, but stays within the focal length.
7. Question: If an object is placed at the focus of a diverging lens, where will the image be located? Answer: For a diverging lens, the image will still be formed on the same side as the object and will be virtual, upright, and diminished. The concept of placing an object at the focus doesn’t apply in the same way it does for converging lenses.
8. Question: Can a diverging lens form an inverted image? Answer: No, a diverging lens always forms an upright (right-side-up) image.
9. Question: Does the material of the lens (glass, plastic, etc.) influence the properties of the image formed by a diverging lens? Answer: The material of the lens can affect the focal length due to different refractive indices, but it won’t change the fundamental properties of the image formed by a diverging lens. The image will remain virtual, upright, and reduced.
10. Question: If a diverging lens has a negative focal length, how does this affect the formation and properties of the image? Answer: The negative focal length of a diverging lens indicates the direction of light bending, but it doesn’t alter the properties of the image. The image will still be virtual, upright, and reduced.