4 Latent heat Heat of fusion Heat of vaporization – Problems and Solutions
1. Calculate the amount of kutentha added to 1 gram gold to change phase from solid to liquid. The heat of fusion for gold is 64.5 x 103 J/kg.
Zodziwika:
Misa (m) = 1 gram = 1 x 10-3 kg
Heat of fusion (LF) = 64.5 x 103 J/kg
Akufuna: Heat (Q)
Yankho:
Q = m LF
Q = (1 x 10)-3 kg)(64.5 x 103 J/kg)
Q = 64.5 Joules
2. Calculate the amount of heat released by 1 gram mercury to change phase from liquid to solid. Heat of fusion for mercury is 11.8 x 103 J/kg.
Zodziwika:
Mass (m) = 1 gram = 1 x 10-3 kg
Heat of fusion (LF) = 11.8 x 103 J/kg
Akufuna: Heat (Q)
Yankho:
Q = m LF
Q = (1 x 10)-3 kg)(11.8 x 103 J/kg)
Q = 11.8 Joules
3. Determine the amount of heat absorbed by 1 kg water to change phase from liquid to vapor (steam). Heat of vaporization for water = 2256 x 103 J/kg
Zodziwika:
Kulemera (m) = 1 kg
Heat of vaporization (LV) = 2256 × 103 J/kg
Akufuna: Heat (Q)
Yankho:
Q = m LV
Q = (1 kg)(2256 × 103 J/kg)
Q = 2256 x 103 Joule
4. Determine the amount of heat released by nitrogen to change phase from vapor to liquid. Heat of vaporization for nitrogen = 200 × 103 J/kg
Zodziwika:
Mass (m) = 1 gram = 1 x 10-3 kg
Heat of vaporization (LV) = 200 × 103 J/kg
Zodziwika: Heat (Q)
Yankho:
Q = m LV
Q = (1 x 10)-3 kg)(200 × 103 J/kg)
Q = 200 Joules
- Kusintha miyeso ya kutentha
- Kukula kwa mzere
- Kukula kwa dera
- Kukula kwa voliyumu
- kutentha
- Kutentha kofanana ndi makina
- Kutentha ndi mphamvu ya kutentha yeniyeni
- Kutentha kobisika, kutentha kwa fusion, kutentha kwa nthunzi
- Kusunga mphamvu potumiza kutentha