Konverżjoni ta' unitajiet – problemi u soluzzjonijiet

Problemi u soluzzjonijiet dwar il-Konverżjoni tal-unitajiet – problemi u soluzzjonijiet

1. Nofs a litru ta' ħalib frisk imħallat maz-zalza tal-pudina, allura x'inhu l-volum ta' ħalib li għandu jitqiegħed fiz-zalza tal-pudina...

A. 5000 ml

B. 500 cc

Ċ. 50 dm³

D. 5-il metru³

Magħruf:

Volume of milk = 0.5 liter

Wanted : 0.5 liter = ….. ml = ….. cm³ (cc) = ….. dm³ = ….. m³

Soluzzjoni:

1 liter = 1000 milliliter (1000 ml)

1 litru = 0.001 m³ = 1 dm³ = 1000 ċm³ (1000 cc)

0.5 liter = (0.5)(1000 ml) = 500 ml

0.5 dm³ = (0.5)(1000 cc) = 500 cc

0.5 litru = 0.5 dm³ = 0.0005m³

It-tweġiba t-tajba hija B.

2. If into 100 milliliters of liquid milk added 250 cc of water then how many mixtures are produced.

A. 12.5 dm³

B. 1.25 dm³

Ċ. 3.5 dm³

D. 0.35 dm³

Magħruf:

Volume of milk = 100 ml

Volume of water = 250 cc = 250 cm³

Wanted : 100 ml + 250 cc = ….. dm³

Soluzzjoni:

ml = millilitru

cc = cm³ = ċentimetru kubu

dm³ = kubu danmetru

1 dm³ = 1 liter = 1000 milliliters so that 100 milliliters = 100/1000 liters = 1/10 liters = 0.1 liter = 0.1 dm³

1 dm³ = 1000 ċm³ so that 250 cm³ = 250/1000 dm³ = 1/4 dm³ = 0.25 dm³

100 ml + 250 cm³ = 0.1 dm³ + 0.25 dm³ = 0.35 dm³

It-tweġiba t-tajba hija D.

3. A classroom whose length is 10 m and its width is 8 m, using ceramic as its floor. The size of the ceramic is 20 cm x 20 cm. The amount of ceramics on the floor in the room is ….

A. 20

B. 200

C. 2000

D. 20000

Magħruf:

The size of a room :

Tul = 10 metru

Wisa' = 8-il metru

Area of a room = 10 m x 8 m = 80 m²

The size of a ceramic :

Tul = 20 ċm

Wisa ' = 20 ċm

Area of a ceramic = 20 cm x 20 cm = 400 cm²

Wanted : The number of ceramic used as the floor

Soluzzjoni:

1 m = 100 ċm

1 m² = 10,000 ċm²

So 80 m² = 80 x 10,000 ċm² = 800,000 ċm²

Number of ceramics = area of a room / area of a ceramic

Number of ceramics = 800,000 cm² / 400 ċm²

Number of ceramics = 2000

It-tweġiba t-tajba hija C.

4. Every second as much as 4 cc of water dripped from a aquarium fis a 5 liters container. The container is fully filled during ….. seconds.

A. 125 seconds

B. 200 seconds

C. 1250 seconds

D. 2000 seconds

Magħruf:

1 litru = 1 dm³ = 1000 ċm³

Volume of water = 4 cc = 4 cm³

Volume of container = 5 liters = 5 dm³ = 5 x 1000 ċm³ = 5000 ċm³

Mfittxija: Time interval the container full filled with water

Soluzzjoni:

5000 ċm³ / 4 ċm³ = 1250 sekondi

It-tweġiba t-tajba hija C.

5. Mother bought drinking water 2 gallons (1 gallon = 19 liters) with price $2. If the volume of kikkra ta 'ilma is 200 ml, then jiddeterminaw il-prezz ta ' kikkra jew ilma.

Magħruf:

1 gallun = 19 litru

2 gallon = 2 x 19 liters = 38 liters

1 liters = 1000 milliliters

38 liters = 38 x 1000 milliliters = 38,000 milliliters

1 glass of water = 200 milliliter

Meħtieġ: Price of a cup of water

Soluzzjoni:

2 gallon of water = 38 liters = 38,000 milliliters

1 cup of water = 200 milliliters

38,000 ml / 200 ml = 190

In 2 gallon of water there are 190 cup of water.

Price of 2 gallon of water = $2

Price of 1 cup of water = $2 / 190 = $0.01