Artikel iwwer d'Widerstänn an der Serie
Wann d'Widerstänn wéi an der Figur gewisen ugeschloss sinn, sinn d'Widerstänn a Serie ubruecht. De Widderstand oder den elektresche Widderstand a Fro kann a Form vu Widderstandskomponenten, Luuchten oder engem aneren elektresche Widderstand sinn.
Déi elektresch Ladung beweegt sech duerch de Widderstand 1 (R1) = an elektresch Ladung beweegt sech duerch de Widderstand 2 (R2) = déi elektresch Ladung beweegt sech duerch de Widderstand 3 (R3). Elektresche Stroum (I) ass eng elektresch Ladung, déi während engem bestëmmten Zäitintervall fléisst (I = Q / t), dofir den elektresche Stroum duerch de Widderstand 1 (I1) = elektresche Stroum duerch de Widderstand 2 (I2) = elektresche Stroum duerch de Widderstand 3 (I3Mathematesch gesinn ass den gesamten elektresche Stroum (I) = I1 = Ech2 = Ech3.
Conversely, the electric voltage (V) decreases when the electric charge moves through each resistor. Electricity voltage also called an electric potential difference, is an electric potential energy per unit of electric charge. Electricity voltage is reduced because electricity is used in each electrical resistance. So, the total electrical voltage (V) is equal to the amount of electricity in each resistor. Mathematically, the total electric voltage (V) = V1 + V.2 + V.3. V = I R so the equation of the electric voltage is V = I R1 + I R2 + I R3. The electric current flowing on each resistor is equal so that this equation changes to V = I (R1 + R2 + R3).
Based on the above equation, it can be concluded that the total electrical resistance (R) or the equivalent resistance of the electrical resistance
which is connected in series is equal to the sum of each electrical resistance, mathematically R = R1 + R2 + R3. If there are only two resistors in series, the equivalent resistor (R) = R1 + R2. If there are four resistors in series, the equivalent resistor (R) = R1 + R2 + R3 + R4. Likewise, if there are five or more five resistors that are connected in series.
Sample problem 1:
If known, R1 = 2 Ω, R2 = 3 Ω an R3 = 4 Ω. All three resistors are connected in series. What is the value of the equivalent resistor? (Ω = ohm).
Léisung:
R=R1 + R2 + R3 = 2 + 3 + 4 = 9 Ω.
This result indicates that the equivalent resistance is greater than the value of the resistors connected in series.
Sample problem 2:
Two resistors R1 = 50 Ω and 50 Ω are connected in series and connected to a 12 Volt battery. Determine
(a) Den gläichwäertege Widderstand
(b) Elektresche Stroum duerch all Widderstand
Léisung:
(a) R = R1 + R2 = 50 Ω + 50 Ω = 100 Ω.
(b) I = V / R = 12 Volt / 100 Ω = 0.12 A
