Mgbasawanye olu - nsogbu na ngwọta

Ọ bụ naanị ihe siri ike ka a na-ahụ mmụba nke nha nha; ihe niile, ma ihe siri ike, mmiri mmiri, na gas, na-enweta mmụba nke nha ...

Mgbasawanye olu nke 1

Nkọwa: V o = Olu mbụ, V = Olu ikpeazụ, ΔV = V – V o = Mgbanwe olu, T o = Okpomọkụ mbụ, T = Okpomọkụ ikpeazụ, ΔT = T – T o = Mgbanwe okpomọkụ, β = ọnụọgụ nke mgbasawanye olu. Nkeji nke β = (C o ) -1

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Mgbasawanye olu nke 2

Mgbasawanye olu nke 3

Mgbasawanye olu nke 4

Usoro mgbasa olu dị n'elu na-emetụta naanị mgbe mgbanwe dị na olu ihe ndị ahụ (ma siri ike, mmiri mmiri, na gas) pere mpe karịa olu mbụ nke ihe ahụ. Ọ bụrụ na mgbanwe na olu ihe karịrị olu mbụ nke ihe ahụ, usoro mgbasa olu anaghị enye nsonaazụ ziri ezi. Ọtụtụ mgbe, mgbanwe na olu nke ihe siri ike na-enweta anaghị oke ibu. N'aka nke ọzọ, usoro mgbasa olu nke mmiri mmiri na gas buru ibu. Usoro mgbasa olu maka ihe gas dịkwa mfe ịgbanwe ma ọ bụrụ na okpomọkụ agbanwee. Ya mere, usoro dị n'elu na-eji naanị maka mgbasa nke ihe siri ike.

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1. N'okpomọkụ 30 o C, olu nke okirikiri aluminom bụ 30 cm 3. Ọnụọgụ nke mgbasawanye ahịrị bụ 24 x 10 -6 o C -1 . Ọ bụrụ na olu ikpeazụ bụ 30.5 cm 3 , kedu okpomọkụ ikpeazụ nke okirikiri aluminom?

A maara:

Ọnụọgụ nke mgbasawanye ahịrị ( α ) = 24 x 10 -6 o C -1

Ọnụọgụ nke mgbasawanye olu ( β ) = 3 α = 3 x 24 x 10 -6 o C -1 = 72 x 10 -6 o C -1

Okpomọkụ mbụ ( T 1 ) = 30 oC

Olu mbụ (V 1 ) = 30 cm 3

Olu ikpeazụ (V 2 ) = 30.5 cm 3

Mgbanwe olu ( Δ V) = 30.5 cm 3 – 30 cm 3 = 0.5 cm 3

Achọrọ: Okpomọkụ ikpeazụ ( T2 )

Ngwọta:

Δ V = β (V1 ) ( ΔT )

Δ V = β (V1 ) ( T2 – T1 )

0.5 cm3 = (72 x 10-6 oC-1)Ogologo (30 cm)3)(T2 - 30oC)

0.5 = (2160 x 10 -6 ) (T 2 – 30 )

0.5 = (2.160 x 10 -3 ) (T 2 – 30 )

0.5 = (2.160 x 10 -3 ) (T 2 – 30 )

0.5 / (2.160 x 10 -3 ) = T 2 – 30

0.23 x 10 3 = T 2 – 30

0.23 x 1000 = T 2 – 30

230 = T 2 – 30

230 + 30 = T 2

T 2 = 260 o C

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2. Ọnụọgụ nke mgbasawanye linear nke okirikiri ígwè bụ 9 x 10 -6 o C -1 . Dayameta dị n'ime nke okirikiri ígwè ahụ na 20 o C bụ 2.2 cm. Ọ bụrụ na dayameta ikpeazụ bụ 2.8 cm, kedu ka okpomọkụ ikpeazụ ga-adị!

A maara:

Ọnụọgụ nke mgbasawanye ahịrị ( α ) = 9 x 10 -6 o C -1

Ọnụọgụ nke mgbasawanye olu ( β) = 3 α = 3 x 9 x 10 -6 o C -1 = 27 x 10 -6 o C -1

Okpomọkụ mbụ ( T 1 ) = 20 oC

Dayameta mbụ (D 1 ) = 2.2 cm

Dayameta ikpeazụ (D 2 ) = 2.8 cm

Mgbada mbụ (r 1 ) = D 1 / 2 = 2.2 cm 3 / 2 = 1.1 cm 3

Oke okirikiri ikpeazụ (r 2 ) = D 2 / 2 = 2.8 cm 3 / 2 = 1.4 cm 3

Mpịakọta mbụ (V 1 ) = 4/3 π r 1 3 = (4/3)(3.14)(1.1 cm) 3 = (4/3)(3.14)(1.331 cm 3 ) = 5.57 cm 3

Olu ikpeazụ (V 2 ) = 4/3 π r 2 3 = (4/3)(3.14)(1.4 cm) 3 = (4/3)(3.14)(2.744 cm 3 ) = 11.48 cm 3

Mgbanwe olu ( Δ V) = 11.48 cm 3 – 5.57 cm 3 = 5.91 cm 3

Achọrọ: Okpomọkụ ikpeazụ ( T2 )

Ngwọta:

Δ V = β (V1 ) ( ΔT )

5.91 cm3 = (27 x 10-6 oC-1)(5.57 cm3)(T2 - 20oC)

5.91 = (150.39 x 10 -6 ) (T 2 – 20)

5.91 / 150.39 x 10 -6 = T 2 – 20

0.039 x 10 6 = T 2 – 20

39 x 10 3 = T 2 – 20

39,000 = T 2 – 20

39,000 + 20 = T 2

T 2 = 39,020 o C

3. A 2000-cm3 aluminom akpa, juputara na mmiri na 0oC. Wee kpoo ọkụ ruo 90oC. Ọ bụrụ na ọnụọgụ nke mgbasawanye linear maka aluminom bụ 24 x 10-6 (oC)-1 na ọnụọgụ nke mgbasawanye olu maka mmiri bụ 6.3 x 10-4 (oC)-1, chọpụta oke mmiri a wụfuru.

A maara:

Olu mbụ nke akpa aluminom na mmiri (Vo ) = 2000 cm 3 = 2 x 10 3 cm 3

Okpomọkụ mbụ nke akpa aluminom na mmiri (T 1 ) = 0 oC

Okpomọkụ ikpeazụ nke akpa aluminom na mmiri (T2 ) = 90 oC

Ọnụọgụ nke mgbasawanye ahịrị maka aluminom (α) = 24 x 10 -6 ( oC ) -1

Ọnụọgụ nke mgbasawanye olu maka aluminom (γ) = 3α = 3 (24 x 10 -6 ( oC ) -1 ) = 72 x 10 -6 o C -1

Ọnụọgụ nke mgbasawanye olu maka mmiri (γ) = 6.3 x 10 -4 ( oC ) -1

Achọtara: Oke mmiri a wụfuru

Ngwọta:

Usoro nke mgbasawanye olu:

V = V o + γ V o ΔT

V – V o = γ V o ΔT

ΔV = γ V o ΔT

V = olu ikpeazụ, V o = olu mbụ, ΔV = mgbanwe olu, γ = ọnụọgụ nke mgbasawanye olu, ΔT = mgbanwe okpomọkụ

Gbakọọ mgbanwe dị na olu nke akpa aluminom:

ΔV = γ V o ΔT = (72 x 10 -6 )(2 x 10 3 )(90) = 12960 x 10 -3 = 12.960 cm 3

Gbakọọ mgbanwe dị na olu mmiri ahụ:

ΔV = γ V o ΔT = (6. 3 x 10 -4 )(2 x 10 3 )(90) = 1134 x 10 -1 = 113.4 cm 3

Mgbanwe dị na olu mmiri ahụ karịrị nke aluminom nke mere na ụfọdụ mmiri gbapụrụ.

Gbakọọ olu mmiri a wụfuru:

113.4 cm 3 – 12.960 cm 3 = 100.44 cm 3

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  1. Ịgbanwe nha okpomọkụ
  2. Mgbasawanye ahịrị
  3. Mgbasawanye mpaghara
  4. Mgbasawanye olu
  5. okpomọkụ
  6. Ihe nhata igwe nke okpomọkụ
  7. Ike okpomọkụ na okpomọkụ kpọmkwem
  8. Okpomọkụ zoro ezo, okpomọkụ nke njikọta, okpomọkụ nke vaporization
  9. Nchekwa ike maka nnyefe okpomọkụ

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