1. Na 20 o C, ogologo mpempe akwụkwọ ígwè bụ 50 cm, obosara ya bụkwa 30 cm. Ọ bụrụ na ọnụọgụgụ nke mgbasawanye ahịrị maka ígwè bụ 10 -5 o C -1 , chọpụta mgbanwe na mpaghara ahụ na mpaghara ikpeazụ na 60 o C.
A maara:
Okpomọkụ mbụ ( T 1 ) = 20 oC
Okpomọkụ ikpeazụ (T2 ) = 60 oC
Mgbanwe na okpomọkụ ( ΔT ) = 60 o C – 20 o C = 40 o C
Mpaghara mbụ (A 1 ) = ogologo x obosara = 50 cm x 30 cm = 1500 cm 2
Ọnụọgụ nke mgbasawanye ahịrị maka ígwè ( α) = 10 -5 o C -1
Ọnụọgụ nke mgbasawanye mpaghara maka ígwè ( β) = 2α = 2 x 10 -5 o C -1
Achọtara: Mgbanwe na mpaghara ( ΔA )
Ngwọta:
Mgbanwe na mpaghara ( ΔA ):
ΔA = βA 1 ΔT
ΔA = ( 2 x 10 -5 o C -1 )(1500 cm 2 )(40 o C)
ΔA = (80 x 10 -5 ) (1500 cm 2 )
ΔA = 1 20,000 x 10 -5 cm 2
ΔA = 1. 2 x 10 5 x 10 -5 cm 2
ΔA = 1.2 cm 2
Mpaghara ikpeazụ ( A 2 ):
A 2 = A 1 + ΔA
A 2 = 1500 cm 2 + 1. 2 cm 2
A 2 = 1501. 2 cm 2
[irp]
2. Na 30 o C, mpaghara mpempe akwụkwọ aluminom bụ 40 cm 2 na ọnụọgụ nke mgbasawanye ahịrị bụ 24 x 10 -6 / o C. Chọpụta okpomọkụ ikpeazụ ma ọ bụrụ na mpaghara ikpeazụ bụ 40.2 cm 2.
A maara:
Okpomọkụ mbụ (T 1 ) = 30 oC
Ọnụọgụ nke mgbasawanye ahịrị ( α) = 24 x 10 -6 o C -1
Ọnụọgụ nke mgbasawanye mpaghara ( β) = 2a = 2 x 24 x 10 -6 o C -1 = 48 x 10 -6 o C -1
Mpaghara mbụ (A 1 ) = 40 cm 2
Mpaghara ikpeazụ (A 2 ) = 40.2 cm 2
Mgbanwe dị na mpaghara ( ΔA) = 40.2 cm 2 – 40 cm 2 = 0.2 cm 2
Achọrọ: Chọpụta okpomọkụ ikpeazụ ( T2 )
Ngwọta:
Usoro mgbanwe na mpaghara ( ΔA) :
ΔA = βA 1 Δ T
Okpomọkụ ikpeazụ (T2 ) :
ΔA = βA 1 ( T2 – T1 )
0.2 cm2 = (48 x) 10-6 oC-1)(40 cm)2)(T2 - 30oC)
0.2 = (1920 x 10 -6 ) (T 2 – 30 )
0.2 = (1.920 x 10 -3 ) (T 2 – 30)
0.2 = (2 x 10 -3 ) (T 2 – 30)
0.2 / (2 x 10 -3 ) = T 2 – 30
0.1 x 10 3 = T 2 – 30
1 x 10 2 = T 2 – 30
100 = T 2 – 30
100 + 30 = T 2
T 2 = 130
Okpomọkụ ikpeazụ = 130 o C
[irp]
3. radius nke mgbanaka dị na 20 o C bụ 20 cm. Ọ bụrụ na radius ikpeazụ dị na 100 o C bụ 20.5 cm, chọpụta ọnụọgụ nke mgbasawanye mpaghara na ọnụọgụ nke mgbasawanye ahịrị…
A maara:
Okpomọkụ mbụ (T 1 ) = 30 oC
Okpomọkụ ikpeazụ (T2 ) = 100 oC
Mgbanwe na okpomọkụ ( ΔT ) = 100 o C – 30 o C = 70 o C
Mgbada mbụ (r 1 ) = 20 cm
Mgbada ikpeazụ (r2 ) = 20.5 cm
Achọrọ: Ọnụọgụ nke mgbasawanye mpaghara ( β )
Ngwọta:
Mpaghara mbụ (A 1 ) = π r 1 2 = (3.14)(20 cm) 2 = (3.14)(400 cm 2 ) = 1256 cm 2
Mpaghara ikpeazụ (A 2 ) = π r 2 2 = (3.14)(20.5 cm) 2 = (3.14)(420.25 cm 2 ) = 1319.585 cm 2
Mgbanwe dị na mpaghara ( ΔA) = 1319.585 cm 2 – 1256 cm 2 = 63.585 cm 2
Usoro mgbanwe na mpaghara ( ΔA) :
ΔA = βA 1 ΔT
Ọnụọgụ nke mgbasawanye mpaghara:
ΔA = βA 1 ΔT
63.585 cm 2 = b (1 256 cm 2 )(70 o C)
63.585 = b ( 87,920 o C)
β = 63.585 / 87,920 o C
β = 0.00072 / o C
β = 7.2 x 1 0 -4 / o C
β = 7.2 x 1 0 -4 o C -1
Ọnụọgụ nke mgbasawanye ahịrị ( α ):
β = 2 α
α = β / 2
α = (7.2 x 1 0 -4 ) / 2
α = 3.6 x 1 0 -4 o C -1
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- Ịgbanwe nha okpomọkụ
- Mgbasawanye ahịrị
- Mgbasawanye mpaghara
- Mgbasawanye olu
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- Ihe nhata igwe nke okpomọkụ
- Ike okpomọkụ na okpomọkụ kpọmkwem
- Okpomọkụ zoro ezo, okpomọkụ nke njikọta, okpomọkụ nke vaporization
- Nchekwa ike maka nnyefe okpomọkụ
