Ihe atụ nke ajụjụ gbasara mgbasawanye mpaghara

Ihe atụ atọ nke ajụjụ gbasara mgbasawanye mpaghara

1. Mpempe akwụkwọ ígwè dị n'okpomọkụ nke 20 oC nwere ogologo 50 cm na obosara 30 cm. Ọ bụrụ na ọnụọgụgụ nke mgbasawanye ígwè dị larịị bụ 10 -5 o C -1 mgbe ahụ mmụba na mpaghara na mkpokọta mpaghara na okpomọkụ nke 60 o C bụ….

Mkparịta ụka

A maara na:

Okpomọkụ mbụ (T 1 ) = 20 oC

Okpomọkụ ikpeazụ (T2 ) = 60 oC

Mgbanwe okpomọkụ (Δ T) = 60 o C – 20 o C = 40 o C

Mpaghara mbụ (A 1 ) = Ogologo x obosara = 50 cm x 30 cm = 1500 cm 2

Ọnụọgụ nke mgbasawanye ahịrị nke ígwè (α ) = 10 -5 o C -1

Ọnụọgụ nke mgbasawanye nke ígwè (β ) = 2a = 2 x 10 -5 o C -1

Ajụjụ: Mmụba na mpaghara (Δ A )

Azịza:

Mmụba na mpaghara (Δ A ):

ΔA = βA 1Δ T

ΔA = ( 2 x 10 -5 o C -1 )(1500 cm 2 )(40 o C)

ΔA = (80 x 10 -5 ) (1500 cm 2 )

ΔA = 1 20.000 x 10 -5 cm 2

ΔA = 1.2 x 10 5 x 10 -5 cm 2

ΔA = 1.2 cm 2

Mpaghara niile ( A2 ) :

A 2 = A 1 + Δ A

A 2 = 1500 cm 2 + 1.2 cm 2

A 2 = 1501 , 2 cm 2

2. Efere aluminom nwere oke mgbasa nke linear nke 24 x 10 -6 / o C nwere mpaghara nke 40 cm 2 na okpomọkụ nke 30 o C. Chọpụta okpomọkụ ikpeazụ ma ọ bụrụ na mpaghara nke efere aluminom abawanye ruo 40,2 cm 2.

Mkparịta ụka

A maara na:

Okpomọkụ mbụ (T 1 ) = 30 oC

Ọnụọgụ nke mgbasawanye ahịrị nke aluminom (α ) = 24 x 10 -6 o C -1

Ọnụọgụ nke mgbasawanye mpaghara nke aluminom (β ) = 2α = 2 x 24 x 10 -6 o C -1 = 48 x 10 -6 o C -1

Mpaghara mbụ (A 1 ) = 40 cm 2

Mpaghara ikpeazụ (A 2 ) = 40,2 cm 2

Mgbanwe na mpaghara (Δ A) = 40,2 cm 2 – 40 cm 2 = 0,2 cm 2

Ajụjụ: Chọpụta okpomọkụ ikpeazụ ( T2 )

Azịza:

Usoro maka mgbanwe na mpaghara (Δ A) :

ΔA = βA 1 Δ T

Okpomọkụ ikpeazụ (T2 ) :

ΔA = βA 1 ( T2 – T1 )

0,2 cm2 = (48 x) 10-6 oC-1)(40 cm)2)(T2 - 30oC)

0,2 = (1920 x 10 -6 ) (T 2 – 30 )

0,2 = (1,920 x 10 -3 ) (T 2 – 30)

0,2 = (2 x 10 -3 ) (T 2 – 30)

0,2 / (2 x 10 -3 ) = T 2 – 30

0,1 x 10 3 = T 2 – 30

1 x 10 2 = T 2 – 30

100 = T 2 – 30

100 + 30 = T 2

T 2 = 130

Okpomọkụ ikpeazụ = 130 oC

3. Ihe okirikiri dị na okpomọkụ nke 20 o C nwere radius nke 20 cm. Ọ bụrụ na okpomọkụ nke 100 o C, radius ahụ na-abawanye ruo 20,5 cm, mgbe ahụ, ọnụọgụ nke mgbasawanye ahịrị nke ihe ahụ bụ….

Mkparịta ụka

A maara na:

Okpomọkụ mbụ (T 1 ) = 30 oC

Okpomọkụ ikpeazụ (T2 ) = 100 oC

Mgbanwe okpomọkụ (Δ T) = 100 o C – 30 o C = 70 o C

Mgbada mbụ (r 1 ) = 20 cm

Oke njedebe (r 2 ) = 20,5 cm

Ajụjụ: Ọnụọgụ nke mgbasawanye mpaghara nke ihe ahụ ( b )

Azịza:

Mpaghara mbụ nke okirikiri ahụ (A 1 ) = π r 1 2 = (3,14)(20 cm) 2 = (3,14)(400 cm 2 ) = 1256 cm 2

Mpaghara ikpeazụ nke okirikiri ahụ (A 2 ) = π r 2 2 = (3,14)(20,5 cm) 2 = (3,14)(420,25 cm 2 ) = 1319,585 cm 2

Mmụba n'ógbè okirikiri (Δ A) = 1319,585 cm 2 – 1256 cm 2 = 63,585 cm 2

Usoro maka mgbanwe na mpaghara (Δ A) :

ΔA = βA 1 ΔT

Ọnụọgụ mgbasawanye mpaghara:

ΔA = βA 1 ΔT

63,585 cm 2 = β (1 256 cm 2 ) (70 o C)

63,585 = β ( 87920 o C)

β = 63,585 / 87920 o C

β = 0,00072 / o C

β = 7,2 x 1 0 -4 / o C

β = 7,2 x 1 0 -4 o C -1

Ọnụọgụ nke mgbasawanye ahịrị (α ):

β = 2 α

α = β / 2

α = (7,2 x 1 0 -4 ) / 2

α = 3,6 x 1 0 -4 o C -1

 

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