Ihe atụ ise nke nsogbu okpomọkụ
1. Tin nke nwere ibu kilogram abụọ nwere okpomọkụ kpọmkwem nke 130 J.kg -1 C -1 . Oke okpomọkụ nke tin na-amịkọrọ iji bulie okpomọkụ ya site na 50 o C ruo 100 o C bụ….
Mkparịta ụka
A maara na:
Ibu (m) = 2 kg
Okpomọkụ kpọmkwem nke tin (c) = 130 J.kg -1 C -1
Mgbanwe okpomọkụ (Δ T) = 100 o C – 50 o C = 50 o C
Ajụjụ: Okpomọkụ (Q) nke tin na-amịkọrọ
Azịza:
Usoro okpomọkụ:
Q = mc Δ T
Nkọwa: Q = okpomọkụ, m = oke, c = okpomọkụ kpọmkwem, Δ T = mgbanwe na okpomọkụ
Okpomọkụ nke tin na-amịkọrọ:
Q = (2 kg)(130 J.kg -1 C -1 )(50 o C)
Q = (100)(130)
Q = 13000 Joule
Q = 1,3 x 10 Joule 4
2. Ọla kọpa nwere okpomọkụ kpọmkwem nke 390 J kg -1 o C -1 na-enwe mgbanwe okpomọkụ nke 40 o C. Ọ bụrụ na okpomọkụ nke ọla kọpa ahụ na-amịkọrọ n'oge mgbanwe okpomọkụ bụ kalori 200, mgbe ahụ oke nke ọla kọpa ahụ bụ...
Mkparịta ụka
A maara na:
Okpomọkụ kpọmkwem nke ọla kọpa (c) = 390 J kg -1 o C -1
Mgbanwe okpomọkụ (Δ T) = 40 o C
Okpomọkụ (Q) = Joules 40
Ajụjụ: Oke (m) nke ọla kọpa
Azịza:
Q = mc Δ T
40 = (m)( 390 )(40 o C)
40 = (m)(390 )(40)
40 = (m)( 390 )(4)
40 = (m)( 1560 )
m = 40/1560
m = 0,026 n'arọ
Ọnụ ọgụgụ ọla kọpa dị gram 26.
3. Mmiri nke nwere oke gram 20 na okpomọkụ kpọmkwem nke 1 cal -1 o C -1 na mbụ nwere okpomọkụ nke 30 o C. Chọpụta mgbanwe na okpomọkụ mmiri ma ọ bụrụ na oke okpomọkụ mmiri ahụ na-amịkọrọ bụ kalori 300!
Mkparịta ụka
A maara na:
Ibu (m) = 20 g
Okpomọkụ mbụ (T 1 ) = 30 oC
Okpomọkụ mmiri kpọmkwem (c) = 1 kalori gr -1 o C -1
Okpomọkụ (Q) = 300 kalori
Ajụrụ: Mgbanwe na okpomọkụ mmiri
Azịza:
Q = mc Δ T
Q = mc (T 2 – T 1 )
300 cal = (20 gr)( 1 cal gr -1 o C -1 )(T 2 – 30 o C)
300 = (20)(1)(T 2 – 30)
300 = 20 (T 2 – 30)
300 = 20 T 2 – 600
300 + 600 = 20 T 2
900 = 20 T 2
T 2 = 900 / 20
T 2 = 45 o C
Mgbanwe okpomọkụ:
Δ T = 45 o C – 30 o C
ΔT = 15 oC
4. Oke okpomọkụ achọrọ iji belata okpomọkụ nke kilogram 4 nke mmiri mmiri nke nwere okpomọkụ kpọmkwem nke 500 J/kg K site na 40 oC na-aghọ 20 oC bụ…
A. 20 kJ
B. 30 kJ
C. 40 kJ
D. 50 kJ
E. 60 kJ
Mkparịta ụka:
A maara :
Ibu (m) = 4 kg
Okpomọkụ kpọmkwem (c) = 500 J/kg K = 500 J/kg Co
Mgbanwe okpomọkụ (delta T) = 40 oC - 20 oC = 20 Co
A jụrụ :
Okpomọkụ (Q)
Jawab :
Usoro Okpomọkụ :
Q = (m)(c)(delta T)
Q = (4)(500)(20) = 40.000 Joules = 40 kJ
kJ = kilogram Joule
Azịza ziri ezi bụ C.
5. A na-eji okpomọkụ nke 30 kpoo ihe siri ike nke dị kilogram abụọ ọkụ.oC na-aghọ 100oC, chọrọ okpomọkụ 7 × 105 Joule. Okpomọkụ kpọmkwem nke ihe ahụ bụ…
A. 400 J/kg K
B. 500 J/kg K
C. 700 J/kg K
D. 1000 J/kg K
E. 5000 J/kg K
Mkparịta ụka:
A maara :
Ibu (m) = 2 kg
Okpomọkụ (Q) = 7 × 105 J = 700.000 J
Mgbanwe okpomọkụ (delta T) = 100 oC - 30 oC = 70 Co
A jụrụ :
Okpomọkụ kpọmkwem (c)?
Jawab :
c = Q / m T
c = 700.000 J / (2 kg)(70 C)o) = 700.000 J / 140 kg Co
c = 5000 J/kg Co
c = 5000 J/kg K
Azịza ziri ezi bụ E.
