3 kérdés a normálerő egyenletéről
1. Egy tömb tömege 5 kg. Ha g = 10 m/s2, határozza meg:
a) a blokk súlya
b) a normálerő, ha a tömböt sík felületre helyezik
c) a merőleges erő, ha a tömb egy 30 fokos szöget zár be a ferde síkono a vízszinteshez
Ismert:
A blokk tömege (m) = 5 kg
Nehézségi gyorsulás (g) = 10 m/s2
Wanted: w, N a síkon és N a lejtőn
Megoldás:
a) Beam weight
w = m g = 5 (10) = 50 Newton
b) The normal force if the block is in a flat plane
N = w = 50 Newton
c) The normal force if the block is on an inclined plane
N = wy = w cos θ = 50 (cos 30) = 50 (½ √3) = 25√3 Newton
2. A 120 gram eraser is pressed perpendicularly to the board with a force of 15 N. What is the normal force acting on the eraser?
Ismert:
Mass (m) = 120 grams = 0.12 kg
Erő (F) = 15 Newton
Wanted: Normális erő
Megoldás:
Normal force = thrust = 15 Newton
3. Bottled drinking water that is still in the box is pulled with a force of F = 200 N which forms an angle of 37o with the horizontal. Sin 37o = 0.6. The mass of the cardboard and its contents is 20 kg. If the coefficient of static friction on the floor is 0.5 and the coefficient of kinetic friction on the floor is 0.2, determine the normal force acting on the cardboard.
Ismert:
Pull force (F) = 200 N
Sin 37 = 0,6
Fy = F sin 37 = (200)(0,6) = 120 N
Cardboard mass (m) = 20 kg
The weight of the cardboard (w) = m g = (20)(10) = 200 N
Wanted: Normal force on cardboard (N)
Megoldás:
Calculate the normal force using the normal force formula:
N = w – Fy = 200 – 120 = 80 Newton