Angular momentum - Teeb meem thiab kev daws teeb meem

1. An object with the lub sij hawm ntawm inertia of 2 kg m2 rotates at 1 rad/s. Yuav ua li cas yog lub lub zog ntawm lub kaum sab xis ntawm tus khoom?

Paub:

Lub sijhawm ntawm inertia (Kuv) = 2 kg m2

Qhov ceev ntawm lub kaum sab xis (ω) = 1 rad/s

Xav tau: Angular zog (L)

Tshuaj:

Formula of angular momentum :

L = Kuv ω

L = tau lub zog ntawm lub kaum sab xis (kg/m²)2/s), I = lub sij hawm ntawm inertia (kg/m²)2), ω = qhov ceev ntawm lub kaum sab xis (rad/s)

The angular momentum :

L = Kuv ω = (2)(1) = 2 kg/m²2/s

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2. A 2-kg cylinder pulley with radius of 0.1 m rotates at a constant angular speed of 2 rad/s. What is the angular momentum of the pulley ?

Angular momentum – problems and solutions 1Paub:

Pawg of pulley (M) = 2 kg

Radius of pulley (r) = 0.1 m

Qhov ceev ntawm lub kaum sab xis (ω) = 2 rkev tshaj tawm

Xav tau: Angular zog

Tshuaj:

Formula of moment of inertia for solid cylinder :

I = 1/2 mr2

Kuv = lub sij hawm ntawm inertia (kg/m²)2), m = loj (kg), r = vojvoog (M)

Lub sijhawm ntawm inertia:

Kuv = 1/2 (2)(0.1)2 = (1)(0.01) = 0.01 kg m²2

The angular speed :

L = Kuv ω = (0.01)(2) = 0.02 kg/m²2/s

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3. A 2-kg uniform sphere with radius of 0.2 m rotates at 4 rad/s. What is the angular momentum of the ball.

Angular momentum – problems and solutions 2Paub:

Pawg ntawm lub pob (M) = 2 kg

Radius ntawm lub pob (r) = 0.2 m

Qhov ceev ntawm lub kaum sab xis (ω) = 4 rahnub/s

Xav tau: Angular zog

Tshuaj:

Formula of moment of inertia for uniform sphere :

I = (2/5) Yawg.2

I = moment of inertia (kg/m²)2), m = pawg (kg), r = vojvoog (M)

The moment of inertia for uniform sphere :

Kuv = (2/5)(2)(0.2)2 = (4/5)(0.04) = 0.032 kg m²2

The angular momentum of sphere :

L = I ω = (0.032)(4) = 0.128 kg/m²2/s

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4. A 1-kg particle rotates at a constant angular speed of 2 rad/s. What is the angular speed if the radius of circle is 10 cm.

Paub:

Pawg of object (M) = 1 kg

The radius of circle (r) = 10 cm = 10/100 = 0.1 m

Qhov ceev ntawm lub kaum sab xis (ω) = 2 rad/s

Xav tau: Angular zog

Tshuaj:

Formula of moment of inertia for particle :

I = Yawg.2 = (1)(0.1)2 = (1)(0.01) = 0.01 kg m²2

Angular momentum :

L = Kuv ω = (0.01)(2) = 0.02 kg m2/s

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