1. Nisa tsakanin magudanan ruwa guda biyu na raƙuman ruwa na saman ruwa mita 20 ne. Wani abu yana shawagi a saman ruwan don ya ji motsin girgiza. Idan lokacin tafiya girgiza ɗaya daƙiƙa 4 ne, to saurin raƙuman ruwa shine .... m/s
A. 20
B. 15
C. 10
D. 5
An sani:
Tsawon Raƙuman Ruwa (λ) = mita 20
Lokaci (T) = daƙiƙa 4
Ana so: Gudun raƙuman ruwa (v)
Magani:
Daidaiton saurin raƙuman ruwa:
v = λ / T = mita 20 / daƙiƙa 4 = mita 5 / daƙiƙa
Amsar da ta dace ita ce D.
2. Maki biyu na A da B suna kan igiyar kuma suna da nisan santimita 90 tsakanin juna. A kan igiyar, raƙuman ruwa masu ratsawa suna yaɗuwa , don haka wannan ma'anar A tana saman raƙuman ruwa, ma'anar B tana ƙasan raƙuman ruwa, kuma a tsakaninsu, akwai ramuka biyu da ramuka biyu. Idan lokacin raƙuman ruwa ya kai daƙiƙa 0.3, to yaduwar raƙuman ruwa tana…
A. 10.8 cm/s
B. 18.0 cm/s
C. 120.0 cm/s
D. 200.0 cm/s
An sani:
Nisa AB (l) = 90 cm
Lokacin raƙuman ruwa (T) = daƙiƙa 0.3
Yawan raƙuman ruwa (f) = 1/0.3 daƙiƙa
Ma'ana A tana kan ƙololuwar raƙuman ruwa, kuma ma'ana B tana kan ƙololuwar raƙuman ruwa.
Tsakanin maki A da B, akwai ƙofofi biyu da kuma ƙofofi biyu.
Ana so: Gudun raƙuman ruwa (v = f λ)
Magani:
Dangane da adadi, za a iya kammala cewa akwai tsawon tsayi 2.5. Nisa tsakanin tsawon tsayi (λ) = 90 cm / 2.5 = 36 cm
Gudun raƙuman ruwa:
v = f λ = (1 / 0.3) (36) = 36 / 0.3 = 120 cm/s.
Madaidaicin amsar ita ce C.
3. Jadawalin da ke ƙasa yana nuna canjin wurin da ke cikin wani matsakaici a matsayin aikin lokaci lokacin da raƙuman ruwa ke ratsawa ta cikin matsakaiciyar.
Idan tsawon tsayin igiyar mita 6 ne, to saurin yaduwar igiyar shine…
A. 3 m/s
B. 6 m/s
C. 8 m/s
D. 12 m/s
An sani:
Akwai raƙuman ruwa guda biyu bisa ga jadawalin da ke sama.
Nisa na tsawon tsayi 1 (λ) = mita 6 / 2 = mita 3
Lokaci (T) = daƙiƙa 0.5
Ana so: Gudun raƙuman ruwa (v)
Magani:
v = f λ = λ / T = mita 3 / daƙiƙa 0.5 = mita 6 / daƙiƙa
Amsar da ta dace ita ce B.
4. Dangane da hoton da ke ƙasa, wurin da ke da bambancin mataki na ¾ da maki A shine ....
A. Maki na B
B. Maki C
C. Maki na D
D. Ma'ana ta E
Magani
Maki B yana da bambancin mataki na ¼ λ tare da maki A
Maki C yana da bambancin mataki na 2/4 λ ko 1/2 λ tare da ma'ana A
Maki D yana da bambancin mataki na 3/4 λ tare da maki A
Maki na F yana da bambancin mataki na 5/4 λ tare da maki na A.
Madaidaicin amsar ita ce C.
5. A saman tafkin ruwa, akwai ganye biyu busassu da suka yi nisa da juna santimita 60. Dukansu suna tafiya sama da ƙasa kamar saman ruwan da mita 2 Hz. Idan ganye ɗaya ya kasance a saman, sauran ganyen suna wurin ramin, kuma a tsakaninsu, akwai rami ɗaya da rami ɗaya. A ƙayyade saurin yaɗuwar raƙuman ruwa.
A. 20 cm/s
B. 30 cm/s
C. 80 cm/s
D. 120 cm/s
An sani:
Nisa tsakanin ganyen biyu = 60 cm
Mita (f) = 2 Hz = 2
Ana so: Gudun raƙuman ruwa
Magani:
Tsakanin ganyen biyu, akwai tsawon tsayi 1.5. Nisa tsakanin tsawon tsayi 1 shine (λ) = 60 cm / 1.5 = 40 cm
Gudun raƙuman ruwa (v):
v = f λ = (2 Hz)(40 cm) = 80 cm/daƙiƙa
Madaidaicin amsar ita ce C.
6. Dangane da hoton da ke ƙasa, ƙayyade girman, lokaci, mita, da kuma saurin raƙuman ruwa.
Magani:
Girman (A) = mita 4
Lokaci (T) = daƙiƙa 6 / 3 = daƙiƙa 2
Mita (f) = 1 / T = 1 / 2 = 0.5 hertz
Tsawon Raƙuman Ruwa (λ) = mita 24 / 3 = mita 8
Gudun raƙuman ruwa (v) = f λ = (0.5 hertz) (mita 8) = mita 4/daƙiƙa ko
Gudun igiyar ruwa (v) = λ / T = mita 8 / daƙiƙa 2 = mita 4/daƙiƙa
Amsar da ta dace ita ce D.
7. A kan igiya mai tsawon mita 1.2 da nauyin gram 200, an samar da raƙuman sinusoidal guda 1.5 tare da mita na 50 Hz. Dangane da waɗannan bayanai, a ƙayyade lokacin raƙuman da ƙarfin tashin hankali na igiyar.
A. Al'ada = daƙiƙa 0.02 da ƙarfin tashin hankali = 6.67 N
B. Al'ada = daƙiƙa 0.01 da ƙarfin tashin hankali = 6.67 N
C. Tsawon lokaci = daƙiƙa 0.02 da ƙarfin tashin hankali = 266.67 N
D. Lokaci = daƙiƙa 0.01 da ƙarfin tashin hankali = 266.67 N
An sani:
Tsawon igiya (l) = mita 1.2 kuma akwai raƙuman sinusoidal guda 1.5, don haka nisan zangon 1 (λ) = mita 1.2 / 1.5 = mita 0.8
Nauyin igiya (m) = gram 200 = 0.2 kg
Mita (f) = 50 Hz
Yawan igiya (µ) = m/l = 0.2 kg / mita 1.2 = (1/6) kg/mita
Ana so: Lokacin raƙuman ruwa (T) da ƙarfin tashin hankali na igiya (T)
Magani:
Lokacin raƙuman ruwa:
T = 1 / f = 1 / 50 Hz = daƙiƙa 0.02
Gudun igiyar ruwa akan igiya:
v = f λ = (50 Hz)(mita 0.8) = mita 40/daƙiƙa
Ƙarfin tashin hankali (T):
Madaidaicin amsar ita ce C.
