Tsarin Juyawa - matsaloli da mafita

1. Ana amfani da ƙarfin F a kan igiya da aka naɗe a kusa da pulley na silinda. Ƙarfin juyi shine 2 N m kuma lokacin inertia shine 1 kg m ² , menene saurin kusurwa na silinda.

An sani:

Juyin juyi ( τ ) = 2 N m

Lokacin inertia (I) = 1 kg m ²

Ana so: Saurin kusurwa na silinda

Magani:

Στ = I α

Στ = karfin juyi, I = lokacin inertia, α = hanzarin kusurwa

Haɓaka silinda a kusurwa:

α = Στ / I = 2/1 = 2 rad/s ²

[irp]

2. Ana amfani da ƙarfin F a kan igiya da aka naɗe a kusa da pulley na silinda. Girman ƙarfin shine 10 N, radius na silinda shine 0.2 m kuma lokacin inertia shine 1 kg m 2, Menene saurin kusurwa na silinda?

An sani:

Ƙarfi (F) = 10 N

Radius na silinda (R) = 0.2 m

Lokacin inertia (I) = 1 kg m ²

Ana so: Saurin kusurwa na silinda.

Magani:

τ = FR

τ = ƙarfin juyi, F = ƙarfi, R = radius na silinda

Karfin juyi:

τ = FR = (1 0 N) (0.2 m) = 2 N m

Στ = I α

Στ = karfin juyi, I = lokacin inertia, α = hanzarin kusurwa

Haɓaka silinda a kusurwa:

α = Στ / I = 2/1 = 2 rad/s ²

[irp]

3. Ana amfani da ƙarfin F a kan igiya da aka naɗe a kusa da pulley na silinda. Girman ƙarfin shine 10 N, radius na silinda shine 0.2 m kuma nauyin silinda shine 20 kg m ^2, Menene saurin kusurwa na silinda.

An sani:

Ƙarfi (F) = 10 N

Radius na silinda (R) = 0.2 m

Nauyin silinda (M) = 20 kg

Ana so: Hanzarin kusurwa na silinda

Magani:

τ = FR = (1 0 N) (0.2 m) = 2 N m

Lokacin inertia:

I = 1⁄2 MR ² = 1⁄2 (20)(0.2) ² = 1⁄2 (20)(0.04) = 0.4 kg m ²

Haɓaka silinda a kusurwa:

α = Στ / I = 2 / 0.4 = 5 rad/s ²

[irp]

4. Toshe mai nauyin kilogiram 1 da aka rataye a kan igiya da aka naɗe a kan injin silinda. Lokacin inertia na injin shine kilogiram 1 m ² kuma radius na injin shine mita 0.2. Menene saurin kusurwa na injin. Saurin nauyi saboda nauyi shine mita 10/s ².

An sani:

Lokacin inertia na kura (I) = 1 kg m ²

Nauyin tubali (m) = 1 kg

Saurin gudu saboda nauyi (g) = 10 m/s ²

Nauyi (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 N

Radius na kura (R) = 0.2 m

Ana so: Haɓaka kusurwa

Magani:

Karfin juyi:

τ = FR = w R = (1 0 N) (0.2 m) = 2 N m

Lokacin inertia:

I = 1 kg m ²

Haɓaka kusurwa:

α = Στ / I = 2/1 = 2 rad/s ²

[irp]

5. Toshe mai nauyin kilogiram 1 da aka rataye a kan igiya da aka naɗe a kan injin silinda. Nauyin injin pulley ɗin shine kilogiram 20 kuma radius na injin pulley ɗin shine mita 0,2. Menene saurin kusurwa na injin pulley ɗin da kuma saurin faɗuwar bututun. Saurin nauyi saboda nauyi shine mita 10/s ².

An sani:

Nauyin kura (M) = 20 kg

Radius na kura (R) = 0,2 m

Nauyin tubali (m) = 1 kg

Saurin gudu saboda nauyi (g) = 10 m/s ²

Nauyi (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 N

Ana so: saurin kusurwa na pulley da kuma saurin faɗuwar tubalan kyauta.

Magani:

Ƙarfin juyi:

τ = FR = w R = (1 0 N) (0.2 m) = 2 N m

Lokacin inertia na silinda pulley:

I = 1⁄2 MR ² = 1⁄2 (20)(0.2) ² = (10)(0.04) = 0.4 kg m ²

Saurin kusurwa na kusurwoyi:

α = Στ / I = 2 / 0.4 = 5 rad/s ²

Haɓaka faɗuwar free fall na tonon:

a = R α = (0.2)(5) = 1 m/s ²