1. Abu yana da lokacin inertia na 1 kg m 2 yana juyawa a daidai gudun kusurwa na 2 rad/s. Menene kuzarin motsi na abin?
An sani:
Lokacin inertia (I) = 1 kg m 2
Gudun kusurwa ( ω) = 2 rad/s
Ana so: Ƙarfin motsi na juyawa (K E )
Magani:
Tsarin makamashin motsi na juyawa:
KE = 1/2 I ω 2
KE = makamashin motsi na juyawa (kg m2/s2), Ina = lokacin inertia (kg m2), ω = saurin kusurwa (ra/s)
Makamashin motsi na juyawa:
KE = 1/2 I ω 2 = 1/2 (1) (2) 2 = 1/2 (1) (4) = 2 Joules
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2. Pulley na silinda mai nauyin kilogiram 20 tare da radius na mita 0.2 yana juyawa a daidai lokacin da yake gudu na 4 rad/s. Menene kuzarin motsi na juyawa na pulley?
An sani:
Nauyin silinda mai kura (m) = 20 kg g
Radius na silinda (r) = 0.2 m
Gudun kusurwa (ω) = 4 ra d/s
Ana so: Menene makamashin motsi na juyawa
Mafita;
Tsarin lokacin inertia na silinda:
I = 1/2 mr 2
I = lokacin inertia ( kg m 2 ), m = nauyi (kg), r = radius (mita)
Lokacin inertia na silinda pulley:
I = 1/2 (20)(0.2) 2 = (10)(0.04) = 0.4 kg m 2
Ƙarfin motsi na juyawa na kura:
KE = 1/2 I ω 2 = 1/2 (0.4) (4) 2 = (0.2) (16) = 3.2 Joules
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3. A- ƙwallon kilogiram 10 mai radius na mita 0.1 yana juyawa a daidai gwargwado na 10 rad/s. Menene kuzarin motsi na ƙwallon.
An sani:
Nauyin ƙwallon (m) = 10 kg
Radius na ƙwallon (r) = 0.1 m
Gudun kusurwa (ω) = 10 r ad/s
Ana so: Ƙarfin motsi na juyawa
Magani:
Tsarin lokacin inertia:
I = (2/5) mr 2
I = lokacin inertia (kg m 2 ), m = nauyi (kg), r = radius (m)
Lokacin rashin kuzari na ƙwallon:
I = (2/5)(10)(0.1) 2 = (4)(0.01) = 0.04 kg m 2
Ƙarfin motsi na juyawa na ƙwallon:
K E = 1/2 I ω 2 = 1/2 (0.04) (10) 2 = (0.02) (100) = 2 Joules
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4. Ƙwayar ƙwaya mai nauyin kilogiram 0.5 tana juyawa a daidai gudun kusurwa na 2 rad/s. Menene kuzarin motsi na jujjuyawar ƙwayar idan radius na da'irar ya kai santimita 10.
An sani:
Nauyin barbashi (m) = 0.5 kg g
Radius na ƙwallon (r) = 10 cm = 10/100 = 0.1 m
Gudun kusurwa (ω) = 2 rad/ s
Ana so: Ƙarfin motsi na juyawa
Magani:
Lokacin inertia ga ƙwayoyin cuta:
I = mr 2 = (0.5)(0.1) 2 = (0.5)(0.01) = 0.005 kg m 2
Makamashin motsi na juyawa:
K E = 1/2 I ω 2 = 1/2 (0.005) (2) 2 = 1/2 (0.005) (4) = (0.005) (2) = 0.01 Joule