Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo - amfani da matsalolin da mafita na dokar farko ta Newton

1. Akwatin nauyi na kilogiram 5 yana kan jirgin sama mai karkata a kusurwar 30 o . Akwatin yana da igiya. Kayyade ƙarfin tashin hankali (T) da ƙarfin da aka saba (N)!

Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo - amfani da matsalolin da mafita na dokar farko ta Newton 1

Magani

Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo - amfani da matsalolin da mafita na dokar farko ta Newton 2ΣFx = 0

T – w sin 30 o = 0

T = w daidai da 30 o

T = (5 kg)(9.8 m/s 2 ) kusan 30 o

T = (49)(0.5)

T = 24.5 Newtons

∑ F y = 0

N – w cos 30 o = 0

N = w cos 30 o

N = (49)(0.87)

N = 43 Newton

[irp]

2. Abubuwa biyu na nauyi m 1 = m 2 = 2 kg, an haɗa su da igiya mara nauyi akan pulley mara gogayya. Nemo ƙarfin tashin hankali T 1 da T 2.

Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo - amfani da matsalolin da mafita na dokar farko ta Newton 3

Magani

Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo - amfani da matsalolin da mafita na dokar farko ta Newton 4

(a) Zane-zanen jiki kyauta don abu na 1 (b) Zane-zanen jiki kyauta don abu na 2

Yi amfani da dokar farko ta Newton ga ƙin yarda ta 1:

∑ F y = 0

T 1 – w 1 = 0

T 1 = w 1 = m 1 g = (2 kg)(9.8 m/s 2 ) = 19.6 N

Yi amfani da dokar farko ta Newton ga ƙin yarda ta 2:

∑ F y = 0

T 2 – w 2 = 0

T 2 = w 2 = m 2 g = (2 kg)(9.8 m/s 2 ) = 19.6 N

T 1 = T 2 = N 19.6.

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3. An haɗa wani abu mai nauyi w A = 30 N da abu mai nauyi w B = 40 N, ta hanyar igiya mai sauƙi wadda ke ratsa wani kurji mara gogayya na nauyin da ba shi da yawa. A ƙayyade ma'aunin matsakaicin gogayya tsakanin w B da saman da aka karkata, idan tsarin yana hutawa.

Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo - amfani da matsalolin da mafita na dokar farko ta Newton 5

Magani

Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo - amfani da matsalolin da mafita na dokar farko ta Newton 6

(a) Zane-zanen jiki kyauta don abu w A (b) Zane-zanen jiki kyauta don abu w B

Yi amfani da dokar farko ta Newton don nuna rashin jituwa a alkiblar w A a tsaye (y):

∑ F y = 0 (babu hanzari a tsaye)

T – w A = 0

T = w A = 30 Newton

Yi amfani da dokar farko ta Newton ga ƙin yarda w B a tsaye (y) alkibla :

∑ F y = 0

N – w B cos 45 o = 0

N = w B cos 45 o = (40)(0.7) = Newtons 28

Yi amfani da dokar farko ta Newton ga ƙin yarda w B a cikin alkiblar kwance (x):

∑ F x = 0

F k + w B sin 45 o – T = 0

μ s N + w B zunubi 45 o – T = 0

μ s (28) + (40) (0.7) - 30 = 0

μ s (28) + 28 – 30 = 0

μ s (28) = 30 – 28

μ s (28) = 2

μ s = 2/28

μ s = 0.07

Matsakaicin matsakaicin gogayya tsakanin w B da saman da aka karkata = 0.07.

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  1. Ƙwayoyin cuta a cikin ma'auni ɗaya
  2. Ƙwayoyin cuta a cikin ma'auni mai girma biyu
  3. Daidaiton jikin da aka haɗa ta hanyar igiyoyi da ƙwallo
  4. Daidaiton jikin da ke kan jirgin sama mai karkata

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