1. Toshe mai nauyin kilogiram 2 yana kwance a kan wani jirgin sama mai karkata a kusurwar 37 o zuwa kwance. Kayyade girman ƙarfin waje da aka yi amfani da shi a kan toshe, don haka toshe bai zame ƙasa da jirgin ba. (sin 37 o = 0.6, cos 37 o = 0.8, g = 10 ms -2 , µ k = 0.2)
An sani:
Nauyi (m) = 2 kg
Saurin gudu saboda nauyi (g) = 10 m/s 2
Nauyin tubalan ( w) = mg = (2)(10) = Newtons 20
Zunubi 37 o = 0.6
cos 37 o = 0.8
Ma'aunin gogayya mai motsi (µ k ) = 0.2
y-partment na nauyin (w y ) = w cos 37 o = (20)(0.8) = Newtons 16
Sashen x na nauyin (w x ) = w sin θ = (20)(sin 37) = (20)(0.6) = Newtons 12
Ƙarfin da aka saba (N) = w y = 16 Newtons
Ana so : Ƙarfin waje (F)
Mafita :
wx = 12 Newton
Ƙarfin gogayya mai motsi (f k ) = µ k N = (0.1)(16) = 1.6 Newtons
Girman ƙarfin waje F da aka yi a kan toshe :
F + f k – w x = 0
F = w x – f k
F = 12 – 1.6
F = 10.4 Newton
Ƙarfin waje F ya fi Newtons 10.4 girma.
[irp]
2. Nauyin tubali = 2 kg, ma'aunin gogayya mai tsauri µ s = 0.4 da θ = 45 o . Kayyade girman ƙarfin F don haka tubalin ya fara zamewa sama.
An sani:
Ma'aunin gogayya mai tsauri (µ s ) = 0.4
Kusurwoyi (θ) = 45 o
Saurin gudu saboda nauyi (g) = 10 m/s 2
Nauyin tubalan (m) = kilogiram 2
Nauyin tubalan (w) = mg = (2 kg)(10 m/s 2 ) = 20 kg m/s 2 = 20 Newtons
Sashen x na nauyin (w x ) = w sin θ = (20)(sin 45) = (20)(0.5√2) = 10√2 Newtons
y-partion na nauyin (w y ) = w cos θ = (20)(cos 45) = (20)(0.5√2) = 10√2 Newtons
Ana so : Girman ƙarfin F
Magani:
Toshe zai fara zamewa sama, idan F ≥ wx + fs.
Sashen x na nauyin:
w x = 10√2 Newton
bangaren y na nauyin :
w y = 10√2 Newton
Ƙarfin al'ada :
N = w y = 10√2 Newton
Ƙarfin gogayya mai motsi :
f s = µ s N = (0,4) (10√2) = 4√2
Girman ƙarfin F don toshe ya fara zamewa sama :
F ≥ w x + f s
F ≥ 10√2 + 4 √2
F ≥ 14√2 Newton
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