Daidaita filin lantarki

Tambayoyi 3 game da lissafin filin lantarki

1. Ƙwallon da ke riƙe da radius na cm 10 yana da wutar lantarki ta 500 μC. Maki A, B, da C suna kwance daidai da tsakiyar ƙwallon a nisan cm 12, cm 10 da cm 8 bi da bi daga tsakiyar ƙwallon. Lissafa ƙarfin filin lantarki a maki A, B, da C!

An sani:Daidaito na filin lantarki 1

Radius na ƙwallon da ke jagorantar (R) = 10 cm = 0.1 m

Cajin wutar lantarki (q) = 500 μC = 500 x 10 -6 C

r A = 12 cm = 0,12 m

r B = 10 cm = 0,1 m

r C = 8 cm = 0,08 m

Madaidaitan Coulomb (k) = 9 x 10 9

Ana so: Ƙarfin filin lantarki a wuri A (E A ), a wuri B (E B ) da kuma a wuri C (E C )

Magani:

a) Ƙarfin filin lantarki a wuri na A

E A = kq / r A 2 = (9 x 10 9 )(500 x 10 -6 ) / (0,12) 2 = (4500 x 10 3 ) / 0,0144 = 312500 x 10 3 = 3,125 x 10 8 N/C

b) Ƙarfin filin lantarki a wurin B

E B = kq / r B 2 = (9 x 10 9 )(500 x 10 -6 ) / (0,1) 2 = (4500 x 10 3 ) / 0,01 = 450.000 x 10 3 = 4,5 x 10 8 N/C

c) Ƙarfin filin lantarki a wuri na C

E C = 0 don kasancewa cikin ƙwallon.

2. Idan aka sanya cajin gwaji na 4 nC a wani wuri, cajin yana fuskantar ƙarfin 5 × 10 - 4 N. Menene girman filin lantarki E a wannan lokacin?

Wanda aka sani:

Gwajin cajin lantarki (q) = 4 nC = 4 x 10 -9 Coulomb

Ƙarfin wutar lantarki (F) = 5 × 10 -4 N

Ana so: Girman filin lantarki (E)

Magani:

E = F / q = (5 × 10 -4 ) / (4 x 10 -9 ) = 1,25 x 10 5 N/C

3. Caji biyu q B = 12 μC da q C = 9 μC an sanya su a kan kusurwar alwatika na dama kamar yadda yake a Hoto. Ƙayyade ƙarfin filin lantarki da aka ji a wurin A!

Wanda aka sani:Daidaito na filin lantarki 2

Caji a wurin B (qB) = 12 μC = 12 x 10 -6 C

Caji a wurin C (qC) = 9 μC = 9 x 10 -6 C

Madaidaitan Coulomb (k) = 9 x 10 9

r AC = 4 cm = 0,04 m

r AB = 3 cm = 0,03 m

SE busca: Ƙarfin filin lantarki a wuri ADaidaito na filin lantarki 3

Magani:

E AC = kq / r 2 = (9 x 10 9 )(9 x 10 -6 ) / (0,04) 2 = 81 x 10 3 / 0,0016 = 5,0 x 10 7 N/C

E AB = kq / r 2 = (9 x 10 9 )(9 x 10 -6 ) / (0,03) 2 = 81 x 10 3 / 0,0009 = 9,0 x 10 7 N/C