Daidaito mai nauyi

Tambayoyi 3 game da lissafin nauyi

1. Ƙwayoyin cuta guda uku kowannensu mai nauyin kilogiram 1 suna kan kusurwar alwatika mai daidaito wanda gefunansa tsawon mita 1 ne. Yaya girman ƙarfin nauyi yake a kowane ƙwayar cuta (a cikin G)?

Magani

Girman ƙarfin nauyi da ɗayan ƙwayoyin halitta ke fuskanta.

F ₁₂ = G (m ₁ )(m ₂ ) / r ² = G (1)(1) / 1 ² = G/1 = G

F ₁₃ = G (m ₁ )(m ₃ ) / r ² = G (1)(1) / 1 ² = G/1 = G

Ƙarfin nauyi da aka samu a matsayi na 1:

F ₁ = √1 ² +1 ² = √1 +1 = √2 Newtons

2. Hoton da ke ƙasa yana nuna abubuwa uku m ₁ = 6 kg; m ₂ = 3 kg da m ₃ = 4 kg suna kwance a kan layi madaidaiciya. Kayyade girma da alkiblar ƙarfin nauyi da aka samu ta hanyar m2! (yanayin a cikin G)

Wanda aka sani:

m₁ = 6kg

m2 = ₃ kg

m3 = ₄ kg

ma'aunin nauyi = G

r ₂₁ = 4 m

r ₂₃ = 2 m

Ana so: Nauyin F wanda ya samo asali daga _m2

Magani:

Ƙarfin nauyi tsakanin _m2 da _m3 :

F = G (3)(4) / 2 ² = G 12 / 4 = 3G

Ƙarfin nauyi tsakanin _m2 da _m1 :

F = G (3)(6) / 4 ² = G 18 / 16 = 1,125G

3. An raba abu A mai nauyin kilogiram 1 da abu B mai nauyin kilogiram 2 ta hanyar nisan mita 2 daga juna. Ma'aunin P shine mita 2 daga abu A da mita 2 daga abu B. Yaya ƙarfin filin nauyi yake a ma'aunin P?

Wanda aka sani:

m _A = 1 kg

m _B = 2 kg

r _PA = 2 m

r _PB = 2 m

Madaidaicin nauyi = G

Ana so: Nauyin E a wuri na P

Magani:

E _PA = G (m _A ) / r ² = G (1) / 2 ² = G/4 = 0,25G

E _PB = G (m _B ) / r ² = G (2) / 2 ² = 2G/4 = 0,5G

Ƙarfin filin nauyi da aka samu a wurin P:

E = √0,25G ² +0,5G ² = √0,0625G ² +0,25G ² = √0,3125G ² = 0,56G N/kg