Tambayoyi 3 game da lissafin bazara mai ɗorewa
1. Maɓuɓɓugar ruwa mai ɗauke da ruwa mai ɗauke da ruwa mai ɗauke da ruwa mai tsawon santimita 10. A ƙarshen da babu ruwa, ana rataye nauyin gram 200 don tsawon maɓuɓɓugar ya zama santimita 11. Idan g = 10 m/s 2 , menene ma'aunin ƙarfin maɓuɓɓugar ruwa?
Wanda aka sani:
Tsawon farko na bazara (y 1 ) = 10 cm = 0.10 m
Tsawon ƙarshe na bazara (y 2 ) = 11 cm = 0.11 m
Canjin tsawon bazara (Δy) = 0.11 – 0.10 = mita 0.01
Nauyin kayan (m) = gram 200 = 0.2 kg
Nauyin kaya (w) = mg = (0,2)(10) = Newtons 2
Ana so: Madaidaitan bazara (k)
Magani:
Tsarin da ba ya canzawa a lokacin bazara:
F = k Δy
k = F / Δy = 2 / 0,01 = 200 / 1 = 200 Newtons/mita
2. Ana iya miƙe maɓuɓɓugar ruwa ta yadda za a faɗaɗa ta da santimita 10 tare da ƙarfin Joule na 0.5. Menene ma'aunin maɓuɓɓugar ruwa?
Wanda aka sani:
Ƙara tsawon bazara (Δy) = 10 cm = mita 0.1
Makamashin ƙarfin bazara (EP) = Joules 0.5
Ana so: Madaidaitan bazara (k)
Magani:
Ana ƙididdige ma'aunin bazara ta amfani da dabarar Makamashin Spring Potential:
EP = ½ k Δy 2
2 EP = k Δy 2
2 (0,5) = k (0,1) 2
1 = k (0,01)
k = 1 / 0,01 = 100 / 1 = 100 Newtons/mita
3. Maɓuɓɓugar ruwa da aka ja da ƙarfin N 100 tana ƙara tsawonta da cm 5. A ƙididdige ma'aunin maɓuɓɓugar ruwa.
Wanda aka sani:
Ƙarfi (F) = 100 N
Ƙara tsawon bazara (Δx) = 5 cm = 0.05 m
Ana so: Madaidaitan bazara (k)
Magani:
F = k Δx
k = F / Δx = 100 / 0,05 = 10.000 / 5 = 2000 Newtons/mita
