Cajin wutar lantarki da aka adana a cikin capacitor - matsaloli da mafita

1. Ƙayyade cajin da ke cikin capacitor C 5.

An sani:Cajin wutar lantarki da aka adana a cikin capacitor - matsaloli da mafita 1

Capacitor 1 (C 1 ) = 6 F

Capacitor 2 (C 2 ) = 6 F

Capacitor 3 (C 3 ) = 3 F

Capacitor 4 (C 4 ) = 12 F

Capacitor 5 (C 5 ) = 6 F

Wutar lantarki (V) = Volt 12

Ana so: Cajin capacitor (C 5 )

Magani:

C abin da c tor

An haɗa Capacitor C 2 da capacitor C 3 a jere . Capacitor mai daidai:

1/C A = 1/C 2 + 1/C 3 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6

C A = 6/3 = Farad 2

An haɗa Capacitor C 4 da capacitor C 5 a jere. Capacitor mai daidai:

1/C B = 1/C 4 + 1/C 5 = 1/12 + 1/6 = 1/12 + 2/12 = 3/12

C B = 12/3 = Farad 4

An haɗa Capacitor C A da capacitor C B a layi ɗaya . Capacitor mai daidai:

C C = C A + C B = 2 + 4 = Farad 6

An haɗa Capacitor C 1 da capacitor C a jere :

1/C = 1/C 1 + 1/C C = 1/6 F + 1/6 F = 2/6

C = 6/2 = Farad 3

Cajin lantarki

Cajin wutar lantarki a cikin capacitor C:

q = VC = (Volts 12)(Farads 3) = Coulombs 36

C<br> <br>ctor 1 da c<br> <br>ctor CC an haɗa su a jere don haka cajin lantarki a cikin capacitor C = ba cajin lantarki a cikin capacitor C1 = cajin lantarki a cikin capacitor CC = Coulombs 36.

Ƙarfin c<br> <br>ctor CC is Farad 6 da kuma caji a cikin capacitor CC is 36 Coulombs. Ƙarfin wutar lantarki na capacitor CC is : V = q / CC = 36 Coulombs / 6 Farads = 6 Volts

Aboki CC daidai yake da capacitor don capacitor CA da kuma capacitor CB an haɗa shi a layi ɗaya. Wutar lantarki ta capacitor CC (VC) = ƙarfin lantarki a cikin capacitor CA (VA) = ƙarfin lantarki a cikin capacitor CB (VB) = 6 Volts.

Cajin wutar lantarki a cikin capacitor C B :

q B = V B C B = (Volts 6)(Farads 4) = Coulombs 24

Aboki CB daidai yake da capacitor don capacitor C4 da kuma C5 an haɗa shi cikin jerin. An haɗa a jere don haka cajin wutar lantarki a cikin capacitor CB (qB) = cajin wutar lantarki a cikin capacitor C4 (q4) = cajin wutar lantarki a cikin capacitor C5 (q5) = 24 Coulombs.

2. An haɗa na'urori masu kama da juna guda biyar masu ƙarfin 20 µF a jere da layi ɗaya, kamar yadda aka nuna a cikin hoton da ke ƙasa, tare da tushen ƙarfin lantarki na volts 6. Ka ƙayyade jimlar kuzarin da aka adana a cikin na'urar capacitor C 5.

An sani:Cajin wutar lantarki da aka adana a cikin capacitor - matsaloli da mafita 2

Capacitor C 1 = C 2 = C 3 = C 4 = C 5 = 20 µF

Wutar lantarki (V) = Volt 6

Ana nema: An adana cajin lantarki a cikin capacitor C 5

Mafita :

Aboki

An haɗa Capacitor C 1 da capacitor C 2 a jere. Capacitor mai daidai:

1/C A = 1/C 1 + 1/C 2 = 1/20 + 1/20 = 2/20

CA = 20/2 = 10 µF

An haɗa Capacitor C 3 da capacitor C 4 a jere . Capacitor mai daidai:

1/C B = 1/C 3 + 1/C 4 = 1/20 + 1/20 = 2/20

C B = 20/2 = 10 µF

An haɗa Capacitor C A da capacitor C B a layi ɗaya . Capacitor mai daidai:

C C = C A + C B = 10 + 10 = 20 µF

An haɗa Capacitor C da capacitor C5 a jere :

1/C = 1/C C + 1/C 5 = 1/20 + 1/20 = 2/20

C = 20/2 = 10 µF

Cajin lantarki

Cajin wutar lantarki a cikin capacitor daidai C:

q = VC = (6 Volt)(10 x 10 -6 Farad) = 60 x 10 -6 Coulomb = 60 µC

Aboki CC da kuma capacitor 5 an haɗa su a jere don haka cajin lantarki a cikin capacitor daidai yake C = ba cajin lantarki a cikin capacitor CC = cajin lantarki a cikin capacitor C5 = 60 µC.

3. An haɗa capacitors guda biyar a jere da layi ɗaya kamar yadda aka nuna a cikin hoton da ke ƙasa. Ƙayyade cajin wutar lantarki a cikin capacitor C 1 (1 µ = 10 -6 )

An sani:Cajin wutar lantarki da aka adana a cikin capacitor - matsaloli da mafita 3

Capacitor 1 (C 1 ) = capacitor 5 (C 5 ) = 9 µ F

Capacitor 2 (C 2 ) = capacitor 3 (C 3 ) = capacitor 4 (C 4 ) = 6 µ F

Wutar lantarki (V) = Volt 12

Ana so: Cajin wutar lantarki a cikin capacitor C 1

Magani:

Aboki

An haɗa Capacitor C 2 da capacitor C 3 a jere . Capacitor mai daidai:

1/C A = 1/C 2 + 1/C 3 = 1/6 + 1/6 = 2/6

C A = 6/2 = 3 µ F

An haɗa Capacitor C A da capacitor C 4 a layi ɗaya . Capacitor mai daidai:

C B = C A + C 4 = 3 + 6 = 9 µ F

An haɗa Capacitor C 1 , capacitor C B da capacitor C 5 a jere . Capacitor mai daidai:

1/C = 1/C 1 + 1/C B + 1/C 5 = 1/9 + 1/9 + 1/9 = 3/9

C = 9/3 = 3 µF = 3 x 10 -6 Farad

Cajin lantarki

Cajin wutar lantarki a cikin capacitor daidai C:

q = VC = (12 Volt)(3 x 10 -6 Farad) = 36 x 10 -6 Coulomb = 36 µC

Aboki C1, karfin CB da kuma capacitor C5 an haɗa su a jere don haka cajin lantarki a cikin capacitor daidai yake C = ba cajin lantarki a cikin capacitor C1 = cajin lantarki a cikin capacitor daidai gwargwado CB = cajin lantarki a cikin capacitor C5 = 36 µC.

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