1. Four capacitors, C1 = 2 μF, C2 = 1 μF, C3 = 3 μF, C4 = 4 μF, are connected in parallel. Determine the capacitance of a single capacitor that will have the same effect as the combination.
An sani:
Aboki C1 = 2 μF
Aboki C2 = 1 μF
Aboki C3 = 3 μF
Aboki C3 = 4 μF
Ana so: Daidaitaccen ƙarfin
Magani:
Daidaitaccen ƙarfin:
C = C1 +C2 +C3
C = 4 μF+2 μF+3 μF=9 μF
The equivalent capacitance of the entire combination is 9 μF.
2. Ayyade da cajin on capacitor C2 idan bambancin yuwuwar between point A and B is 9 Volt…
An sani:
C<br> <br>ctor C1 = 20 μF = 20 x 10-6 F
C<br> <br>ctor C2 = 30 μF = 30 x 10-6 F
Potential difference between point A da kuma B (VAB) = Volt 9
Nema : the charge on capacitor C2 (Q2)
Magani:
Potential difference :
Capacitors are connected in parallel so that the potential difference between A and B (VAB) = the potential difference on capacitor C1 (V1) = the potential difference on capacitor C2 (V2) = 9 Volts.
Cajin wutar lantarki akan capacitor C2 :
Q2 = C2 V2 = (30 x 10-6)(9) = 270 x 10-6 C
Q2 = 270 μC
Cajin wutar lantarki akan capacitor C2 is 270 μC.
3. Three capacitors, C1 = 4 μF, C2 = 2 μF, C3 = 3 μF, are connected in parallel. The capacitor are charged. The potential difference on capacitor C2 is 4 Volt. Determine
(a) Electric charge on capacitor C1, C2 da C3
(b) Electric charge on the equivalent capacitor of the entire combination
An sani:
C<br> <br>ctor C1 = 4 μF = 4 x 10-6 F
Capacitor C2 = 2 μF = 2 x 10-6 F
Capacitor C3 = 3 μF = 3 x 10-6 F
Potential difference on capacitor C2 (V2) = Volt 4
Nema : Cajin wutar lantarki akan capacitor C3 (Q3)
Magani:
(A) Cajin wutar lantarki akan capacitor C3
Bambancin da ke tsakanin capacitors da capacitors C3 :
Capacitors are connected in parallel so that the potential difference on capacitor C3 (V3) = the potential difference on capacitor C2 (V2) = the potential difference on capacitor C1 (V1) = the potential difference on equivalent capacitor (V) = Volt 4
Cajin wutar lantarki akan capacitor C1 :
Q1 = C1 V1 = (4 x 10-6)(4) = 16 x 10-6 C
Q1 = 16 μC
Cajin wutar lantarki akan capacitor C2 :
Q2 = C2 V2 = (2 x 10-6)(4) = 8 x 10-6 C
Q2 = 8 μC
Cajin wutar lantarki akan capacitor C3 :
Q3 = C3 V3 = (3 x 10-6)(4) = 12 x 10-6 C
Q3 = 12 μC
(B) Electric charge on equivalent capacitor
Q = Q1 +Q2 +Q3
Q = 16 μC + 8 μC + 12 μC=36 μC
Alternative solution :
Daidaitaccen ƙarfin:
C = C1 +C2 +C3
C=4 μF+2 μF+3 μF=9 μF
C = 9 x 10-6 F
The potential difference on the equivalent capacitor :
V1 = V2 = V3 = V = 4 Volt
The electric charge on the equivalent capacitor :
Q = C V = (9 x 10-6)(4) = 36 x 10-6 C
Q = 36 μC
