Resistors ann an co-shìnte

Resistors ann an co-shìnte 1

Artaigil mu na Resistors ann an co-shìnte

Ma tha na resistors ceangailte mar a tha san fhigear, tha na resistors ceangailte ann am parail.

Tha sruth dealain (sruth dealain = cosgais dealain a bhios a’ sruthadh rè ùine) a thig a-steach don phuing ceangail mar an ceudna ris an t-sruth dealain a thig a-mach às a’ phuing ceangail. Tha grunn cheanglaichean ann agus mar sin tha an sruth dealain iomlan = meud an t-sruth dealain a tha a’ sruthadh anns gach ceangal. Gu matamataigeach, I = I1 + I.2 + I.3Ged a tha an diofar comas dealain no bholtaids dealain anns gach ceangal tha e mar an ceudna.

I = V/R agus mar sin bidh an co-aontar gu h-àrd ag atharrachadh gu I = V/R1 + V/R2 + V/R3Tha am bholtaids dealain co-ionann, agus mar sin bidh an co-aontar seo ag atharrachadh gu I = V (1/R1 +1/R2 +1/R3). Ma tha an aghaidh co-ionann 1/R an uairsin tha I = V (1/R). Mar sin, 1/R = 1/R1 +1/R2 +1/R3.

faic cuideachd  Meòrachadh speurail agus meòrachadh sgapte

Tha buannachd aig cuairtean co-shìnte, ma bhriseas an sruth dealain gu aon de na resistors, bidh an sruth dealain a’ leantainn air adhart a’ sruthadh chun na resistors eile. Ach ann an sreath, ma bhriseas sruth dealain ann an aon resistor, cha tèid na resistors uile a dhealanachadh.

Eisimpleir de dhuilgheadas 1:

Tha fios gu bheil R1 = 2 Ω, R2 = 3 Ω. Tha an dà resistor co-shìnte. Dè an luach a th’ aig an resistor co-ionann? (Ω = Ohm).

fuasgladh:

1/R = 1/R1 +1/R2 = 1/2 + 1/3 = 3/6 + 2/6 = 5/6

R = 6/5 = 1.2 Ω.

Tha an toradh seo a’ sealltainn gu bheil luach an aghaidh-sheasamh co-ionann nas lugha na luach gach aghaidh-sheasamh co-shìnte.

Eisimpleir de dhuilgheadas 2:

Dà Rs1 = Tha 50 Ω agus 50 resistor ceangailte ann an sreath agus co-shìnte, ceangailte ri bataraidh 12 Volt. Obraich a-mach:

faic cuideachd  Co-aontar leantainneachd

(a) An aghaidh cho-ionann

(b) Sruth dealain tro gach resistor

fuasgladh:

(a) Resistors ann an sreath:

R = R1 + R.2 = 50 Ω + 50 Ω = 100 Ω.

Resistors ann an co-shìnte:

1/R = 1/R1 +1/R2 = 1/50 + 1/50 Ω = 2/50

R = 50/2 = 25 Ω

(b) Resistors ann an sreath:

I = V / R = 12 Volts / 100 Ω = 0.12 A

Resistors ann an co-shìnte:

I = V / R = 12 Volts / 25 Ω = 0.48 A

Tha an toradh seo a’ sealltainn gu bheil an sruth dealain iomlan a tha a’ sruthadh anns a’ chuairt cho-shìnte nas motha, agus gu bheil an sruth dealain iomlan a tha a’ sruthadh anns an t-sreath nas lugha.

Fàg beachd