1.
Zanjirdagi elektr tokini aniqlang (1 µF = 10 -6 F)
Ma'lum:
Qarshilik (R) = 12 Ohm
Induktor (L) = 0.075 H
Kondensator (C) = 500 µF = 500 x 10 -6 F = 5 x 10 -4 Farad
Kuchlanish kuchi (V) = V o sin ω t = V o sin 2πf t = 26 sin 200t
Kerakli: Elektr toki
yechim:
Empedans (Z):
Induktiv reaktivlik (X L ) = ωL = (200)(0,075) = 15 Ohm
Sig'imli reaktivlik (X C ) = 1 / ω C = 1 / (200)(5 x 10 -4 ) = 1 / (1000 x 10 -4 ) = 1 / 10 -1 = 10 1 = 10 Ohm
Qarshilik (R) = 12 Ohm
Elektr toki (I) :
I = V / Z = 26 Volt / 13 Ohm
I = 2 Volt/Ohm
I = 2 Amper
2. Agar zanjirning impedansi 250 Ω bo'lsa, R rezistorining qarshiligini aniqlang.
Ma'lum:
Zanjirning impedansi (Z) = 250 Ω
Kondensator (C) = 8 m F = 8 x 10 -6 F
Induktor (L) = 0.8 H
Kuchlanish (V) = 200 Volt
w = 500 rad/s
Kerakli: Rezistorning qarshiligi (R)
yechim:
3. Induktorning ikkala chetining potensiallar farqini aniqlang.
Ma'lum:
R = 40 Vt
X L = 150 Vt
X C = 120 Vt
V = 100 Volt
Istalgan: potensiallar farqi
yechim:
Zanjirning umumiy empedansi Z:
Induktorning ikkala chetining potensiallar farqi:
