1. A 0.2-kg ball, attached to the end of a horizontal cord, is revolved in a circle of radius 1 meter and ball’s maximum speed is 10 rpm. What is the magnitude of the centripetal acceleration and the magnitude of the tension force?
Dipikanyaho:
massa (m) = 0.2 kg
Radius (r) = 1 m
Laju sudut (ω) = 10 rev/min = 10 rev/60 s = 0.17 rev/s = (0.17)(6.28 rad)/s = 1 rad/s
laju (v) = r ω = (1 m)(1 rad/s) = 1 m/s
Dipilari: as dan ΣF
Solusi:
(a) The magnitude of the centripetal acceleration
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(b) The magnitude of the tension force
ΣF = ma
T = m as
T = (0.2 kg)(1 m/s2)
T = 0.2 kg m/s2
T = 0.2 N
2. A 1-kg ball at the end of a string is revolving uniformly in a horizontal circle of radius 1 m. The cord will break when the tension in it exceeds 100 N. What is the maximum speed the ball can have?
Dipikanyaho:
Massa (m) = 1 kg
Radius (r) = 1 meter
Tension force (T) = gaya sentripetal (ΣF) = 100 N
miharep: v maximum
Solusi:

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- Massa sareng beurat
- Gaya normal
- Hukum gerak kadua Newton
- Gaya gesekan
- Motion on a horizontal surface without friction force
- The motion of two bodies with the same acceleration on the rough horizontal surface with a friction force
- Motion on an inclined plane without friction force
- Gerak dina bidang miring kasar kalawan gaya gesekan
- Gerakan dina lift
- Gerakan awak disambungkeun ku tali sareng katrol
- Dua awak anu gaduh akselerasi anu sami
- Ngabulatkeun kurva datar - dinamika gerak sirkular
- Ngabulatkeun kurva miring - dinamika gerak sirkular
- Gerakan seragam dina bunderan horizontal
- Gaya séntripetal dina gerak sirkular seragam