9 Converting temperature scales (Celsius scale Fahrenheit scale Kelvin scale)
1. 50 oC = ….. oF?
leyuran
At standard atmospheric tekenan, the freezing point of water is 0 oC on the Celsius scale jeung 32 oF on the Fahrenheit scale. At standard atmospheric pressure, the boiling point of water is 100 oC on the Celsius scale and 212 oF on the Fahrenheit scale.
0 oC = 32 oF sareng 100 oC = 212 oF. A change of 5 Co = a change of 9 Fo.
For a Celsius scale, the distance between 0 oC sareng 100 oC divided into 100 equal intervals. For a Fahrenheit scale, the distance between 0 oC sareng 100 oC divided into 180 equal intervals.
ToF = (180/100) ToC + 32
ToF = (9/5) ToC + 32
ToF = (9/5) 50 + 32
ToF = (9) 10 + 32
ToF=90 + 32
ToF=122
50 oC = 122 oF
2. 86 oF = ….. oC?
leyuran
ToC = (100/180)(ToF – 32)
ToC = (5/9)(ToF – 32)
ToC = (5/9)(86 – 32)
ToC = (5/9)(54)
ToC = (5)(6)
ToC = 30
86 oF=30 oC
3. 50oC = ….. K ?
leyuran
T = T oC + 273
T = 50 + 273
T = 323
50 oC= 323 K
4. 212oF = ….. K ?
leyuran
ToC = (100/180)(ToF – 32)
ToC = (5/9)(ToF – 32)
ToC = (5/9)(212 – 32)
ToC = (5/9)(180)
ToC = (5)(20)
ToC = 100
212 oF=100 oC + 273
212 oF=373 K
5. x oC = x oF
x = ….. ?
leyuran
1 : Converting Celsius scale into Fahrenheit scale

2 : Converting Fahrenheit scale into Celsius scale

6. 122°F = ….. Celsius
leyuran
The conversion between the two temperature scales can be written :
TC = 5/9 (TF - 32)
TC = suhu in Celsius, TF = temperature in Fahrenheit
The temperature in Celsius :
TC = 5/9 (122 – 32) = TC = 5/9 (90) = 5 (10)
TC = 50 oC
7. The figure below shows the temperature measurement of a liquid with the Fahrenheit scale thermometer! If the temperature of the liquid is measured using a Celsius scale thermometer, then naon the liquid temperature.
Dipikanyaho:
Fahrenheit skala (TF) = 95oF
Dipilari: Celsius scale
Solusi:
At a pressure of 1 atm, the freezing point of water is 0 °C while the Fahrenheit scale is 32 oF. Conversely, the boiling point of water for the Celsius scale is 100 oC while the Fahrenheit scale is 212 oF.
On the Celsius scale, between 0 °C and 100 ° C there are 100 ° while on the Fahrenheit scale between 32 °F to 212 °F there is 180°.
TC = 100/180 (TF - 32)
TC = 5/9 (TF - 32)
TC = 5/9 (95 - 32)
TC = 5/9 (63)
TC = 315 / 9
TC = 35oC
8. Based on figure below, determine the temperature P on the Celsius thermometer.
leyuran
TC = 100/180 (TF - 32) 
TC = 5/9 (TF - 32)
TC = 5/9 (104 – 32)
TC = 5/9 (72)
TC = 360 / 9
TC = 40 oC
9. If the temperature of Celsius scale as shown in figure below, determine the temperature of Fahrenheit scale as shown in figure below.
Solusi:
ToF = (180/100) ToC + 32
ToF = (9/5) ToC + 32
ToF = (9/5) 60 + 32
ToF = (9) 12 + 32
ToF=108 + 32
ToF=140
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