Hukum Charles (tekanan konstan) – masalah sareng solusi

1. In a closed container, the gas expands so that the final volume becomes 3 times the initial volume (V = initial volume, T = initial suhu). What is the final temperature?

Dipikanyaho:

Volume awal (V1) = V

Volume ahir (V2) = 3V

Suhu awal (T1) = T

miharep: Suhu ahir (T2)

Solusi:

Rumus tina Hukum Charles :

Charles's law (constant pressure) - problems and solutions 1

The final temperature of gases becomes 3 times the initial temperature.

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2. abdideal gases initially have volume V and temperature T. If the gas undergoes the isobaric process so that the temperature becomes 2 times the initial temperature then the final volume of gases is…

Dipikanyaho:

Volume awal (V1) = V

Suhu awal (T1) = T

Suhu ahir (T2) = 2T

miharep: final volume (V2)

Solusi:

Charles's law (constant pressure) - problems and solutions 2

The final volume of gases becomes 2 times the initial volume.

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3. In a closed container, ideal gases initially have a volume of 2 liters and temperature of 27oC. If the final volume of gases becomes 3 liters then the final temperature is…

Dipikanyaho:

Volume awal (V1) = 2 liters = 2 dm3 = 2 x 10-3 m3

Volume ahir (V2) = 3 liters = 3 dm3 = 3 x 10-3 m3

Suhu awal (T1) = 27oC + 273 = 300 K

Dipilari: Suhu ahir (T2)

Solusi:

Charles's law (constant pressure) - problems and solutions 3

The final temperature is 177oC or 177 + 273 = 450 Kelvin.

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