Lipotso tse 3 mabapi le equation ea matla a tloaelehileng
1. Boloko bo na le boima ba 5 kg. Haeba g = 10 m/s 2 , fumana:
a) boima ba boloko
b) matla a tloaelehileng haeba boloko bo behiloe sefofaneng se bataletseng
c) matla a tloaelehileng haeba boloko bo lutse sefofaneng se sekametseng se etsang sekhutlo sa 30 o ho ea ho se otlolohileng
Tse tsejoang:
Boima ba boloko (m) = 5 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Ho batloa: w, N sefofaneng le N moeding
tharollo:
a) Boima ba mahlasedi
w = mg = 5 (10) = 50 Newton
b) Matla a tloaelehileng haeba boloko bo le sebakeng se bataletseng
N = w = 50 Newton
c) Matla a tloaelehileng haeba boloko bo sekametse
N = w y = w cos θ = 50 (cos 30) = 50 (½ √3) = 25√3 Newtons
2. Sesupa-metsotso sa digrama tse 120 se hatelloa ka ho otloloha botong ka matla a 15 N. Matla a tloaelehileng a sebetsang ho sesupa-metsotso ke afe?
Tsejoa:
Boima (m) = digrama tse 120 = 0.12 kg
Matla (F) = 15 Newton
Ho batloa: Matla a tloaelehileng
tharollo:
Matla a tloaelehileng = ho sutumelletsa = 15 Newtons
3. Metsi a nooang a ka botlolong a ntseng a le ka lebokoseng a huloa ka matla a F = 200 N a etsang sekhutlo sa 37 o ka lehlakoreng le otlolohileng. 37 o = 0.6. Boima ba khateboto le dikahare tsa yona ke 20 kg. Haeba coefficient ya static friction fatshe e le 0.5 mme coefficient ya kinetic friction fatshe e le 0.2, fumana matla a tlwaelehileng a sebetsang khatebotong.
Tse tsejoang:
Matla a ho hula (F) = 200 N
Sebe sa 37 = 0,6
Fy = F sebe 37 = (200)(0,6) = 120 N
Boima ba khateboto (m) = 20 kg
Boima ba khateboto (w) = mg = (20)(10) = 200 N
Ho batloa: Matla a tloaelehileng holim'a khateboto (N)
tharollo:
Bala matla a tloaelehileng u sebelisa foromo ea matla a tloaelehileng:
N = w – F y = 200 – 120 = 80 Newtons
