Tekanyo ea matla a khoheli

Lipotso tse 3 mabapi le equation ea matla a khoheli

1. Dikaroloana tse tharo ka nngwe tse nang le boima ba 1 kg di hodima dikhutlotharo tse lekanang tseo mahlakore a tsona a bolelele ba 1 m. Matla a kgoheli a fumanwang ke karoloana ka nngwe ya ntlha (ho G) a maholo hakae?

tharollo

Boholo ba matla a khoheli a bonoang ke e 'ngoe ea likaroloana.

F ₁₂ = G (m ₁ )(m ₂ ) / r ² = G (1)(1) / 1 ² = G/1 = G

F ₁₃ = G (m ₁ )(m ₃ ) / r ² = G (1)(1) / 1 ² = G/1 = G

Matla a khoheli a hlahang ntlheng ea 1:

F ₁ = √1 ² +1 ² = √1 + 1 = √2 Li-Newton

2. Setšoantšo se ka tlase se bontša lintho tse tharo m ₁ = 6 kg; m ₂ = 3 kg le m ₃ = 4 kg li robetse moleng o otlolohileng. Fumana boholo le tataiso ea matla a khoheli a hlahang a fumanoang ke m2! (boemo ho G)

Tse tsejoang:

m₁ = 6 kg

m2 = ₃ kg

m3 = ₄ kg

matla a khoheli a sa fetoheng = G

r ₂₁ = 4 m

r ₂₃ = 2 m

Ho batloa: Matla a khoheli a bakoang ke F a bonoang ke _m2

tharollo:

Matla a khoheli a pakeng tsa _m2 le _m3 :

F = G (3)(4) / 2 ² = G 12 / 4 = 3G

Matla a khoheli a pakeng tsa _m2 le _m1 :

F = G (3)(6) / 4 ² = G 18 / 16 = 1,125G

3. Ntho A e nang le boima ba 1 kg le ntho B e nang le boima ba 2 kg di arotswe ka sebaka sa 2 m ho tloha ho e mong. Ntlha ya P e 2 m ho tloha ho ntho A le 2 m ho tloha ho ntho B. Tshimo ya matla a khoheli e matla hakae ntlheng ya P?

Tse tsejoang:

m _A = 1 kg

m _B = 2 kg

r _PA = 2 m

r _PB = 2 m

Matla a khoheli a sa fetoheng = G

Ho batloa: Matla a khoheli a E ntlheng ea P

tharollo:

E _PA = G (m _A ) / r ² = G (1) / 2 ² = G/4 = 0,25G

E _PB = G (m _B ) / r ² = G (2) / 2 ² = 2G/4 = 0,5G

Matla a matla a khoheli a hlahang ntlheng ea P:

E = √0,25G ² +0,5G ² = √0,0625G ² +0,25G ² = √0,3125G ² = 0,56G N/kg