Ho potlakisa bohareng ba pelo - mathata le litharollo

1. Bolo, e hoketsoeng pheletsong ea thapo e rapameng, e potoloha ka selikalikoe sa radius ea 20 cm. Bolo e potoloha 360 o motsotsoana o mong le o mong. Fumana boholo ba ho potlakisa ha centripetal!

Tse tsejoang:

Lebelo la Angular (ω ) = 360 o /motsotswana = 1 revolution/motsotswana = 6.28 radians/motsotswana

Radius (r) = 20 cm = 0.2 m

Ho batloa: Ho potlakisa centripetal (a r )

Tharollo:

a r = v 2 / r —> v = r ω

a r = (r ω) 2 / r = r 2 ω 2 / r

a r = r ω 2

a s = ho potlaka ha bohareng, v = lebelo le otlolohileng, r = radius, ω = lebelo la angular

Boholo ba ho potlaka ha centripetal :

a r = r ω 2 a r = (0,2 m)( 6.28 rad/s)

a r = 1.256 m/s 2

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2. Lebili la 30 cm ka radius le potoloha ka lebelo la 180 rpm. Fumana lebelo la bohareng ba ntlha e ka lehlakoreng la lebili!

Tse tsejoang:

Radius (r) = 30 cm = 0.3 m

Lebelo la Angular ( ω ) = diphetoho tse 180 / metsotsoana e 60 = diphetoho tse 3 / motsotsoana = (3)(di-radian tse 6.28) / motsotsoana = di-radian tse 18.84/motsotswana

Ho batloa: ho potlakisa bohareng ( a r ) ba r = 0.3 m

Tharollo:

Boholo ba ho potlaka ha centripetal:

a r = r ω 2

a r = (0.3 m)(18.84 rad/s)

a r = 5.65 m/s 2

3. Koloi ea mabelo e tsamaea tseleng e chitja ea radius ea limithara tse 50. Haeba lebelo la koloi e le 72 km/h, fumana boholo ba lebelo la centripetal!

Tse tsejoang:

Radius (r) = limithara tse 50

Lebelo (v) = 72 km/h = (72)(limithara tse 1000) / metsotsoana e 3600 = limithara tse 20/motsotsoana

Ho batloa : boholo ba ho potlaka ha centripetal (a r )

Tharollo:

a r = v 2 / r = 20 2 / 50 = 400 / 50 = 8 m/s 2

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4. Koloi e na le lebelo le phahameng ka ho fetisisa la centripetal la 10 m/s 2 , kahoo koloi e ka reteleha ntle le ho thella tseleng e kobehileng. Haeba koloi e tsamaea ka lebelo le sa fetoheng la 108 km/h, radius ea curve e sa kobehang ke efe?

Tse tsejoang:

Ho potlaka ha centripetal (a r ) = 10 m/s 2

Lebelo la koloi (v) = 108 km/ h = (108)(1000) / 3600 = 30 metres s /se c ho d

Ho batloa: radius (r)

Tharollo:

r = v 2 / a r

r = 30 2 / 10 = 900 / 10 = 90 limithara s

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  1. Mathata a sampole a diyuniti tsa dikhutlo a fetolang ka ditharollo
  2. Mathata le litharollo tsa sampole ea ho falla ka mokhoa o otlolohileng le oa ho falla ka mokhoa o otlolohileng
  3. Mathata a sampole ea lebelo la angular le lebelo le otlolohileng ka litharollo
  4. Mathata a mohlala oa ho potlakisa ka mokhoa o otlolohileng le oa ho potlakisa ka litharollo
  5. Mehlala ea mathata a metsamao e chitja e tšoanang ka litharollo
  6. Mathata a sampole ea ho potlakisa centripetal ka litharollo
  7. Mathata a sampole ea metsamao e chitja e sa tšoanelang ka litharollo

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