1. Xoog P ah ayaa lagu dabaqaa hal dhinac oo ka mid ah alwaax dhererkiisu yahay 2 m. Waa maxay baaxadda xoogga ? dhidibka wareegga ee barta A.
La yaqaan:
Xoogga (F) = 10 N
Dhererka AB (r AB ) = 2 m
Xoogga F waa mid toosan oo ku toosan biraha.
Gacanta kabaalka (l ) = r AB sin 90 o = (2 m)(1) = 2 m
La Doonayo: Xoogga ku wareegsan dhidibka wareegga
Xalka:
Xoogga:
τ = F l = (10 N)(2 m) = 20 N m
Calaamadda dheeraadka ah sababtoo ah iftiinka ayaa wareega saacadda ka soo horjeeda u wareegaya.
2. Dhererka fallaadhaha AB waa 2 m, baaxadda xoogga F-na waa 10 N. Waa maxay baaxadda awoodda? Dhidibka wareegga ee barta A.
La yaqaan:
Xoogga (F) = 10 N
Dhererka AB (r AB ) = 2 m
Gacanta kabaalka (l ) = r AB sin 60 o = (2 m)(0.5 √3 ) = √3 m
La Doonayo: Xoogga ku wareegsan dhidibka wareegga
Xalka:
Xoogga:
τ = F l = (10 N)( √3 m) = 10 √3 N m
Calaamadda dheeraadka ah sababtoo ah xoogga F wuxuu sababaa in iftiinka uu wareego wareegga saacadda ka soo horjeeda.
3. Dhererka alwaaxdu waa 2 m. Cabbirka F 1 waa 10 N, cabbirka F 2na waa 15 N. Go'aami xoogga shabagga ee ku wareegsan bartamaha alwaaxdu.
dhidibka wareegga ee bartamaha alwaaxa.
La yaqaan:
Xoogga 1 (F 1 ) = 10 N
Masaafada u dhaxaysa F 1 iyo bartamaha alwaaxa (r 1 ) = 1 m
Gacanta kabaalka 1 (l 1 ) = r 1 sin 90 o = (1 m)(1) = 1 m
Xoogga F 1 wuxuu ku toosan yahay biraha.
Xoogga 2 (F 2 ) = 15 N
Masaafada u dhaxaysa F 2 iyo bartamaha alwaaxa (r 2 ) = 1 m
Xoogga F 2 wuxuu ku toosan yahay biraha.
Gacanta kabaalka 2 (l 2 ) = r 1 sin 90 o = (1 m)(1) = 1 m
La Doonayo: Wareegga saafiga ah ee ku saabsan dhidibka wareegga
Xalka:
Awoodda 1aad:
τ 1 = F 1 l 1 = (10 N)( 1 m) = 10 N m
Calaamadda dheeraadka ah sababtoo ah xoogga F 1 wuxuu sababaa in iftiinka uu wareego wareegga saacadda ka soo horjeeda.
Awoodda 2aad:
τ 2 = F 2 l 2 = (15 N) ( 1 m) = -15 N
Calaamadda laga jaray sababtoo ah xoogga F 2 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Xoogga saafiga ah:
Σ τ = τ 1 - τ 2 = 10 - 15 = - 5 N m
Calaamadda laga jarayo waa sababtoo ah fallaarta ayaa u wareegaysa dhanka saacadda.
4. Dhererka fallaadhaha AB waa 2 m, baaxadda F 1 waa 10 N iyo baaxadda F 2 waa 10 N. Go'aami xoogga shabagga ee ku wareegsan bartamaha fallaadhaha.
dhidibka wareegga ee bartamaha alwaaxa.
La yaqaan:
Xoogga 1 (F 1 ) = 10 Nn
Masaafada u dhaxaysa F 1 iyo bartamaha alwaaxa (r 1 ) = 1 m
Gacanta kabaalka 1 (l 1 ) = r 1 sin 60 o = (1 m)(0.5 √3 ) = 0.5 √3 m
Xoogga 2 (F 2 ) = 10 N
Masaafada u dhaxaysa F 2 iyo bartamaha alwaaxa (r 2 ) = 1 m
Xoogga F 2 wuxuu ku toosan yahay biraha.
Gacanta kabaalka 2 (l 2 ) = r 2 sin 90 o = (1 m)(1) = 1 m
La Doonayo: Wareegga saafiga ah ee ku saabsan dhidibka wareegga
Xalka:
Awoodda 1aad:
τ 1 = F 1 l 1 = (10 N) ( 0.5 √3 m) = 5 √3 = 8.7 Nm
Calaamadda dheeraadka ah sababtoo ah xoogga F 1 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Awoodda 2aad:
τ 2 = F 2 l 2 = (10 N)( 1 m) = -10 N m
Calaamadda laga jaray sababtoo ah xoogga F 2 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Xoogga saafiga ah:
Σ τ = τ 1 - τ 2 = 8.7 - 10 = - 1.3 N m
Calaamadda laga jaray sababtoo ah xoogga saafiga ah wuxuu sababaa in fallaadha ay u wareegto dhanka saacadda.
5. Dhererka alwaaxdu waa 10 m, baaxadda F 1 waa 10 N, baaxadda F 2 waa 10 N iyo baaxadda F 3 waa 15 N. Masaafada u dhaxaysa barta A iyo barta C waa 7.5 m. Xoogga F 2 wuxuu ku yaal bartamaha alwaaxda. Go'aami wareegga saafiga ah ee ku saabsan barta C oo ku taal 2.5 m laga bilaabo barta B.
Dhidibka wareegga wuxuu ku yaal barta C
La yaqaan:
Xoogga 1 (F 1 ) = 10 N
Masaafada u dhaxaysa F 1 iyo barta C (r 1 ) = 2.5 m
Xoogga F 1 wuxuu ku toosan yahay biraha.
Gacanta kabaalka 1 (l 1 ) = r 1 sin 90 o = ( 2.5 m)( 1 ) = 2.5 m
Xoogga 2 (F 2 ) = 10 N
Masaafada u dhaxaysa F 2 iyo barta C (r 2 ) = 2.5 m
Xoogga F 2 wuxuu ku toosan yahay biinka.
Gacanta kabaalka 2 (l 2 ) = r 2 sin 90 o = ( 2.5 m)(1) = 2.5 m
Xoogga 3 (F 3 ) = 15 N
Masaafada u dhaxaysa F 3 iyo barta C (r 3 ) = 7.5 m
Xoogga F 3 wuxuu ku toosan yahay biinka.
Gacanta kabaalka 3 (l 3 ) = r 3 sin 90 o = (7.5 m)(1) = 7.5 m
La Doonayo: Wareegga saafiga ah ee ku saabsan dhidibka wareegga
Xalka:
Awoodda 1aad:
τ 1 = F 1 l 1 = (10 N)( 2.5 m) = 25 N m
Calaamadda dheeraadka ah sababtoo ah xoogga F 1 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Awoodda 2aad:
τ 2 = F 2 l 2 = (10 N)( 2.5 m) = 25 N m
Calaamadda T ee lagu daray sababtoo ah xoogga F 2 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Awoodda 3aad:
τ 3 = F 3 l 3 = (15 N)( 7.5 m) = -112..5 N m
Calaamadda laga jaray sababtoo ah xoogga F 3 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Xoogga saafiga ah:
Σ τ = τ 1 + τ 2 - τ 3 = 25 + 25 - 112.5 = - 62.5 N m
Calaamadda laga jaray sababtoo ah xoogga saafiga ah wuxuu sababaa in fallaadha ay u wareegto dhanka saacadda.
6. Dhererka alwaaxdu waa 10 m, baaxadda F1 waa 10 N, baaxadda F2 waa 10 N iyo baaxadda F3 waa 10 N. Go'aami wareegga saafiga ah ee ku saabsan barta A, oo ku taal 5 m u jirta meesha
tirada isticmaalka xoogga F1.
dhidibka wareegga ee barta A.
La yaqaan:
Xoogga 1 (F 1 ) = 10 N
Masaafada u dhaxaysa F 1 iyo barta A (r 1 ) = 5 m
Gacanta kabaalka 1 (l 1 ) = r 1 sin 60 o = (5 m)(0.5 √3 ) = 2.5 √3 m
Xoogga 2 (F 2 ) = 10 N
Masaafada u dhaxaysa F 2 iyo barta A (r 2 ) = 0
Xoogga F 2 wuxuu ku toosan yahay biinka.
Gacanta kabaalka 2 (l 2 ) = r 2 sin 90 o = (0)(1) = 0
Xoogga 3 (F 3 ) = 10 N
Masaafada u dhaxaysa F 3 iyo barta A (r 3 ) = 10 m
Gacanta kabaalka 3 (l 3 ) = r 3 sin 30 o = (10 m)(0.5) = 5 m
La Doonayo: wareegga saafiga ah ee ku saabsan dhidibka wareegga
Xalka:
Awoodda 1aad:
τ 1 = F 1 l 1 = (10 N)( 2.5 √3 m ) = 25√3 = 43.3 N m
Calaamadda dheeraadka ah sababtoo ah xoogga F 1 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Awoodda 2aad:
τ 2 = F 2 l 2 = (10 N) (0) = 0
Awoodda 3aad:
τ 3 = F 3 l 3 = (10 N)( 5 m) = -50 N m
Calaamadda laga jaray sababtoo ah xoogga F 3 wuxuu sababaa in iftiinka uu u wareego dhanka saacadda.
Xoogga saafiga ah:
Σ τ = τ 1 + τ 2 - τ 3 = 43.3 + 0 - 50 = - 6.7 N m
Calaamadda laga jaray sababtoo ah xoogga saafiga ah wuxuu sababaa in fallaadha ay u wareegto dhanka saacadda.
