9 Tusaalooyin oo Su'aalo Ganacsi ah
1. Xoogga 20 Newton ayaa lagu dabaqayaa baloog ilaa balooggu uu u socdo masaafo dhan 2 mitir. Shaqada uu qabto xoogga F ee baloogga waa…
Dood
Waa la garanayaa :
Xoogga (F) = 20 N
Barakaca (yada) = 2 mitir
Xagasha = 0 (jihada xooggu waxay la mid tahay jihada barokaca ama jihada xooggu waxay la mid tahay jihada barokaca si xagasha ay samaysay xoogga iyo barokaca ay eber noqoto)
La weydiiyay Dadaal (W)
Jawab :
Catatan:
Haddii jihada xooggu la mid tahay jihada barokaca, xisaabi shaqada adoo isticmaalaya qaacidada W = Fs, adigoon u baahnayn inaad ku darto cos eedo.
2. Shay waa mid taagan oo saaran sagxad siman. Xoog F = 10 N ayaa lagu dabaqaa shayga, isagoo samaynaya xagal 30 ah.o ka soo horjeedka dusha sare ee dabaqa. Haddii shaygu u dhaqaaqo 1 mitir, intee in le'eg ayay shaqada ku qabataa xoogga F ee shayga?
Dood
Waa la garanayaa :
Xoogga (F) = 10 Newton
Xoogga u socda dhanka barakaca (F)x) = F cos 30o = (10)(0,5√3) = 5√3 Newtons
Barakaca (yada) = 1 mitir
La weydiiyay : dadaal (W) ?
Jawab :
W = Fx s = (5√3)(1) = 5√3 Joule
3. Shay culeyskiisu yahay 1 kg ayaa si xor ah uga soo dhacaya dhererkiisu yahay 2 mitir. Haddii dardargelinta cufisjiidadka awgeed ay tahay 10 m/s2, go'aami shaqada ay qabteen xoogga cufisjiidadka ee shayga!
Dood
Waa la garanayaa :
Cufka shayga (m) = 1 kg
Dhererka (h) = 2 mitir
Dardargelinta cufisjiidadka awgeed (g) = 10 m/s2
La weydiiyay Shaqada ay qabtaan xoogga cufisjiidadka ee ku yaal shay (W)
Jawab :
Jihada xoogga cufisjiidadka ama miisaanka (w) waa mid toosan hoos u socota, jihada barokaca shayga (s) sidoo kale waa mid toosan hoos u socota si xoogga cufisjiidadka uu ugu socdo jihada la mid ah barokaca shayga.
W = Fs = wh = mgh
W = (1)(10)(2) = 20 Joule
4. Gu' ayaa la sudhay culays dhan 1 kg si gu'gu u helo koror dhererkiisu yahay 2 cm. Haddii dardargelinta cufisjiidadka awgeed ay tahay 10 m/s2, go'aami (a) joogtada guga (b) shaqada uu gu'gu ku qabtay culayska
Dood
Waa la garanayaa :
Cuf (m) = 1 kg
Dardargelinta cufisjiidadka awgeed (g) = 10 m/s2
Kordhinta dhererka guga (x) = 2 cm = 0,02 mitir
La weydiiyay : joogtada guga iyo shaqada ay qabteen ciidanka gu'ga
Jawab :
(a) Joogtada guga
Qaaciddada sharciga Hooke :
F = k x.
Dib ugu celi qaacidadan si aad u xisaabiso joogtada guga:
k = F / x = w / x = mg / x
k = (1)(10) / 0,02 = 10 / 0,02
k = 500 Newton/mitir
(b) Shaqada ay qabteen ciidanka gu'ga
W = – ½ kx2
W = – ½ (500)(0,02)2
W = – (250)(0,0004)
W = -0,1 Joule
Shaqada ay qabtaan xoogga gu'ga ee culayska waa mid taban sababtoo ah jihada xoogga gu'ga ayaa ka soo horjeeda jihada barakaca culayska.
5. Sanduuq wali ku jira dusha sare ee dhulka ayaa la dardar gelinayaa iyadoo la adeegsanayo xoog 10 N ah si sanduuqu u dhaqaaqo masaafo dhan 2 mitir. Haddii xoogga riixitaanka uu ku socdo jihada uu sanduuqa ku socdo oo sanduuqa uu ku shaqeeyo xoog is jiidjiid ah oo 2 Newtons ah, markaa shaqada guud ee sanduuqa lagu qabtay waa...
Dood
Waa la garanayaa :
Xoogga (F) = 10 Newton
Xoogga is-khilaafka dhaqdhaqaaqa (F)k) = 2 Newton
Barakaca (yada) = 2 mitir
La weydiiyay : Dadaal guud (Wtotal)
Jawab :
Shaqada lagu sameeyay xoog (F):
W1 = Fs cos 0 = (10)(2)(1) = 20 Joules
Shaqada ay qabato xoogga isku dhaca dhaqdhaqaaqa (F)k):
W2 =Fk s = (2)(2)(cos 180) = (2)(2)(-1) = -4 Joules
Dadaal guud waa:
Wtotal =W1 - W2
Wtotal = 20 - 4
Wtotal = 16 Joule
6. Shay culeyskiisu yahay 5 kg wuxuu 10 mitir ka sarreeyaa dusha sare ee Dhulka. Dardargelinta cufisjiidadka awgeed waa 10 m/s -2 . Tirada shaqada loo baahan yahay si shayga loogu raro dherer dhan 15 mitir oo ka sarreeya dusha sare ee Dhulka waa...
A.. 75 Joule
B.. 250 Joule
C.. 500 Joule
D.. 750 Joule
E. 1.250 Joule
Dood
Waa la ogyahay in:
Cufka shayga (m) = 5 kg
Dhererka (h) = 10 mitir
Dardargelinta cufisjiidadka awgeed (g) = 10 m/s 2
Su'aal: Dadaal lagu doonayo in shay loo raro dherer dhan 15 mitir
Jawaab:
Dadaalka lagu dhaqaajinayo shay wuxuu ugu yaraan la mid yahay xoogga cufisjiidadka ee ku shaqeeya shayga.
Qaacidada shaqada ee ay qabato xoogga cufisjiidadka:
W = wh = mgh
Sharaxaad: W = dadaal, w = cufisjiidadka, h = dherer, m = cuf, g = dardargelinta cufisjiidadka
Qaacidada shaqada la qabtay waa:
W = wh = mgh = (5 kg)(10 m/s 2 )(10 m) = 500 kg m 2 / s 2 = 500 Joules
Jawaabta saxda ah waa C.
7. Shay culeyskiisu yahay 2 kg ayaa ku dhaqaaqa dusha siman xawaare dhan 2 m/s –1 . Daqiiqado kadib, shaygu wuxuu ku socdaa xawaare dhan 5 m/s –1 . Shaqada lagu sameeyay shayga inta lagu jiro muddadan waa…
A. 4 Joule
B. 9 Joule
C. 15 Joule
D. 21 Joule
E. 25 Joule
Dood
Waa la ogyahay in:
Cufka shayga (m) = 2 kg
Xawaaraha bilowga ah (vo o ) = 2 ms –1
Xawaaraha kama dambaysta ah (v t ) = 5 ms –1
Su'aal: Shaqada lagu qabtay shayga inta lagu jiro waqtiga
Jawaab:
Aragtida tamarta shaqada-kinetic-ga waxay sheegaysaa in shaqada guud ee lagu sameeyay shay ay la mid tahay isbeddelka tamarta dhaqdhaqaaqa shayga. Xisaab ahaan:
W = ΔEK = EK 2 - EK 1 = 1/2 mv t 2 - 1/2 mv o 2 = 1/2 m (v t 2 - v o 2 ) = 1/2 (2) (5 2 -2 2 ) = (1) (25-4) = 21 Joules
8. Miis culeyskiisu yahay 10 kg ayaa marka hore ku dul yaal sagxad siman, waxaa la riixaa 3 ilbiriqsi wuxuuna ku socdaa xariiq toosan oo leh xawaare dhan 2 ms s −2 . Tirada shaqada la qabtay waa…
A. 20 Joule
B. 30 Joule
C. 60 Joule
D. 180 Joule
E. 360 Joule
Dood
Waa la ogyahay in :
Cuf (m) = 10 kg
Xawaaraha bilowga ah (v o ) = 0 (bilowgii jadwalku waa mid taagan)
Muddada (t) = 3 ilbiriqsi
Dardargelinta (a) = 2 m/s 2
Waxaa la weydiiyay : dadaal (W)?
Jawaab :
Marka hore, xisaabi masaafada la safray adoo isticmaalaya qaacidada GLBB:
s = v o t + ½ at 2 = (0)(3) + ½ (2)(3) 2
s = 0 + (1)(9) = 9
Shaqada miiska lagu sameeyay:
W = Fs = (ma)(s) = (10)(2)(9) = 180 Joules
Jawaabta saxda ah waa D.
9. Baloog culeyskiisu yahay 1,5 kg ayaa kor loogu riixayaa xoog joogto ah F = 15 N oo ku yaal diyaarad janjeerta sida ku cad sawirka. U qaado in dardargelinta cufisjiidadka (g) ay tahay 10 ms -2 oo is jiidjiidka u dhexeeya baloogga iyo diyaaradda janjeerta ay tahay eber. Wadarta shaqada laga qabtay baloogga waa…
A. 15 J
B. 30 J
C. 35 J
D. 45 J
E. 50 J
Dood
Waa la ogyahay in :
Cufka baloogga (m) = 1,5 kg
Dardargelinta cufisjiidadka awgeed (g) = 10 m/s 2
Miisaanka baloogga (w) = mg = (1,5)(10) = 15 Newton
Xoogga riixitaanka (F) = 15 Newton
Su'aal : Shaqada guud ee laga qabtay baloogga (W)?
Jawaab :
Waxaa jira laba xoog oo shaqo ka qabanaya baloogga; xoogga barbar socda barokaca baloogga, kuwaas oo kala ah xoogga riixitaanka (F) iyo miisaanka baloogga oo barbar socda dusha sare ee diyaaradda janjeerta (w x ).
Shaqada ay qabteen ciidanka riixaya waa:
W 1 = F s = (15 N)(2 m) = 30 N m = 30 Joules
Shaqada waxaa qabta cufisjiidadka wx:
W 2 = w x s = (w sin 30 o )(2 m) = (15 N)(1/2)(2 m) = 15 N m = 15 Joules
Shaqada guud ee laga qabtay baloogga:
Wadarta W = W 1 – W 2 = 30 J – 15 J = 15 Joules
Jawaabta saxda ah waa A.
