Tusaale Su'aalo Ka Hadlaya Wareegyada Korontada
Wareegyada korontadu waa mowduuc muhiim u ah fiisigiska iyo injineernimada korontada. Fahmidda sida wareegyadu u shaqeeyaan iyo sida loo xisaabiyo qiimayaasha ayaa muhiim u ah qof kasta oo xiiseynaya injineernimada korontada ama ka shaqeynta aaladaha elektaroonigga ah. Maqaalkani wuxuu dabooli doonaa tusaalooyin dhowr ah oo ku saabsan dhibaatooyinka wareegga korantada iyo sharraxaaddooda oo ah tixraac loogu talagalay ardayda iyo xirfadlayaasha raadinaya inay sii qoto dheereeyaan aqoontooda.
Hordhac ku saabsan Wareegyada Korontada
Guud ahaan, wareegga korontadu wuxuu ka kooban yahay dhowr qaybood oo aasaasi ah sida iska caabinta, kaabsoolayaasha, inductor-yada, iyo ilaha danabka ama hadda jira. Qaybahani waxay ku xiran yihiin qaab-dhismeedyo gaar ah si ay u qabtaan shaqooyin gaar ah, sida calaamadaha shaandhaynta ama kordhinta ama hoos u dhigista danabka. Falanqaynta wareegga, sharciyada Ohm iyo Kirchhoff waxaa badanaa loo isticmaalaa in lagu xisaabiyo hadda iyo danabka wareegga.
Tusaale ahaan Dhibaatada 1aad: Wareegga Taxanaha Fudud
Su'aal:
Iyadoo la siinayo wareeg taxane ah oo ka kooban saddex iska caabin \( R1 = 2 \Omega \), \( R2 = 3 \Omega \), iyo \( R3 = 5 \Omega \) oo ku xiran isha danabka \( V = 10 V \). Xisaabi socodka hadda ee wareegga iyo danabka ku socda iska caabin kasta.
Dood:
1. Soo hel iska caabin buuxda:
Wareeg taxane ah, iska caabinta guud waa wadarta dhammaan iska caabinta shaqsiyeed.
\[
R_{\text{wadarta}} = R1 + R2 + R3 = 2 \Omega + 3 \Omega + 5 \Omega = 10 \Omega
\]
2. Soo hel qulqulka socda:
Sida waafaqsan sharciga Ohm, hadda waxaa loo xisaabin karaa sidan:
\[
I = \frac{V}{R_{\text{total}}} = \frac{10 V}{10 \Omega} = 1 A
\]
3. Soo hel danab kasta oo ku jira Resistor kasta:
Danabka ku jira iska caabin kasta waxaa loo xisaabiyaa sidan:
\[
V_{R1} = I \ jeer R1 = 1 A \ jeer 2 \Omega = 2 V
\]
\[
V_{R2} = I \ jeer R2 = 1 A \ jeer 3 \Omega = 3 V
\]
\[
V_{R3} = I \ jeer R3 = 1 A \ jeer 5 \Omega = 5 V
\]
Markaa, qulqulka hadda ee wareegga waa 1 A, danabkuna wuxuu ku socdaa iska caabin kasta waa 2 V, 3 V, iyo 5 V, siday u kala horreeyaan.
Su'aal Tusaale 2: Wareeg Fudud oo Isbarbar socda
Su'aal:
Marka la eego wareeg barbar socda oo ka kooban saddex iska caabin \( R1 = 6 \Omega \), \( R2 = 3 \Omega \), iyo \( R3 = 2 \Omega \) oo ku xiran isha danab \( V = 12 V \). Xisaabi hadda iyada oo loo marayo iska caabin kasta.
Dood:
1. Hadda ku jira Resistor kasta:
Wareeg barbar socda, danabka ku dhex jira iska caabin kasta waa isku mid oo wuxuu la mid yahay danabka isha. Sidaa darteed, hadda ku dhex jira iska caabin kasta waxaa lagu xisaabiyaa iyadoo la adeegsanayo sharciga Ohm.
\[
I_{R1} = \frac{V}{R1} = \frac{12 V}{6 \Omega} = 2 A
\]
\[
I_{R2} = \frac{V}{R2} = \frac{12 V}{3 \Omega} = 4 A
\]
\[
I_{R3} = \frac{V}{R3} = \frac{12 V}{2 \Omega} = 6 A
\]
Markaa, hadda dhex mara iska caabin kasta waa 2 A, 4 A, iyo 6 A siday u kala horreeyaan.
Su'aal Tusaale ah 3: Isku-darka Wareegyada Taxanaha iyo Isbarbardhigga ah
Su'aal:
Marka la eego wareeg isku dhafan oo ka kooban \( R1 = 4 \Omega \), \( R2 = 2 \Omega \), iyo \( R3 = 3 \Omega \). \( R2 \) iyo \( R3 \) ayaa isku xiran, ka dibna waxay ku xiran yihiin taxane iyagoo wata \( R1 \) iyo isha danab \( V = 15 V \). Xisaabi hadda iyo danab kasta oo ku dhex jira iska caabin kasta.
Dood:
1. Soo hel iska caabinta u dhiganta ee \( R2 \) iyo \( R3 \):
\[
\frac{1}{R_{\text{parallel}}} = \frac{1}{R2} + \frac{1}{R3} = \frac{1}{2 \Omega} + \frac{1}{3 \Omega} = \frac{3 + 2}{6} = \frac{5}{6 \Omega}
\]
\[
R_{\text{isbarbardhig}} = \frac{6}{5} \Omega = 1,2 \Omega
\]
2. Iska caabinta Guud:
\[
R_{\text{total}} = R1 + R_{\text{parallel}} = 4 \Omega + 1,2 \Omega = 5,2 \Omega
\]
3. Wadarta Hadda:
\[
I_{\text{total}} = \frac{V}{R_{\text{total}}} = \frac{15 V}{5,2 \Omega} \qiyaastii 2,88 A
\]
4. Danab ku jira \( R1 \):
\[
V_{R1} = I_{\text{total}} \times R1 = 2,88 A \times 4 \Omega \qiyaastii 11,52 V
\]
5. Danabka ku jira \( R2 \) iyo \( R3 \):
Maadaama \( R2 \) iyo \( R3 \) ay is barbar socdaan, danabyadu waa isku mid:
\[
V_{\text{isbarbardhig}} = V – V_{R1} = 15 V – 11,52 V \qiyaastii 3,48 V
\]
6. Soo hel hadda ku jirta \( R2 \) iyo \( R3 \):
\[
I_{R2} = \frac{V_{\text{isbarbardhig}}}{R2} = \frac{3,48 V}{2 \Omega} \qiyaastii 1,74 A
\]
\[
I_{R3} = \frac{V_{\text{isbarbardhig}}}{R3} = \frac{3,48 V}{3 \Omega} \qiyaastii 1,16 A
\]
Sidaas darteed, socodka hadda ee wareegga waa qiyaastii 2,88 A. Danabka ku dhex jira \( R1 \) waa qiyaastii 11,52 V, danabka ku dhex jira \( R2 \) iyo \( R3 \) waa qiyaastii 3,48 V. Hadda ku dhex jira \( R2 \) waa 1,74 A iyo guud ahaan \( R3 \) waa 1,16 A.
Gabagabo
Maqaalkani wuxuu ka hadlayaa dhowr tusaale oo ah dhibaatooyinka wareegga fudud iyo kuwa isku dhafan, iyo sidoo kale tallaabooyinka lagu xallinayo. Fahmidda fikradaha aasaasiga ah iyo sida loo dabaqo sharciyada Ohm iyo Kirchhoff waxay sahlaysaa xallinta dhibaatooyinka wareegga kala duwan. Ku celcelinta joogtada ah ee dhibaatooyinka kala duwan waxay hagaajin kartaa fahamkaaga iyo awooddaada aad ku falanqeyn karto wareegyada korantada. Kuwa raadinaya faham qoto dheer, waxaa lagu talinayaa inay si qoto dheer u dhexgalaan walxaha ku jira wareegyada AC, shaandheeyayaasha, iyo falanqaynta domain-ka soo noqnoqda.
