Tusaale ahaan ku dabaqidda sharciga koowaad ee thermodynamics habka isochoric (mugga joogtada ah)

3 Tusaalooyin su'aalo ah oo ku saabsan hirgelinta sharciga koowaad ee thermodynamics ee hababka isochoric (mugga joogtada ah)

1. Garaafka cadaadiska (P) ee ka dhanka ah mugga (V) ee gaaska maraya habka isochoric. Shaqada uu gaaska ku sameeyo habka AB waa…

Dood
Geedi socodka AB = habka isochoric (mugga joogtada ah). Mugga isochoric, mugga gaaska (iyo mugga booska) isma beddelo sidaas darteed ma jiro shaqo uu gaasku qabto.

2. Saddex mool oo gaas monatomic ah heerkul ah 47^oC iyo cadaadis 2 x 10⁵ Pascal wuxuu maraa hab isochoric ah ilaa cadaadisku kor u kaco ilaa 3 x 10.⁵ Pascal. Isbeddelka tamarta gudaha ee gaaska waa… Joogtada gaaska guud (R) = 8,315 J/mol.K
Dood
Waa la garanayaa :
Heerkulka bilowga ah (T)₁= 47^oC + 273 = 320 K
Cadaadiska bilowga ah (P)₁) = 2 x 10⁵ Pa
Cadaadiska kama dambaysta ah (P)₂) = 3 x 10⁵ Pa
Joogtada gaaska guud (R) = 8,315 J/mol.K
Tirada burooyinka (n) = 3
La weydiiyay Isbeddellada ku yimaada tamarta gaaska
Jawab :
Habka isochoric, mugga wuxuu ahaanayaa mid joogto ah sidaa darteed gaaska ma sameeyo wax shaqo ah (W = 0).
Sharciga Koowaad ee Thermodynamics :
Iyada oo lagu saleynayo soo saarista qaacidadan, waxaa lagu soo gabagabeynayaa in habka isochoric, kulaylka lagu daray nidaamka (Q) uu keeno in tamarta gudaha ee nidaamka (U) ay korodho. Taas bedelkeeda, kulaylka uu sii daayo nidaamku wuxuu sababaa in tamarta gudaha ee nidaamka ay yaraato. Immisa ayuu le'eg yahay isbeddelka tamarta gudaha ee gaaska? Isbeddelka tamarta gudaha ee gaaska waxaa lagu xisaabiyaa iyadoo la adeegsanayo qaacidada tamarta gudaha ee hoose.
Tamarta gaaska :
Si loo xisaabiyo isbeddelka tamarta gudaha, heerkulka ugu dambeeya (T) waa in la ogaadaa.₂) Xisaabi T₂ iyadoo la adeegsanayo qaacidada sharciga ee Gay-Lussac.
Sharciga Gay-Lussac (mugga isochoric/mugga joogtada ah) :
Xisaabi isbeddelka tamarta ee gaaska:
Isbeddelka tamarta gudaha ee gaaska waa 5986,8 Joules.

3. Wadarta guud ee 0,2 moles oo gaas monatomic ah heerkul ah 27^oC waxay ku jirtaa weel xiran. Kulaylka ay tahay in la nuugo si loo kordhiyo heerkulka gaaska ilaa 400 K waa… Joogtada gaaska guud (R) = 8,315 J/mol.K
Dood
Waa la garanayaa :
Tirada boollada (n) = 0,2 boollada
Heerkulka bilowga ah (T)₁= 27^oC + 273 = 300 K
Heerkulka kama dambaysta ah (T)₂) = 400 K
Joogtada gaaska guud (R) = 8,315 J/mol.K
La weydiiyay Kuleylka oo la nuugo (Q)
Jawab :
Habka isochoric, mugga wuxuu ahaanayaa mid joogto ah sidaa darteed gaaska ma sameeyo wax shaqo ah (W = 0).
Sharciga Koowaad ee Thermodynamics :
Kuleylka la nuugo (Q) = kororka tamarta gudaha ee gaaska (U). Isbeddelka tamarta gudaha ee gaaska waxaa lagu xisaabiyaa iyadoo la adeegsanayo qaacidada tamarta gudaha ee hoose.
Tamarta gaaska :
Kulaylka uu nuugo gaaska = isbeddelka tamarta gudaha = 249,45 Joules.