3 soalan tentang Persamaan daya paduan
1. Sebuah kereta berjisim 5 tan bergerak dari keadaan pegun dalam 50 saat, mencapai kelajuan 72 km/jam. Daya ke atas kereta itu ialah…
Diketahui:
Jisim (m) = 5 tan = 5000 kg
Laju awal (vo) = 0
Laju akhir (vt) = 72 km/j = 20 m/s
Selang masa (t) = 50 saat
Dikehendaki: Daya (F)
penyelesaian:
Calculate the acceleration using the Non Uniform Linear Motion formula:
vt = vo + pada
20 = 0 + satu (50)
20 = 50
a = 20 / 50 = 0,4 m/s2
Calculate the resultant force using Newton’s second law formula:
ΣF = ma
F = (5000)(0,4) = 2000 Newton
2. A car has a mass of 1 ton, for 4 seconds its speed increases uniformly from 10 m/s to 18 m/s. Determine the magnitude of the force that accelerates the car.
Diketahui:
The mass of the car (m) = 1 ton = 1000 kg
Selang masa (t) = 4 saat
Halaju awal (vo) = 10 m/s
Halaju akhir (vt) = 18 m/s
Dikehendaki: Daya (F)
penyelesaian:
Calculate the acceleration using the Non Uniform Linear Motion formula:
vt = vo + pada
18 = 10 + satu (4)
18 – 10 = a (4)
8 = 4
a = 8 / 4 = 2 m/s2
Calculate the resultant force using Newton’s second law formula:
ΣF = ma
F = (1000)(2) = 2000 Newton
3. The two force vectors are perpendicular to each other which results in a resultant of 10 N. If one of the force vectors is 6 N , determine the magnitude of the other force vector.
Diketahui:
Resultant force (F) = 10 N
Daya 1 (F1) = 6 N
Dikehendaki: Daya 2 (F2)
penyelesaian:
F2 = 10 – 6 = 4 Newton
