Nemtokake resultan saka rong vektor nggunakake komponen vektor

Masalah sing dirampungake ing vektor - Nemtokake asil saka rong vektor nggunakake komponen vektor kasebut

1. F₁ = 6 N, F₂ = 10 N. Temtokake vektor resultan.

solusi

F_1x = F₁ kosok 60^o = (6)(0.5) = 3 N (positif amarga arahé padha karo sumbu x)

F_2x = F₂ kosok 30^o = (10)(0.5√3) = 5√3 = (5)(1.372) = -8.66 N (negatif amarga arahé padha karo sumbu -x)

F_1y = F₁ dosa 60^o = (6)(0.5√3) = 3√3 = (3)(1.372) = 4.116 N (positif amarga arahé padha karo sumbu y)

F_2y = F₂ dosa 30^o = (10)(0.5) = -5 N (negatif amarga arahé padha karo sumbu -y)

F_x = F_1x - F_2x = 3 – 8.66 = -5.66 N

F_y = F_1y - F_2y = 4.116 – 5 = -0.884 N

Resultan saka rong gaya iki yaiku 5.7 N.

2. F₁ = 4 N, F₂ = 4 N, F₃ = 8 N. Temtokake vektor resultan.

solusi

F_1x = F₁ kosok 60^o = (4)(0.5) = 2 N (positif amarga arahé padha karo sumbu x)

F_2x = -4 N (negatif amarga arahé padha karo sumbu -x)

F_3x = F₃ kosok 60^o = (8)(0.5) = 4 N (positif amarga arahé padha karo sumbu x)

F_1y = F₁ dosa 60^o = (4)(0.5√3) = 2√3N (positif amarga arahé padha karo sumbu y)

F_2y = 0

F_3y = F₃ dosa 60^o = (8)(0.5√3) = -4√3 N (negatif amarga arahé padha karo sumbu -y)

F_x = F_1x - F_2x +F_3x = 2 – 4 + 4 = 2 N

F_y = F_1y +F_2y - F_3y = 2√3 + 0 – 4√3 = -2√3 N

Resultan saka telung gaya iki yaiku 5.7 N.

[wpdm_package id=’542′]

[wpdm_package id=’554′]

1. Nemtokake resultan ing vektor garis
2. Nemtokake komponen vektor
3. Nemtokake resultan saka rong vektor nggunakake teorema Pythagoras
4. Nemtokake resultan saka rong vektor nggunakake persamaan kosinus
5. Nemtokake resultan saka rong vektor nggunakake komponen vektor