Ka'idar Pascal - matsaloli da mafita

Ka'idar Pascal - matsaloli da mafita

1. An san:

Yankin A ₁ = 10 cm ²

Faɗin A ₂ = 100 cm ²

Ƙarfi 2 (F ₂ ) = 100 Newton

Ana nema: Ƙarfi 1 (F ₁ )

Magani:

P = F / A

P = matsin lamba , F = ƙarfi , A = yanki

P₁ = F₁ / ZUWA₁
P₂ = F₂ / ZUWA₂

P₁ =P₂
F₁ / ZUWA₁ = F₂ / ZUWA₂

F ₁ / 10 cm ² = 100 N / 100 cm ²

F ₁ / 10 = 1 N

F ₁ = (10)(1 N)

F ₁ = 10 Newton

2. Idan yankin A ₁ = 0.001 m2 ^kuma yankin A ₂ = 0.1 m2 ^, ƙarfin shigarwa na waje F ₁ = 100 N, to ƙarfin fitarwa na waje F ₂?

An sani:

Fadin A ₁ = 0.001 m ²

Fadin A ₂ = 0.1 m ²

Ƙarfin shigarwa na waje F ₁ = Newtons 100

Ana so : Ƙarfin fitarwa na waje (F ₂ )

Magani:

P₁ =P₂
F₁ / ZUWA₁ = F₂ / ZUWA₂

100 N / 0.001 m ² = F ₂ / 0.1 m ²

100 N / 0.001 = F ₂ / 0.1

100,000 N = F ₂ / 0.1

F ₂ = (0.1)(100,000 N)

F ₂ = N 10,000

3. Nauyin mota = 16,000 N. Menene ƙarfin shigarwar waje F…

An sani:

Nauyin mota (w) = 16,000 N

Yankin B (A _B ) = 4000 cm ² = 4000 / 10,000 m ² = 4 / 10 m ² = 0.4 m ²

Yankin A (A _A ) = 50 cm ² = 50 / 10,000 m ² = 0.005 m ²

Ana nema: Force F

Magani:

F / A _A = w / A _B

F / 0.005 m ² = 16,000 N / 0.4 m ²

F / 0.005 = 16,000 N / 0.4

F / 0.005 = N40,000

F = (40,000 N)(0.005)

F = 200 Newton

4.

Faɗin A shine 60 cm ² kuma faɗin B shine 4,200 cm ² , ana tantance ƙarfin shigarwar waje na F.

An sani:

Yankin A (A _A ) = 60 cm ²

Yankin B (A _B ) = 4200 cm ²

Nauyi w (w) = 3500 Newton

Ana so: F ₁

Magani:

An ƙididdige ƙarfin F ta amfani da lissafin ƙa'idar Pascal :

F ₁ / A ₁ = F ₂ / A ₂

F ₁ / 60 cm ² = 3500 N / 4200 cm ²

F ₁ / 60 = 35 N / 42

F ₁ = (60)(35) / 42

F ₁ = 2100 / 42

F ₁ = 50 Newton

5. Ɗaukar na'urar hydraulic tana da babban sashe na giciye da ƙaramin sashe na giciye. Babban yanki na giciye ya ninka ƙaramin yanki na giciye sau 20. Idan a kan ƙaramin sashe na giciye aka ba shi ƙarfin shigarwa na N 25, to, a ƙayyade ƙarfin fitarwa.

An sani:

Ƙaramin yanki na giciye (A ₁ ) = A

Babban yanki mai faɗi (A ₂ ) = 20A

Ƙarfin shigarwa (F ₁ ) = 25 N

Ana so: Ƙarfin fitarwa (F ₂ )

Magani:

1. Menene Ka'idar Pascal?
   • Amsa: Ka'idar Pascal ta bayyana cewa duk wani canji a matsin lamba da aka yi a kowane lokaci a cikin ruwa ana watsa shi ba tare da raguwa ba a cikin ruwan a duk hanyoyi.
2. Ta yaya lif ɗin hydraulic yake aiki bisa ga ƙa'idar Pascal?
   • Amsa: A cikin wani injin ɗagawa na hydraulic, ƙaramin ƙarfi da aka shafa wa ƙaramin injin yana haifar da matsin lamba wanda ba a rage shi ba zuwa babban injin da ke da babban yanki. Wannan yana haifar da babban ƙarfi akan babban injin, wanda ke ba shi damar ɗaga abubuwa masu nauyi.
3. Me yasa canjin matsin lamba ba ya raguwa a cikin Ka'idar Pascal?
   • Amsa: Saboda ruwa ba ya iya matsewa, idan aka shafa matsi a wani ɓangare na ruwan, ba zai iya matsewa ba, don haka yana canja canjin matsi zuwa kowane ɓangare na ruwan daidai gwargwado.
4. Ta yaya ƙaruwar zurfin ruwa ke shafar matsin lamba, idan aka yi la'akari da ƙa'idar Pascal?
   • Amsa: Yayin da zurfin ruwa ke ƙaruwa, matsin lambar kuma yana ƙaruwa saboda nauyin ruwan da ke sama. Wannan ya yi daidai da ƙa'idar Pascal yayin da ƙaruwar matsin lamba ke faruwa iri ɗaya a wani takamaiman zurfin.
5. Me yasa kunnuwanmu ke bugawa idan muka hau ko sauka da sauri a cikin jirgin sama ko kuma muka nutse cikin ruwa mai zurfi?
   • Amsa: Sauyin yanayi mai sauri ko zurfi yana haifar da canje-canjen matsin lamba cikin sauri a cikin yanayin da ke kewaye (iska ko ruwa). Kunnuwanmu suna tashi a matsayin hanyar daidaita matsin lamba na ciki da matsin lamba na waje, daidai da Ka'idar Pascal.
6. Idan sirinji mai rufewa wanda ba shi da kumfa a iska ya lalace, me yasa yake da wuya a matse ruwan da ke ciki?
   • AmsaRuwa ba shi da ƙarfi sosai. Idan ka yi ƙoƙarin rage yawan ruwan da ke cikin sirinji, matsin lamba yana ƙaruwa, yana hana matsi, bisa ga ƙa'idar Pascal.
7. Ta yaya Dokar Pascal ta bayyana abin da ya faru na fashewar madatsar ruwa idan aka ƙirƙiri ƙaramin rami a gindinsa?
   • Amsa: Saboda nauyin ruwan, matsin lamba a gindin madatsar ruwan yana da yawa. Ko da ƙaramin buɗewa yana ba da damar yin wannan matsin lamba mai yawa akan gine-ginen da ke kewaye, wanda zai iya haifar da mummunan gazawar madatsar ruwan.
8. Me ya sa ya fi sauƙi a zubar da ruwa daga kwalbar matsewa kusan cikakke fiye da wanda babu komai a ciki?
   • Amsa: Kwalba cike take da ruwa mai yawa wanda idan aka matse ta, tana watsa matsin lamba da aka yi amfani da shi cikin ruwan yadda ya kamata saboda Ka'idar Pascal. Kwalba mara komai tana da iska mai yawa, wadda za a iya matse ta, don haka matsin lamba iri ɗaya ba ya haifar da zubewar ruwa mai ƙarfi kamar yadda yake.
9. A tsarin hydraulic, shin ƙarfin fitarwa koyaushe ya fi ƙarfin shigarwa girma?
   • Amsa: Ba lallai ba ne. Rabon ƙarfin fitarwa zuwa ƙarfin shigarwa yana ƙaddara ne ta hanyar rabon yankunan fistan fitarwa da shigarwa. An tsara tsarin don ƙara ƙarfi ta hanyar samun yankin fistan fitarwa mafi girma fiye da shigarwa, amma rabon yanki ne ke ƙayyade ƙara ƙarfi.
10. Idan aka yi la'akari da ƙa'idar Pascal, me yasa halittu masu zurfi a cikin teku suke da jiki mai ƙarfi da ƙanƙanta?

• Amsa: Halittun ruwa masu zurfi suna fuskantar matsin lamba mai yawa saboda nauyin ginshiƙin ruwa da ke saman ruwa. Domin su tsira, waɗannan halittu sun samo asali don samun jiki mai ƙarfi da ƙanƙanta waɗanda za su iya jure waɗannan matsin lamba masu yawa.